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What is the mole fraction of oxygen in a gas mixture that is 37 percent oxygen and 63 percent nitrogen in volume?
To find the mole fraction of oxygen, first convert the percentages to fractions: 37% oxygen is 0.37 and 63% nitrogen is 0.63. Since the total mole fraction in a mixture is 1, the mole fraction of oxygen would be 0.37/(0.37 + 0.63) = 0.37/1 = 0.37. Therefore, the mole fraction of oxygen in the gas mixture is 0.37.
What should the mole percent of oxygen be in the diving gas for the partial pressure of oxygen in the mixture to be 0.21 ATM the same as in air at 1 ATM?
For the partial pressure of oxygen in the mixture to be 0.21 ATM, you would need the mole percent of oxygen in the diving gas to be 21%. This is because the partial pressure of a gas in a mixture is directly proportional to its mole fraction in the mixture, assuming ideal gas behavior.
What is the particial pressure of oxygen?
The partial pressure of oxygen is a measure of the pressure exerted by oxygen in a mixture of gases. In atmospheric air at sea level, the partial pressure of oxygen is around 160 mmHg. The partial pressure of oxygen can also be calculated using the equation: partial pressure of oxygen = total pressure of gas mixture * mole fraction of oxygen gas in the mixture.
What is the mole ratio of air to methane gas in the cumbustion of methane?
The balanced chemical equation for the combustion of methane is CH4 + 2O2 -> CO2 + 2H2O. This means that the mole ratio of air to methane gas is 2:1, as two moles of oxygen from the air are required to react with one mole of methane gas.
What is th second most common gas found in the air we breathe?
This gas is oxygen - 20,946 %.
What is the mole fraction of oxygen in a gas mixture that is 37 percent oxygen and 63 percent nitrogen in volume?
To find the mole fraction of oxygen, first convert the percentages to fractions: 37% oxygen is 0.37 and 63% nitrogen is 0.63. Since the total mole fraction in a mixture is 1, the mole fraction of oxygen would be 0.37/(0.37 + 0.63) = 0.37/1 = 0.37. Therefore, the mole fraction of oxygen in the gas mixture is 0.37.
A mixture of gases contains 0.25 mol oxygen gas and 1.50 mol carbon dioxide gas at STP the mole fraction of oxygen gas in its mixture is?
The total moles of gas in the mixture is 0.25 + 1.50 = 1.75 mol. The mole fraction of oxygen gas is the moles of oxygen gas divided by the total moles, so 0.25 mol / 1.75 mol = 0.143. Therefore, the mole fraction of oxygen gas in the mixture is 0.143.
What should the mole percent of oxygen be in the diving gas for the partial pressure of oxygen in the mixture to be 0.21 ATM the same as in air at 1 ATM?
For the partial pressure of oxygen in the mixture to be 0.21 ATM, you would need the mole percent of oxygen in the diving gas to be 21%. This is because the partial pressure of a gas in a mixture is directly proportional to its mole fraction in the mixture, assuming ideal gas behavior.
What is the partial pressure of 20.84 percent of O2 in air?
The partial pressure of a gas in a mixture is equal to the total pressure of the mixture multiplied by the mole fraction of that gas. Since the mole fraction of O2 in air is 0.2084 and the total pressure of air is approximately 1 atmosphere, the partial pressure of O2 in air is approximately 0.2084 atmosphere.
When can volume fraction be equal to mole fraction?
The volume fraction of a substance is equal to the mole fraction for ideal gas mixture
What is the particial pressure of oxygen?
The partial pressure of oxygen is a measure of the pressure exerted by oxygen in a mixture of gases. In atmospheric air at sea level, the partial pressure of oxygen is around 160 mmHg. The partial pressure of oxygen can also be calculated using the equation: partial pressure of oxygen = total pressure of gas mixture * mole fraction of oxygen gas in the mixture.
What is the mole ratio of air to methane gas in the cumbustion of methane?
The balanced chemical equation for the combustion of methane is CH4 + 2O2 -> CO2 + 2H2O. This means that the mole ratio of air to methane gas is 2:1, as two moles of oxygen from the air are required to react with one mole of methane gas.
A mixture of gases contains 0.25 mol oxygen gas 0.75 mol nitrogen gas and 1.50 mol carbon dioxide gas at STP The mole fraction of carbon dioxide gas in this mixture is?
The total moles of gas in the mixture is 0.25 + 0.75 + 1.5 = 2.5 mol. The mole fraction of carbon dioxide gas is the moles of CO2 divided by the total moles of gas, which is 1.5 mol / 2.5 mol = 0.6. So, the mole fraction of carbon dioxide gas in the mixture is 0.6.
What is th second most common gas found in the air we breathe?
This gas is oxygen - 20,946 %.
What is the second most common gas found in the air we breath?
Oxygen is the second most common/abundant gas in the air that we breathe. Nitrogen is the most abundant gas in the air we breathe. The composition of air is often treated as 79 mole or volume percent N2 and 21 mole or volume percent O2.
What is the second most common gas found in the air we breathe?
Oxygen is the second most common/abundant gas in the air that we breathe. Nitrogen is the most abundant gas in the air we breathe. The composition of air is often treated as 79 mole or volume percent N2 and 21 mole or volume percent O2.
A sample of air is made up of nitrogen oxygen and argon in the mole fractions 78 percent N2 21 percent O2 and 10 percent Ar what is the density of air at standard temperature and pressure?
The molar mass of air can be calculated by adding the weighted average of nitrogen, oxygen, and argon based on their mole fractions. Then, the density of air at standard temperature and pressure can be calculated using the ideal gas law. The standard molar volume of ideal gas is 22.4 L/mol at standard temperature and pressure.
