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Consider the following balanced equation Fe203 plus 3H2 gives 2Fe plus 3H2O What mass of hydrogen would be required to convert 160g of iron III oxide into iron?
6g hydrogen would be required for 160g ferric oxide in this reaction.
The relative atomic weights of the elements are:
Hydrogen - 1
Oxygen - 16
Iron - 56
giving the relative atomic weights of the compounds (on the left of the equation):
Fe2O3 = 56×2 + 16×3 = 160
3H2 = 3×(1×2) = 6
So for every 160 units of mass of iron III oxide there will be 6 units of mass of hydrogen required.
→ for 160g of iron III oxide ÷ 160 × 6 = 6 g of hydrogen.
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