Aluminum Oxide is Al2O3 and Al = 27 and oxygen =16 so the molar mass is 102 g/mol Al2O3
3.75 mol Al ~ 3.75/2 mol Al2O3 ~ (3.75/2)mol * 102 g/mol = 191.25 = 191 gram Al2O3
2 moles of aluminum to 3 moles of oxygen
This value is 38,9 mol.
The balanced chemical equation for the reaction between aluminum (Al) and oxygen (Oβ) to form aluminum oxide (AlβOβ) is: [ 4 \text{ Al} + 3 \text{ O}_2 \rightarrow 2 \text{ Al}_2\text{O}_3 ] According to the balanced equation, 4 moles of aluminum (Al) produce 2 moles of aluminum oxide (AlβOβ). Therefore, if 4.0 moles of aluminum completely react, it will produce ( \frac{2}{4} \times 4.0 ) moles of aluminum oxide. Calculate that to find the answer.
4 moles
33 grams aluminum (1 mole Al/26.98 grams) = 1.2 moles of aluminum ================
2 moles of aluminum to 3 moles of oxygen
This value is 38,9 mol.
The balanced chemical equation for the reaction between aluminum (Al) and oxygen (Oβ) to form aluminum oxide (AlβOβ) is: [ 4 \text{ Al} + 3 \text{ O}_2 \rightarrow 2 \text{ Al}_2\text{O}_3 ] According to the balanced equation, 4 moles of aluminum (Al) produce 2 moles of aluminum oxide (AlβOβ). Therefore, if 4.0 moles of aluminum completely react, it will produce ( \frac{2}{4} \times 4.0 ) moles of aluminum oxide. Calculate that to find the answer.
4 moles
4 moles
No moles of oxygen are produced by complete combustion of propane. Oxygen is CONSUMED, not produced. For combustion of 4 moles of propane, it will use 20 moles of oxygen.
33 grams aluminum (1 mole Al/26.98 grams) = 1.2 moles of aluminum ================
1,075 moles of aluminium chloride are obtained.
Steps to take: Write the chemical formula : Al2O3 Calculate the number of moles for aluminum oxide. You should know the formula which is the mass given (0.051g) divided by the Mass of aluminum oxide. Since there is '2' moles of Aluminium you multiplly the number of moles calculated for aluminum oxide by 2. Then you have calculated the number of Ions.
depends on how much aluminum oxide you have, 1gram, 2 billion Kg? how many? cant find the number of moles of oxygen without knowing the mass of the al203
there are two moles produced in potassium nitrate.
0,6 moles of (ClO4)3- and 0,2 mol Al