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What is the mass in grams of 0.819 mol of the element He?
The molar mass of helium (He) is approximately 4.0026 g/mol. To find the mass of 0.819 mol of helium, you would multiply the number of moles by the molar mass: 0.819 mol * 4.0026 g/mol ≈ 3.28 grams of helium.
What is the mass in grams of 2.50 X 10-2 of CdS?
To calculate the mass of CdS, we need to have the molar mass of CdS. Cadmium (Cd) has a molar mass of approximately 112.41 g/mol, and sulfur (S) has a molar mass of approximately 32.07 g/mol. Adding these together, we get a molar mass of approximately 144.48 g/mol for CdS. To find the mass of 2.50 x 10^-2 mol of CdS, we would multiply the number of moles by the molar mass: (2.50 x 10^-2 mol) x (144.48 g/mol) = 3.61 g of CdS.
What is the mass of hydrogen in kilograms?
The molar mass of hydrogen is approximately 1.008 g/mol. To convert this to kilograms, we divide by 1000 to get 0.001008 kg/mol.
What is the mass in grams of 1.00 mol Al?
7 X 102 g Al this is the awnser using significant figures
How much does 2.18 mol of Cu weigh?
The molar mass of copper (Cu) is approximately 63.55 g/mol. To calculate the weight of 2.18 mol of copper, you would multiply the number of moles by the molar mass: 2.18 mol x 63.55 g/mol ≈ 138.49 g. Therefore, 2.18 mol of copper weighs approximately 138.49 grams.
How many total atoms are in 0.750 of p2o5?
To find the total number of atoms in 0.750 mol of P2O5, first calculate the molar mass of P2O5 (141.94 g/mol). Then multiply the molar mass by Avogadro's number (6.022 x 10^23 atoms/mol) to find the total number of atoms in 0.750 mol.
How do you convert PO4-P to P2O5?
To convert PO4-P to P2O5, you can use the molar mass of each compound. Phosphorus (P) has a molar mass of 30.97 g/mol, while P2O5 has a molar mass of 141.94 g/mol. So, you can calculate the conversion factor by dividing the molar mass of P2O5 by the molar mass of P to determine how much P2O5 is equivalent to 1 unit of PO4-P.
What is the maximum amount in moles of P2O5 that can theoretically be made from 211 g of P 4 and excess oxygen Express your answer to three significant figures and include the appropriate units?
The molar mass of P4 is 123.9 g/mol, and the molar mass of P2O5 is 141.94 g/mol. The stoichiometry of the reaction shows that 1 mol of P4 produces 1 mol of P2O5. Therefore, the maximum amount of P2O5 that can be produced from 211 g of P4 is 211 g / 123.9 g/mol = 1.70 mol of P2O5.
How many moles of phosphorus are needed to form 8.6 mol p2o5?
Molar mass of P2O5 is 142gmol-1. You need 17.2 moles of p.
How many atoms are in 740 g of P2O5?
To find the number of atoms in 740 g of P2O5, we need to first convert the mass to moles using the molar mass of P2O5, which is 141.94 g/mol. Then, we can use Avogadro's number (6.022 x 10^23) to find the number of atoms. So, 740 g of P2O5 is equal to approximately 5.21 moles, which is equivalent to 3.14 x 10^24 atoms.
How many grams of P2O5 will be produced from 125 g of P?
From every two atoms of P, one molecule of P2O5 is formed. The relative formula mass of two atoms of P (phosphorous) is 62, whereas for one molecule of P2O5 it is 142. The mass of P2O5 formed is therefore 142/62 times the mass of P we started with. This comes out to 286.3g (to one decimal place).
How many moles of oxygen atoms are present in 5.00mol of diphosphorus pentoxide P2O5?
In one molecule of diphosphorus pentoxide (P2O5), there are 5 oxygen atoms. So, in 5.00 mol of P2O5, there would be 5.00 mol * 5 = 25.00 moles of oxygen atoms.
What is the mass of 0.7891 mol of ferric oxide (Fe2O3)?
Atomic Mass of Fe: 55.8g/mol Atomic mass of O: 16g/mol Molecular mass of Fe2O3: 2(55.8)+3(16) = 159.6g/mol mass = Molecular mass x number of moles mass = 159.6g/mol x 0.7891mol = 125.94g
What is the mass of 0.7891 mol of ferric oxide Fe2O3?
Atomic mass of Fe: 55.8g/mol Atomic mass of O: 16g/mol Molecular mass of Fe2O3: 2(55.8)+3(16) = 159.6g/mol mass = Molecular mass x number of moles mass = 159.6g/mol x 0.7891mol = 125.94g
What is the mass of 0.7891 mol of ferric oxide?
Atomic Mass of Fe: 55.8g/mol Atomic mass of O: 16g/mol Molecular mass of Fe2O3: 2(55.8)+3(16) = 159.6g/mol mass = Molecular mass x number of moles mass = 159.6g/mol x 0.7891mol = 125.94g
What is the mass in grams of 0.330mol of calcium?
The mass is 0.330 mol Ca (40.08 g/mol) = 13.2 g Ca
What is the mass of 0.45 mol of ammonium sulfate?
To calculate the mass of 0.45 mol of ammonium sulfate (NH4)2SO4, you need to know its molar mass. The molar mass of (NH4)2SO4 is 132.14 g/mol. Multiply the number of moles (0.45 mol) by the molar mass to get the mass: 0.45 mol x 132.14 g/mol = 59.46 grams. Therefore, the mass of 0.45 mol of ammonium sulfate is 59.46 grams.
