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Atomic Mass of Fe: 55.8g/mol
Atomic Mass of O: 16g/mol
Molecular mass of Fe2O3: 2(55.8)+3(16) = 159.6g/mol
mass = Molecular mass x number of moles
mass = 159.6g/mol x 0.7891mol = 125.94g
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What is the percent of ferric oxide?
Ferric oxide often refers to iron (III) oxide, which has a chemical formula Fe2O3. The atomic mass of iron (Fe) is 55.85 g/mol, and the atomic mass of oxygen (O) is 16.00 g/mol. Therefore, the molar mass of Fe2O3 is 159.69 g/mol. To calculate the percentage composition of iron (III) oxide, divide the atomic mass of iron by the molar mass of the compound and multiply by 100. So, (2 * 55.85) / 159.69 ≈ 0.698 or 69.8% is the percent of ferric oxide.
What is the mass of 0.7891 mol of ferric oxide Fe2O3?
Atomic mass of Fe: 55.8g/mol Atomic mass of O: 16g/mol Molecular mass of Fe2O3: 2(55.8)+3(16) = 159.6g/mol mass = Molecular mass x number of moles mass = 159.6g/mol x 0.7891mol = 125.94g
What is the mass of 0.7891 mol of ferric oxide?
Atomic Mass of Fe: 55.8g/mol Atomic mass of O: 16g/mol Molecular mass of Fe2O3: 2(55.8)+3(16) = 159.6g/mol mass = Molecular mass x number of moles mass = 159.6g/mol x 0.7891mol = 125.94g
How many moles of Fe2O3 are in 251 g of the compound?
Adding together the mass of two irons and three oxygen.....,251 grams Fe2O3 (1 mole Fe2O3/159.7 grams)= 1.57 moles iron II oxide ( also known as ferric oxide )===================================
What is the mass of Fe2O3?
The molar mass of anhydrous iron(II) nitrate is 179,91 g.
What is the percent of ferric oxide?
Ferric oxide often refers to iron (III) oxide, which has a chemical formula Fe2O3. The atomic mass of iron (Fe) is 55.85 g/mol, and the atomic mass of oxygen (O) is 16.00 g/mol. Therefore, the molar mass of Fe2O3 is 159.69 g/mol. To calculate the percentage composition of iron (III) oxide, divide the atomic mass of iron by the molar mass of the compound and multiply by 100. So, (2 * 55.85) / 159.69 ≈ 0.698 or 69.8% is the percent of ferric oxide.
What is the mass of 0.7891 mol of ferric oxide Fe2O3?
Atomic mass of Fe: 55.8g/mol Atomic mass of O: 16g/mol Molecular mass of Fe2O3: 2(55.8)+3(16) = 159.6g/mol mass = Molecular mass x number of moles mass = 159.6g/mol x 0.7891mol = 125.94g
What is the mass of 0.7891 mol of ferric oxide?
Atomic Mass of Fe: 55.8g/mol Atomic mass of O: 16g/mol Molecular mass of Fe2O3: 2(55.8)+3(16) = 159.6g/mol mass = Molecular mass x number of moles mass = 159.6g/mol x 0.7891mol = 125.94g
What is the chemical formula for Fe2O3?
That is the chemical formula. The name would be iron (III) oxide, or ferric oxide in the old system.
How many moles of Fe2O3 are in 251 g of the compound?
Adding together the mass of two irons and three oxygen.....,251 grams Fe2O3 (1 mole Fe2O3/159.7 grams)= 1.57 moles iron II oxide ( also known as ferric oxide )===================================
What is the mass of Fe2O3?
The molar mass of anhydrous iron(II) nitrate is 179,91 g.
What is the formula weight of rust?
Rust is a compound primarily composed of iron(III) oxide, with a chemical formula of Fe2O3. To calculate the formula weight, you would add the atomic weights of two iron atoms (Fe) and three oxygen atoms (O) together. Using the atomic weights from the periodic table, the formula weight of rust (Fe2O3) would be approximately 159.69 g/mol.
Each molecule of iron oxide fe2o3 contains how many atoms of iron?
There are two atoms of iron and three atoms of oxygen in the compound Fe2O3. The mass percent of iron is 69.943%
Consider the following balanced equation Fe203 plus 3H2 gives 2Fe plus 3H2O What mass of hydrogen would be required to convert 160g of iron III oxide into iron?
6g hydrogen would be required for 160g ferric oxide in this reaction. The relative atomic weights of the elements are: Hydrogen - 1 Oxygen - 16 Iron - 56 giving the relative atomic weights of the compounds (on the left of the equation): Fe2O3 = 56×2 + 16×3 = 160 3H2 = 3×(1×2) = 6 So for every 160 units of mass of iron III oxide there will be 6 units of mass of hydrogen required. → for 160g of iron III oxide ÷ 160 × 6 = 6 g of hydrogen.
How many moles are in 182.7 g Fe?
For this you need the atomic (molecular) mass of Fe2(SO4)3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. Fe2(SO4)3=400.1 grams768 grams Fe2(SO4)3 / (400.1 grams) = 1.92 moles Fe2(SO4)3
When 1.187 grams of metallic oxide is reduced with excess hydrogen 1.054 grams of the metal is produced What is the metallic oxide?
The molar mass of the metal can be found by taking the difference in mass before and after reduction. The difference in mass is 0.133 grams and the molar mass of the metal is determined to be 29 grams/mol, suggesting the metallic oxide is iron (III) oxide (Fe2O3).
Iron III oxide is formed when iron combines with oxygen in the air How many grams of Fe2O3 are formed when 16.7 g of Fe reacts completely with oxygen?
To determine the mass of Fe2O3 formed, you need to first find the molar mass of Fe and Fe2O3. Then, use stoichiometry to calculate the mass of Fe2O3 that can be produced from 16.7 g of Fe. The balanced equation is 4Fe + 3O2 → 2Fe2O3, which shows that 4 mol of Fe produces 2 mol of Fe2O3. By converting 16.7 g of Fe to moles, you can then use the mole ratio to find the grams of Fe2O3 formed.
