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740 grams P2O5 (1 mole P2O5/141.94 grams)(6.022 X 10^23/1 mole P2O5)

= 3.14 X 10^24 atoms of P2O5

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How many total atoms are in 0.220 g of P2O5?

There are 1.15 x 10^21 atoms in 0.220 g of P2O5.


How many total atoms are in 0.850 g of P2O5?

To find the total number of atoms in 0.850 g of P2O5, we need to first calculate the number of moles of P2O5 using its molar mass. Then, using Avogadro's number (6.022 x 10^23 atoms/mole), we can determine the total number of atoms. Finally, the answer is approximately 2.57 x 10^22 atoms in 0.850 g of P2O5.


How many total atoms are in 0.750 of p2o5?

To find the total number of atoms in 0.750 mol of P2O5, first calculate the molar mass of P2O5 (141.94 g/mol). Then multiply the molar mass by Avogadro's number (6.022 x 10^23 atoms/mol) to find the total number of atoms in 0.750 mol.


What is the maximum amount in moles of P2O5 that can theoretically be made from 211 g of P 4 and excess oxygen Express your answer to three significant figures and include the appropriate units?

The molar mass of P4 is 123.9 g/mol, and the molar mass of P2O5 is 141.94 g/mol. The stoichiometry of the reaction shows that 1 mol of P4 produces 1 mol of P2O5. Therefore, the maximum amount of P2O5 that can be produced from 211 g of P4 is 211 g / 123.9 g/mol = 1.70 mol of P2O5.


How do you convert PO4-P to P2O5?

To convert PO4-P to P2O5, you can use the molar mass of each compound. Phosphorus (P) has a molar mass of 30.97 g/mol, while P2O5 has a molar mass of 141.94 g/mol. So, you can calculate the conversion factor by dividing the molar mass of P2O5 by the molar mass of P to determine how much P2O5 is equivalent to 1 unit of PO4-P.

Related Questions

How many total atoms are in 0.220 g of P2O5?

There are 1.15 x 10^21 atoms in 0.220 g of P2O5.


How many total atoms are in 0.850 g of P2O5?

To find the total number of atoms in 0.850 g of P2O5, we need to first calculate the number of moles of P2O5 using its molar mass. Then, using Avogadro's number (6.022 x 10^23 atoms/mole), we can determine the total number of atoms. Finally, the answer is approximately 2.57 x 10^22 atoms in 0.850 g of P2O5.


How many total atoms are in 0.750 of p2o5?

To find the total number of atoms in 0.750 mol of P2O5, first calculate the molar mass of P2O5 (141.94 g/mol). Then multiply the molar mass by Avogadro's number (6.022 x 10^23 atoms/mol) to find the total number of atoms in 0.750 mol.


How many grams of P2O5 will be produced from 125 g of P?

From every two atoms of P, one molecule of P2O5 is formed. The relative formula mass of two atoms of P (phosphorous) is 62, whereas for one molecule of P2O5 it is 142. The mass of P2O5 formed is therefore 142/62 times the mass of P we started with. This comes out to 286.3g (to one decimal place).


How many atom are in 0.670 grams of P2O5?

To find the number of atoms in 0.670 grams of P2O5, first calculate the molar mass of P2O5, which is approximately 283.88 g/mol. Next, determine the number of moles in 0.670 grams by dividing the mass by the molar mass: 0.670 g / 283.88 g/mol ≈ 0.00236 moles. Since each molecule of P2O5 contains 7 atoms (2 phosphorus and 5 oxygen), multiply the number of moles by Avogadro's number (approximately (6.022 \times 10^{23}) molecules/mol) and then by 7 to find the total number of atoms: 0.00236 moles × (6.022 \times 10^{23}) molecules/mol × 7 ≈ 9.86 × (10^{20}) atoms.


How many grams is 740 milligrams?

740 mg = 0.74 g


What is the maximum amount in moles of P2O5 that can theoretically be made from 211 g of P 4 and excess oxygen Express your answer to three significant figures and include the appropriate units?

The molar mass of P4 is 123.9 g/mol, and the molar mass of P2O5 is 141.94 g/mol. The stoichiometry of the reaction shows that 1 mol of P4 produces 1 mol of P2O5. Therefore, the maximum amount of P2O5 that can be produced from 211 g of P4 is 211 g / 123.9 g/mol = 1.70 mol of P2O5.


What is the mass of 0.0250 mol of P2O5?

3.55g


How do you convert PO4-P to P2O5?

To convert PO4-P to P2O5, you can use the molar mass of each compound. Phosphorus (P) has a molar mass of 30.97 g/mol, while P2O5 has a molar mass of 141.94 g/mol. So, you can calculate the conversion factor by dividing the molar mass of P2O5 by the molar mass of P to determine how much P2O5 is equivalent to 1 unit of PO4-P.


How many total atoms are in 0.330 g of P2O5?

To find the total number of atoms in 0.330 g of P₂O₅, first calculate the molar mass of P₂O₅, which is approximately 283.88 g/mol (with phosphorus at about 30.97 g/mol and oxygen at about 16.00 g/mol). Then, determine the number of moles in 0.330 g: ( \text{moles} = \frac{0.330 , \text{g}}{283.88 , \text{g/mol}} \approx 0.00116 , \text{mol} ). Since each formula unit of P₂O₅ contains 7 atoms (2 phosphorus and 5 oxygen), the total number of atoms is ( 0.00116 , \text{mol} \times 7 , \text{atoms/formula unit} \times 6.022 \times 10^{23} , \text{atoms/mol} \approx 4.87 \times 10^{21} , \text{atoms} ).


How many atoms are in 0.700g of P2O5?

To find the number of atoms in 0.700 g of P₂O₅, first calculate the molar mass of P₂O₅, which is approximately 142.0 g/mol (with phosphorus at about 31.0 g/mol and oxygen at about 16.0 g/mol). Next, determine the number of moles in 0.700 g by dividing by the molar mass: 0.700 g / 142.0 g/mol ≈ 0.00493 moles. Since each formula unit of P₂O₅ contains 7 atoms (2 phosphorus and 5 oxygen), multiply the moles by Avogadro's number (approximately (6.022 \times 10^{23}) atoms/mol) to find that there are roughly (1.48 \times 10^{21}) atoms in 0.700 g of P₂O₅.


How many total atoms are in 0.400 g of P2O5?

To find the total number of atoms in 0.400 g of P₂O₅, first calculate the molar mass of P₂O₅, which is approximately 283.88 g/mol (with phosphorus (P) at about 30.97 g/mol and oxygen (O) at about 16.00 g/mol). Then, determine the number of moles in 0.400 g by dividing the mass by the molar mass: (0.400 , \text{g} \div 283.88 , \text{g/mol} \approx 0.00141 , \text{mol}). Since each molecule of P₂O₅ contains 7 atoms (2 phosphorus + 5 oxygen), multiply the moles by Avogadro's number (approximately (6.022 \times 10^{23}) atoms/mol) and then by 7, resulting in approximately (5.89 \times 10^{21}) total atoms.