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Atomic Mass of Fe: 55.8g/mol

Atomic Mass of O: 16g/mol

Molecular mass of Fe2O3: 2(55.8)+3(16) = 159.6g/mol

mass = Molecular mass x number of moles

mass = 159.6g/mol x 0.7891mol = 125.94g

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Ebba Hoeger

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Leonora Medhurst

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2y ago

Atomic Mass of Fe: 55.8g/mol

Atomic mass of O: 16g/mol

Molecular mass of Fe2O3: 2(55.8)+3(16) = 159.6g/mol

mass = Molecular mass x number of moles

mass = 159.6g/mol x 0.7891mol = 125.94g

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Q: What is the mass of 0.7891 mol of ferric oxide (Fe2O3)?
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How many moles of Fe2O3 are in 251 g of the compound?

Adding together the mass of two irons and three oxygen.....,251 grams Fe2O3 (1 mole Fe2O3/159.7 grams)= 1.57 moles iron II oxide ( also known as ferric oxide )===================================


What is the formula weight of rust?

Rust has a chemical formula of Fe2O3. Ferric oxide has a molar mass of 159.69 grams per mol and a density of 5.26 grams per cubic centimeter.


What is the chemical formula for Fe2O3?

That is the chemical formula. The name would be iron (III) oxide, or ferric oxide in the old system.


What is the mass of 0.7891 mol of ferric oxide Fe2O3?

Atomic mass of Fe: 55.8g/mol Atomic mass of O: 16g/mol Molecular mass of Fe2O3: 2(55.8)+3(16) = 159.6g/mol mass = Molecular mass x number of moles mass = 159.6g/mol x 0.7891mol = 125.94g


What is the mass of 0.7891 mol of ferric oxide?

Atomic Mass of Fe: 55.8g/mol Atomic mass of O: 16g/mol Molecular mass of Fe2O3: 2(55.8)+3(16) = 159.6g/mol mass = Molecular mass x number of moles mass = 159.6g/mol x 0.7891mol = 125.94g


What is the mass of Fe2O3?

The molar mass of anhydrous iron(II) nitrate is 179,91 g.


Each molecule of iron oxide fe2o3 contains how many atoms of iron?

There are two atoms of iron and three atoms of oxygen in the compound Fe2O3. The mass percent of iron is 69.943%


How many moles are in 182.7 g Fe?

For this you need the atomic (molecular) mass of Fe2(SO4)3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. Fe2(SO4)3=400.1 grams768 grams Fe2(SO4)3 / (400.1 grams) = 1.92 moles Fe2(SO4)3


The formula for rust can be represented by Fe2O3 How many moles of Fe are present in 14.2 g of the compound?

14.2g Fe2O3 (1mol Fe2O3/159.7g(2mol Fe/1mol Fe2O3) = 0.178 moles Fe


How do you calculate the Fe content in FeO and Fe2O3?

Mass of Fe=(Mass of Fe2O3)(Mr Fe/ Mr Fe2O3)


Consider the following balanced equation Fe203 plus 3H2 gives 2Fe plus 3H2O What mass of hydrogen would be required to convert 160g of iron III oxide into iron?

6g hydrogen would be required for 160g ferric oxide in this reaction. The relative atomic weights of the elements are: Hydrogen - 1 Oxygen - 16 Iron - 56 giving the relative atomic weights of the compounds (on the left of the equation): Fe2O3 = 56×2 + 16×3 = 160 3H2 = 3×(1×2) = 6 So for every 160 units of mass of iron III oxide there will be 6 units of mass of hydrogen required. → for 160g of iron III oxide ÷ 160 × 6 = 6 g of hydrogen.


What is the name of the compound FeO2?

FeNo2 is iron nitrite.Answer 2. Ferrous Nitrite or iron Nitrite (II)would be Fe(NO2)2.Ferric Nitrite or Iron Nitrite (III) would be Fe(NO2)3.