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If by "air" you mean oxygen, then the mole ratio can by found by balancing a reaction equation. CH4 + 202 -> CO2 + 2H2O The ratio is 1:2.

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15y ago
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2mo ago

The balanced chemical equation for the combustion of methane is CH4 + 2O2 -> CO2 + 2H2O. This means that the mole ratio of air to methane gas is 2:1, as two moles of oxygen from the air are required to react with one mole of methane gas.

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Q: What is the mole ratio of air to methane gas in the cumbustion of methane?
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