The balanced equation between hydrogen (H) and oxygen (O) is 2H₂ + O₂ → 2H₂O. This equation shows the reaction where hydrogen gas and oxygen gas combine to form water vapor.
The balanced equation for the reaction of lithium with water is: 2Li + 2H₂O → 2LiOH + H₂
The balanced chemical equation for the combustion of butane (C₄H₁₀) in oxygen (O₂) is: 2C₄H₁₀ + 13O₂ → 8CO₂ + 10H₂O.
The balanced equation for the reaction between calcium hydroxide (Ca(OH)₂) and sulfuric acid (H₂SO₄) is: Ca(OH)₂ + H₂SO₄ → CaSO₄ + 2H₂O.
no reaction take place between copper and water. so there is no blance equation.
The balanced equation for the reaction between lithium and oxygen is: 4Li + O2 -> 2Li2O.
The balanced equation for the reaction of lithium with water is: 2Li + 2H₂O → 2LiOH + H₂
The balanced chemical equation for the combustion of butane (C₄H₁₀) in oxygen (O₂) is: 2C₄H₁₀ + 13O₂ → 8CO₂ + 10H₂O.
2H2 + O2 --> 2H2O
The balanced equation for the reaction between calcium hydroxide (Ca(OH)₂) and sulfuric acid (H₂SO₄) is: Ca(OH)₂ + H₂SO₄ → CaSO₄ + 2H₂O.
no reaction take place between copper and water. so there is no blance equation.
The balanced equation for the reaction between lithium and oxygen is: 4Li + O2 -> 2Li2O.
The balanced equation for the combustion of C₈H₁₀ (octane) is: C₈H₁₀ + 12.5 O₂ → 8 CO₂ + 5 H₂O
The balanced symbol equation for making water is: 2H₂ + O₂ → 2H₂O.
To determine the coefficient of C₃H₈O₃ in a balanced chemical equation, we need to know the specific reaction it is involved in. For example, in the complete combustion of propane-1,2,3-triol (glycerol), the balanced equation shows that the coefficient of C₃H₈O₃ can vary depending on the products formed, typically being 1 if it is the only reactant. Please provide the specific reaction for a precise answer.
2H2 + O2 ---> 2H20 is balanced when total numbers of atoms of EACH element seperately are equal on both sides ('Reactant' and 'Product' side): Left (2x H2=) 4 H atoms and (1x2 O=) 2 O atoms Right (2x H2=) 4 H's and (2x1 O=) 2 O's
The balanced equation for the combustion of butan-1-ol (C₄H₉OH) is: C₄H₉OH + 6O₂ → 4CO₂ + 5H₂O
CH3CH2OH + 3O2 --> 2CO2 + 3H2O Reactants: 6 H; 2 C; 7 O. Products: 6 H; 2 C; 7 O