What is the maximum amount in moles of P2O5 that can theoretically be made from 211 g of P 4 and excess oxygen Express your answer to three significant figures and include the appropriate units?

Answer 1

136/31 = 4.387 moles P /2 = 2.19355 moles P2O5

Answer 2

The molar mass of P4 is 123.9 g/mol, and the molar mass of P2O5 is 141.94 g/mol. The stoichiometry of the reaction shows that 1 mol of P4 produces 1 mol of P2O5. Therefore, the maximum amount of P2O5 that can be produced from 211 g of P4 is 211 g / 123.9 g/mol = 1.70 mol of P2O5.

Answer 3

The number of P2O5 moles is 3,406.