2 moles of aluminum to 3 moles of oxygen
The mole ratio of oxygen to pentane in the balanced chemical equation for the combustion of pentane is 13:1. This means that 13 moles of oxygen are required to completely react with 1 mole of pentane.
Yes.Explanationary:27 g Al = 1.0 mole Al24 g = 1.5 mole O2 so this ratio (in mole) is 1:1.52Al + 3O2 --> Al2O3 so the balanced mole ratio is 2:3 or 1:1.5
To determine the theoretical yield of aluminum oxide, we first need to write a balanced chemical equation for the reaction between aluminum and oxygen to form aluminum oxide. The balanced equation is 4Al + 3O2 -> 2Al2O3. From the equation, we can see that 4 moles of aluminum react with 3 moles of oxygen to produce 2 moles of aluminum oxide. Therefore, if 2.40 moles of aluminum is exposed to 2.10 moles of oxygen, the limiting reactant is oxygen. Using stoichiometry, we can calculate the theoretical yield of aluminum oxide, which is 1.60 moles.
The molar ratio of hydrogen to oxygen in water (H2O) is 2:1. This means that for every 2 moles of hydrogen, there is 1 mole of oxygen.
The balanced chemical equation for the combustion of methane is CH4 + 2O2 -> CO2 + 2H2O. This means that the mole ratio of air to methane gas is 2:1, as two moles of oxygen from the air are required to react with one mole of methane gas.
The mole ratio of oxygen to pentane in the balanced chemical equation for the combustion of pentane is 13:1. This means that 13 moles of oxygen are required to completely react with 1 mole of pentane.
Yes.Explanationary:27 g Al = 1.0 mole Al24 g = 1.5 mole O2 so this ratio (in mole) is 1:1.52Al + 3O2 --> Al2O3 so the balanced mole ratio is 2:3 or 1:1.5
To determine the mole ratio of mercury to oxygen in a sample, you need to know the chemical formula of the compound containing these elements. For example, in mercuric oxide (HgO), the mole ratio of mercury to oxygen is 1:1. If the sample is a different compound, the ratio will vary accordingly based on its chemical formula. Without specific information about the compound, the mole ratio cannot be accurately defined.
To determine the theoretical yield of aluminum oxide, we first need to write a balanced chemical equation for the reaction between aluminum and oxygen to form aluminum oxide. The balanced equation is 4Al + 3O2 -> 2Al2O3. From the equation, we can see that 4 moles of aluminum react with 3 moles of oxygen to produce 2 moles of aluminum oxide. Therefore, if 2.40 moles of aluminum is exposed to 2.10 moles of oxygen, the limiting reactant is oxygen. Using stoichiometry, we can calculate the theoretical yield of aluminum oxide, which is 1.60 moles.
If the magnesium is not polished, there may be impurities or oxides on the surface that could affect the reported mole ratio of oxygen to magnesium. This could result in a higher reported mole ratio due to the presence of excess oxygen-containing compounds on the surface, leading to an inaccurate measurement of the actual ratio of oxygen to magnesium.
The empirical formula of aluminum oxide is Al2O3, which indicates that each aluminum atom is bonded to two oxygen atoms. This ratio of aluminum to oxygen atoms is the simplest whole number ratio in which they combine.
Three atoms of oxygen are required to react with each two atoms of aluminum to form the most common product of reaction between oxygen and aluminum. Therefore, 0.75 mole of oxygen atoms will be required to react with 0.5 mole of aluminum atoms. The atomic weight of oxygen is 15.999; therefore, the mass will be (0.75)(15.999) = 12 grams of oxygen, to the maximum possibly justified number of significant digits.
No. According to the law of definite proportions, the mole ratio will always be the same.
The molar ratio of hydrogen to oxygen in water (H2O) is 2:1. This means that for every 2 moles of hydrogen, there is 1 mole of oxygen.
Aluminum oxide has the molecular formula of Al2O3. It is composed of aluminum (Al) and oxygen (O) and is 102.0 grams per mole.
The balanced chemical equation for the combustion of methane is CH4 + 2O2 -> CO2 + 2H2O. This means that the mole ratio of air to methane gas is 2:1, as two moles of oxygen from the air are required to react with one mole of methane gas.
The mole ratio of carbon (C) to oxygen (O) depends on the specific compound or reaction you are considering. For example, in carbon dioxide (CO₂), the mole ratio of C to O is 1:2, while in carbon monoxide (CO), it is 1:1. To determine the mole ratio, you must analyze the chemical formula or the reaction in question.