The equation ( \text{H}_2 + \text{O}_2 \rightarrow \text{H}_2\text{O} ) is not balanced as written. To balance it, you need to ensure that there are equal numbers of each type of atom on both sides. The balanced equation is ( 2\text{H}_2 + \text{O}_2 \rightarrow 2\text{H}_2\text{O} ), which has 4 hydrogen atoms and 2 oxygen atoms on both sides.
No, the equation H2 O2 - H2O is not balanced. To balance it, you would recognize that one molecule of hydrogen peroxide (H2O2) can decompose into two molecules of water (H2O) and one molecule of oxygen (O2). The balanced equation would be: 2 H2O2 → 2 H2O + O2.
Oxygen limits the reaction, so......Balanced equation. 2H2 + O2 -> 2H2O 7.89 mole H2O (1 mole O2/2 mole H2O) = 3.95 mole oxygen gas needed ------------------------------------------
To form water (H2O) from hydrogen (H2) and oxygen (O2), the balanced chemical equation is 2 H2(g) + O2(g) → 2 H2O(g). From the equation, 2 volumes of H2 produce 2 volumes of H2O, meaning 1 volume of O2 produces 2 volumes of H2O. Therefore, to form 50 L of H2O, you would need 25 L of O2(g).
First off, you decide the product (becomes easier after a while of doing chemistry). The product is H2O (water). O2+H2=>H2O, but this is not stochiometrically balanced, so you have to change the amount of H2O's on the right side of equation and then to balance the amount of hydrogens. If you add a 2 in front of both, you get O2 + 2H2 => 2H2O
The reactants in this equation are hydrogen gas (H2) and oxygen gas (O2).
No. It would have to be H2O2 - H2 = O2 in order to be balanced.
No, the equation H2 O2 - H2O is not balanced. To balance it, you would recognize that one molecule of hydrogen peroxide (H2O2) can decompose into two molecules of water (H2O) and one molecule of oxygen (O2). The balanced equation would be: 2 H2O2 → 2 H2O + O2.
It is not balanced. There should be a 2 in front of H2 and H2O
The balanced symbol equation for water is 2H2 + O2 -> 2H2O.
2 H2 + O2 = 2 H2O
= H2+O2 =2H2+O2=2H2O
Oxygen limits the reaction, so......Balanced equation. 2H2 + O2 -> 2H2O 7.89 mole H2O (1 mole O2/2 mole H2O) = 3.95 mole oxygen gas needed ------------------------------------------
The balanced chemical equation for the reaction is 2H2 + O2 -> 2H2O. Using stoichiometry, we find that 3g of H2 will react completely with 24g of O2 to form 18g of H2O. Therefore, the maximum amount of H2O formed when 3g of H2 reacts with 29g of O2 is 18g.
To form water (H2O) from hydrogen (H2) and oxygen (O2), the balanced chemical equation is 2 H2(g) + O2(g) → 2 H2O(g). From the equation, 2 volumes of H2 produce 2 volumes of H2O, meaning 1 volume of O2 produces 2 volumes of H2O. Therefore, to form 50 L of H2O, you would need 25 L of O2(g).
Water decomposes into Oxygen and Hydrogen gases, each of which is a 2 atom molecule: H20 -> H2 + O2 BUT that's not balanced - there's Oxygen 'appearing' from nowhere on the right side so to balance it (2) H2O -> H2 + O2 But now we have 4 Hydrogens on left and only two on right (2) H2O -> (2)H2 + O2 4 hydrogens and 2 oxygen - > 4 hydrogens and 2 Oxygens Balanced!
The chemical equation given “H2 + O2 -> H2O” is not balanced. To balance it, you need to modify the coefficients in front of the molecules. The balanced equation should be: "2H2 + O2 -> 2H2O" where you have two molecules of hydrogen gas reacting with one molecule of oxygen gas to produce two molecules of water.
First off, you decide the product (becomes easier after a while of doing chemistry). The product is H2O (water). O2+H2=>H2O, but this is not stochiometrically balanced, so you have to change the amount of H2O's on the right side of equation and then to balance the amount of hydrogens. If you add a 2 in front of both, you get O2 + 2H2 => 2H2O