Atomic Mass of Fe: 55.8g/mol
Atomic Mass of O: 16g/mol
Molecular mass of Fe2O3: 2(55.8)+3(16) = 159.6g/mol
mass = Molecular mass x number of moles
mass = 159.6g/mol x 0.7891mol = 125.94g
Ferric oxide often refers to iron (III) oxide, which has a chemical formula Fe2O3. The atomic mass of iron (Fe) is 55.85 g/mol, and the atomic mass of oxygen (O) is 16.00 g/mol. Therefore, the molar mass of Fe2O3 is 159.69 g/mol. To calculate the percentage composition of iron (III) oxide, divide the atomic mass of iron by the molar mass of the compound and multiply by 100. So, (2 * 55.85) / 159.69 ≈ 0.698 or 69.8% is the percent of ferric oxide.
Atomic mass of Fe: 55.8g/mol Atomic mass of O: 16g/mol Molecular mass of Fe2O3: 2(55.8)+3(16) = 159.6g/mol mass = Molecular mass x number of moles mass = 159.6g/mol x 0.7891mol = 125.94g
Atomic Mass of Fe: 55.8g/mol Atomic mass of O: 16g/mol Molecular mass of Fe2O3: 2(55.8)+3(16) = 159.6g/mol mass = Molecular mass x number of moles mass = 159.6g/mol x 0.7891mol = 125.94g
The molar mass of lithium oxide (Li2O) is 29.88 g/mol.
The relative formula mass of lead oxide (PbO) is calculated by adding the atomic masses of the elements in the formula. The atomic mass of lead (Pb) is 207.2 g/mol, and the atomic mass of oxygen (O) is 16.0 g/mol. Therefore, the relative formula mass of lead oxide is 207.2 + 16.0 = 223.2 g/mol.
Ferric oxide often refers to iron (III) oxide, which has a chemical formula Fe2O3. The atomic mass of iron (Fe) is 55.85 g/mol, and the atomic mass of oxygen (O) is 16.00 g/mol. Therefore, the molar mass of Fe2O3 is 159.69 g/mol. To calculate the percentage composition of iron (III) oxide, divide the atomic mass of iron by the molar mass of the compound and multiply by 100. So, (2 * 55.85) / 159.69 ≈ 0.698 or 69.8% is the percent of ferric oxide.
Atomic mass of Fe: 55.8g/mol Atomic mass of O: 16g/mol Molecular mass of Fe2O3: 2(55.8)+3(16) = 159.6g/mol mass = Molecular mass x number of moles mass = 159.6g/mol x 0.7891mol = 125.94g
Atomic Mass of Fe: 55.8g/mol Atomic mass of O: 16g/mol Molecular mass of Fe2O3: 2(55.8)+3(16) = 159.6g/mol mass = Molecular mass x number of moles mass = 159.6g/mol x 0.7891mol = 125.94g
The molar mass of ferric ammonium citrate is approximately 270.00 g/mol.
The molar mass of lithium oxide (Li2O) is 29.88 g/mol.
To find the mass of 24.6 formula units of magnesium oxide, we first need to determine the molar mass of magnesium oxide. Magnesium has a molar mass of approximately 24.3 g/mol, and oxygen has a molar mass of approximately 16.0 g/mol. Therefore, the molar mass of magnesium oxide (MgO) is 24.3 + 16.0 = 40.3 g/mol. Next, we multiply the molar mass of MgO by the number of formula units (24.6) to find the total mass: 40.3 g/mol x 24.6 = 992.38 grams. Therefore, the mass of 24.6 formula units of magnesium oxide is approximately 992.38 grams.
The relative formula mass of lead oxide (PbO) is calculated by adding the atomic masses of the elements in the formula. The atomic mass of lead (Pb) is 207.2 g/mol, and the atomic mass of oxygen (O) is 16.0 g/mol. Therefore, the relative formula mass of lead oxide is 207.2 + 16.0 = 223.2 g/mol.
To find the number of moles, you need to divide the mass of copper oxide by its molar mass. The molar mass of copper oxide (CuO) is approximately 79.55 g/mol. Therefore, 7.95g of copper oxide is equal to 0.1 moles (7.95g / 79.55 g/mol).
61.979 g mol-1
This suggests the substance is lithium oxide (Li2O). The molar mass of Li2O is 29.88 g/mol. Therefore, 62g of Li2O is equivalent to 2.07 moles (62g / 29.88 g/mol = 2.07 mol).
Aluminum Oxide is Al2O3 and Al = 27 and oxygen =16 so the molar mass is 102 g/mol Al2O33.75 mol Al ~ 3.75/2 mol Al2O3 ~ (3.75/2)mol * 102 g/mol = 191.25 = 191 gram Al2O3
The molar mass of tribromine oxide (Br3O) can be calculated by adding up the atomic masses of its constituent atoms. The molar mass of bromine (Br) is approximately 79.90 g/mol, and the molar mass of oxygen (O) is approximately 16.00 g/mol. Therefore, the molar mass of tribromine oxide is approximately 249.70 g/mol.