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Yes.

Explanationary:

27 g Al = 1.0 mole Al

24 g = 1.5 mole O2 so this ratio (in mole) is 1:1.5

2Al + 3O2 --> Al2O3 so the balanced mole ratio is 2:3 or 1:1.5

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How many grams of Oxygen are needed to completely react with 5.0 grams of butane in a butane lighter?

To calculate the grams of oxygen needed, you first need to balance the chemical equation for the combustion of butane. C₄H₁₀ + O₂ → CO₂ + H₂O. From the balanced equation, 2 moles of butane react with 13 moles of oxygen. One mole of butane is 58.12 g, and one mole of oxygen is 32 g. Therefore, 5.0 g of butane would require (5.0 g / 58.12 g/mol) * 13 moles of oxygen, which is approximately 1.12 grams of oxygen.


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When the amount of oxygen is limited, carbon and oxygen react to form carbon monoxide. How many grams of CO can be formed from 35 grams of oxygen?


A 55 g sample of iron reacts with 24 g of oxygen to form how many grams of iron oxide?

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How much water wold form if 14.8 grams of hydrogen reacted with 34.8 grams of oxygen?

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Related Questions

What does aluminium react with?

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What mass of oxygen (O2) is required to react completely with 86.17 grams of C6H14?

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How much oxygen in grams will be required to react with 0.5 mole of aluminium?

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What is the total mass of water formed when 8 grams of hydrogen reacts completely with 64 grams of ovygen?

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How many grams of aluminum chloride are produced when 54 grams of aluminum react with chlorine gas?

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How many grams of Oxygen are needed to completely react with 5.0 grams of butane in a butane lighter?

To calculate the grams of oxygen needed, you first need to balance the chemical equation for the combustion of butane. C₄H₁₀ + O₂ → CO₂ + H₂O. From the balanced equation, 2 moles of butane react with 13 moles of oxygen. One mole of butane is 58.12 g, and one mole of oxygen is 32 g. Therefore, 5.0 g of butane would require (5.0 g / 58.12 g/mol) * 13 moles of oxygen, which is approximately 1.12 grams of oxygen.