If by "air" you mean oxygen, then the mole ratio can by found by balancing a reaction equation. CH4 + 202 -> CO2 + 2H2O The ratio is 1:2.
The stoichiometric air-fuel ratio for nitromethane (CH3NO2) is approximately 1.7:1, which means that 1.7 moles of air are needed for every mole of nitromethane to achieve complete combustion. This ratio is based on the stoichiometry of the reaction between nitromethane and oxygen (O2) in air.
Methane gas settles down because methane gas is heavier than and is carried by the upward displacement of air. ---------------------------------------------- The density of methane is 0,717 g/L and the density of air is 1,2 g/L at 0 0C; consequently methane gas raise in the air.
CH4 + 2 O2 --> CO2 + 2 H2Ox / 64 = 1 / 16x = 4 g oxygenAssuming oxygen is 20% oxygen...4 = .2 xx = 20 g air that is one possible answer.A better answer--- air is 20% oxygen by volume and 80% nitrogen by volume.1g methane / 16 = 0.0625 mole0.0625 / 1mole meth = x / 2mole oxyx = 0.125 mole oxygen =20% of air--- 0.625 mole 'air'0.2 x 32 + 0.8 x 28 = 28.8 g/mole of air0.625 x 28.8 = 18 grams of airSince air is 20% oxygen by volume, the 2nd answer is best.
The mole fraction of oxygen gas in air is approximately 0.21. This means that out of every 1 mole of air, 0.21 moles are oxygen gas molecules.
The balanced chemical equation for methane (CH4) burning in air (O2) is: CH4 + 2O2 → CO2 + 2H2O
Wrong air/fuel ratio Poor atomisation of fuel Poor spark Incorrect timing of spark
The stoichiometric air-fuel ratio for nitromethane (CH3NO2) is approximately 1.7:1, which means that 1.7 moles of air are needed for every mole of nitromethane to achieve complete combustion. This ratio is based on the stoichiometry of the reaction between nitromethane and oxygen (O2) in air.
air,fuel and a heat source
Methane gas settles down because methane gas is heavier than and is carried by the upward displacement of air. ---------------------------------------------- The density of methane is 0,717 g/L and the density of air is 1,2 g/L at 0 0C; consequently methane gas raise in the air.
Yes methane is lighter than air because it is less dense than air.
The fact that it oxidizes in air is a chemical property of methane.
CH4 + 2 O2 --> CO2 + 2 H2Ox / 64 = 1 / 16x = 4 g oxygenAssuming oxygen is 20% oxygen...4 = .2 xx = 20 g air that is one possible answer.A better answer--- air is 20% oxygen by volume and 80% nitrogen by volume.1g methane / 16 = 0.0625 mole0.0625 / 1mole meth = x / 2mole oxyx = 0.125 mole oxygen =20% of air--- 0.625 mole 'air'0.2 x 32 + 0.8 x 28 = 28.8 g/mole of air0.625 x 28.8 = 18 grams of airSince air is 20% oxygen by volume, the 2nd answer is best.
Flatulence contains a portion of methane gas, and the methane portion is lighter than air.
Yes, methane can explode when there is a sufficient amount mixed with air in the presence of an ignition source. Methane is highly flammable and can form explosive mixtures in the air at certain concentrations.
It is the same as any other thing on earth. Earth's gravitational pull is the same for all mass. If it is not on Earth, then it is the same as the gravitational pull where it is located.
The mole fraction of oxygen gas in air is approximately 0.21. This means that out of every 1 mole of air, 0.21 moles are oxygen gas molecules.
nowhere