To find the number of atoms in 0.670 grams of P2O5, first calculate the molar mass of P2O5, which is approximately 283.88 g/mol. Next, determine the number of moles in 0.670 grams by dividing the mass by the molar mass: 0.670 g / 283.88 g/mol ≈ 0.00236 moles. Since each molecule of P2O5 contains 7 atoms (2 phosphorus and 5 oxygen), multiply the number of moles by Avogadro's number (approximately (6.022 \times 10^{23}) molecules/mol) and then by 7 to find the total number of atoms: 0.00236 moles × (6.022 \times 10^{23}) molecules/mol × 7 ≈ 9.86 × (10^{20}) atoms.
From every two atoms of P, one molecule of P2O5 is formed. The relative formula mass of two atoms of P (phosphorous) is 62, whereas for one molecule of P2O5 it is 142. The mass of P2O5 formed is therefore 142/62 times the mass of P we started with. This comes out to 286.3g (to one decimal place).
Molar mass of P2O5 is 142gmol-1. You need 17.2 moles of p.
In the chemical formula P2O5, there are 2 phosphorus (P) atoms and 5 oxygen (O) atoms. To find the total number of atoms, you simply add these numbers together: 2 + 5 = 7. Therefore, there are a total of 7 atoms in P2O5.
The balanced equation for the reaction must be given to determine the molar ratio between O2 and P2O5. Without that information, it is not possible to determine the exact number of moles of P2O5 produced from 8.00 moles of O2.
To find the number of moles in 16 grams of O₂, you can use the molar mass of oxygen. The molar mass of O₂ (oxygen gas) is approximately 32 grams per mole (16 grams/mole for each oxygen atom, and there are two atoms in O₂). Therefore, the number of moles in 16 grams of O₂ is calculated as follows: 16 grams ÷ 32 grams/mole = 0.5 moles. Thus, there are 0.5 moles of O₂ in 16 grams.
To find the number of atoms in 740 g of P2O5, we need to first convert the mass to moles using the molar mass of P2O5, which is 141.94 g/mol. Then, we can use Avogadro's number (6.022 x 10^23) to find the number of atoms. So, 740 g of P2O5 is equal to approximately 5.21 moles, which is equivalent to 3.14 x 10^24 atoms.
From every two atoms of P, one molecule of P2O5 is formed. The relative formula mass of two atoms of P (phosphorous) is 62, whereas for one molecule of P2O5 it is 142. The mass of P2O5 formed is therefore 142/62 times the mass of P we started with. This comes out to 286.3g (to one decimal place).
There are 1.15 x 10^21 atoms in 0.220 g of P2O5.
The atom doesn't contain gram which is a unit of mass.
Molar mass of P2O5 is 142gmol-1. You need 17.2 moles of p.
To find the total number of atoms in 0.750 mol of P2O5, first calculate the molar mass of P2O5 (141.94 g/mol). Then multiply the molar mass by Avogadro's number (6.022 x 10^23 atoms/mol) to find the total number of atoms in 0.750 mol.
5, the subscript immediately after the atomic symbol O for oxygen.
117 grams of sodium chloride (NaCl) is equivalent to 117 grams of chlorine gas because each molecule of NaCl contains one sodium atom and one chlorine atom.
1 atom-gram of uranium = 238,02891 grams
The formula P2O5, could itself represent one molecule of diphosphorus pentoxide. Or you could specify any number of moles. One mole of P2O5 would be 6.022 x 1023 molecules of P2O5. Two moles would be 1.204 x 1024 molecules, and so on.
In the chemical formula P2O5, there are 2 phosphorus (P) atoms and 5 oxygen (O) atoms. To find the total number of atoms, you simply add these numbers together: 2 + 5 = 7. Therefore, there are a total of 7 atoms in P2O5.
In one molecule of diphosphorus pentoxide (P2O5), there are 5 oxygen atoms. So, in 5.00 mol of P2O5, there would be 5.00 mol * 5 = 25.00 moles of oxygen atoms.