The mole ratio of oxygen to pentane in the balanced chemical equation for the combustion of pentane is 13:1. This means that 13 moles of oxygen are required to completely react with 1 mole of pentane.
The molecular weight of pentane is approximately 72.15 grams per mole. So, one mole of pentane weighs 72.15 grams.
The balanced chemical equation for the combustion of pentane C5H12 is: C5H12 + 8O2 → 5CO2 + 6H2O Therefore, for every 1 mole of pentane, 8 moles of oxygen gas are required. So, 0.100 mol of pentane will require 0.100 mol * 8 = 0.800 mol of oxygen gas to react completely.
The mole ratio of aluminum to oxygen in aluminum oxide (Al2O3) is 4:3, which means for every 4 moles of aluminum, there are 3 moles of oxygen.
The molar ratio of hydrogen to oxygen in water (H2O) is 2:1. This means that for every 2 moles of hydrogen, there is 1 mole of oxygen.
The balanced chemical equation for the combustion of methane is CH4 + 2O2 -> CO2 + 2H2O. This means that the mole ratio of air to methane gas is 2:1, as two moles of oxygen from the air are required to react with one mole of methane gas.
The molecular weight of pentane is approximately 72.15 grams per mole. So, one mole of pentane weighs 72.15 grams.
The balanced chemical equation for the combustion of pentane C5H12 is: C5H12 + 8O2 → 5CO2 + 6H2O Therefore, for every 1 mole of pentane, 8 moles of oxygen gas are required. So, 0.100 mol of pentane will require 0.100 mol * 8 = 0.800 mol of oxygen gas to react completely.
If the magnesium is not polished, there may be impurities or oxides on the surface that could affect the reported mole ratio of oxygen to magnesium. This could result in a higher reported mole ratio due to the presence of excess oxygen-containing compounds on the surface, leading to an inaccurate measurement of the actual ratio of oxygen to magnesium.
The mole ratio of aluminum to oxygen in aluminum oxide (Al2O3) is 4:3, which means for every 4 moles of aluminum, there are 3 moles of oxygen.
No. According to the law of definite proportions, the mole ratio will always be the same.
The molar ratio of hydrogen to oxygen in water (H2O) is 2:1. This means that for every 2 moles of hydrogen, there is 1 mole of oxygen.
The balanced chemical equation for the combustion of methane is CH4 + 2O2 -> CO2 + 2H2O. This means that the mole ratio of air to methane gas is 2:1, as two moles of oxygen from the air are required to react with one mole of methane gas.
Pentane reacts with the oxygen in an excess of air to form five molecules of carbon dioxide and six molecules of water from each molecule of pentane; substantial heat is released by the reaction.
The product of the reaction of pentane reacting with oxygen is carbon dioxide and water. This is due to the combustion of pentane in the presence of oxygen, which produces carbon dioxide and water as the final products.
Burning pentane, C5H12, is a combustion reaction in which pentane and oxygen will react to form carbon dioxide and water. The chemical equation is C5H12 + 8O2 --> 5CO2 + 6H2O
Start with a balanced equation: C5H12 + 8O2 --> 5CO2 + 6H2OFind the number of moles of water in 72 g: FW of H2O is 18 g/mol so 72g/18g/mol is 4 molRecall from the balanced equation the number of moles of water produced for each mole of Pentane: 6 waters for each pentaneYou produce 4 moles of water so the ratio from the balanced equation says you will need 4/6 mole of pentaneFind the FW of the pentane: It (coincidentally) comes 72 grams/molSo, 0.67 mol of pentane times 72 g/mol will give the final answer of 48.24 grams
Yes.Explanationary:27 g Al = 1.0 mole Al24 g = 1.5 mole O2 so this ratio (in mole) is 1:1.52Al + 3O2 --> Al2O3 so the balanced mole ratio is 2:3 or 1:1.5