740 grams P2O5 (1 mole P2O5/141.94 grams)(6.022 X 10^23/1 mole P2O5)
= 3.14 X 10^24 atoms of P2O5
There are 1.15 x 10^21 atoms in 0.220 g of P2O5.
To find the total number of atoms in 0.850 g of P2O5, we need to first calculate the number of moles of P2O5 using its molar mass. Then, using Avogadro's number (6.022 x 10^23 atoms/mole), we can determine the total number of atoms. Finally, the answer is approximately 2.57 x 10^22 atoms in 0.850 g of P2O5.
To find the total number of atoms in 0.750 mol of P2O5, first calculate the molar mass of P2O5 (141.94 g/mol). Then multiply the molar mass by Avogadro's number (6.022 x 10^23 atoms/mol) to find the total number of atoms in 0.750 mol.
The molar mass of P4 is 123.9 g/mol, and the molar mass of P2O5 is 141.94 g/mol. The stoichiometry of the reaction shows that 1 mol of P4 produces 1 mol of P2O5. Therefore, the maximum amount of P2O5 that can be produced from 211 g of P4 is 211 g / 123.9 g/mol = 1.70 mol of P2O5.
To convert PO4-P to P2O5, you can use the molar mass of each compound. Phosphorus (P) has a molar mass of 30.97 g/mol, while P2O5 has a molar mass of 141.94 g/mol. So, you can calculate the conversion factor by dividing the molar mass of P2O5 by the molar mass of P to determine how much P2O5 is equivalent to 1 unit of PO4-P.
There are 1.15 x 10^21 atoms in 0.220 g of P2O5.
To find the total number of atoms in 0.850 g of P2O5, we need to first calculate the number of moles of P2O5 using its molar mass. Then, using Avogadro's number (6.022 x 10^23 atoms/mole), we can determine the total number of atoms. Finally, the answer is approximately 2.57 x 10^22 atoms in 0.850 g of P2O5.
To find the total number of atoms in 0.750 mol of P2O5, first calculate the molar mass of P2O5 (141.94 g/mol). Then multiply the molar mass by Avogadro's number (6.022 x 10^23 atoms/mol) to find the total number of atoms in 0.750 mol.
From every two atoms of P, one molecule of P2O5 is formed. The relative formula mass of two atoms of P (phosphorous) is 62, whereas for one molecule of P2O5 it is 142. The mass of P2O5 formed is therefore 142/62 times the mass of P we started with. This comes out to 286.3g (to one decimal place).
740 mg = 0.74 g
The molar mass of P4 is 123.9 g/mol, and the molar mass of P2O5 is 141.94 g/mol. The stoichiometry of the reaction shows that 1 mol of P4 produces 1 mol of P2O5. Therefore, the maximum amount of P2O5 that can be produced from 211 g of P4 is 211 g / 123.9 g/mol = 1.70 mol of P2O5.
3.55g
To convert PO4-P to P2O5, you can use the molar mass of each compound. Phosphorus (P) has a molar mass of 30.97 g/mol, while P2O5 has a molar mass of 141.94 g/mol. So, you can calculate the conversion factor by dividing the molar mass of P2O5 by the molar mass of P to determine how much P2O5 is equivalent to 1 unit of PO4-P.
49.1740 g (6.02 x 1023 atoms) / (91.22 g) = 3.25 x 1023 atoms
6,687.1023 chlorine atoms
The number of atoms of lead is 6,68.10e23.
5 g of sulfur contain 0,94.10e23 atoms.