Balanced equation first.
4P + 5O2 -> 2P2O5
8.00 mole O2 (2 mole P2O5/5 mole O2)
= 3.20 moles P2O5 produced
800 g oxygen are needed.
0.035mol. Apply to PV=nRT
At STP, assuming petrol is octane with a density of .8 ---- 1 L x .8 = 800 grams --- octane has a molar mass of 116 g/mole --- 800 g / 116 = 7 moles 1 mole of vapour (gas) at STP occupies 22.4 L 22.4 x 7 = 156.8 Liters
For this you need the atomic mass of Na. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.2.1 moles Na × (23.0 grams) = 48.3 grams Na
There are 800,000 metres in 800 kilometres.
In 0.800 moles of MgO, there are the same number of oxygen atoms as there are in 0.800 moles of O atoms. One mole of MgO contains one mole of oxygen atoms, which is equivalent to 6.022 x 10^23 oxygen atoms.
25 moles of sulfur dioxide contain 600 grams of oxygen. Each mole of SO2 contains 2 moles of oxygen, and the molar mass of O is 16 g/mol. So, 25 moles x 2 moles = 50 moles of O, which is 50 moles x 16 g/mol = 800 g of O.
800 g oxygen are needed.
Sulfur dioxide is SO2, so there are 2 moles of oxygen for each mole of sulfur. In 25 moles of SO2, there are 25 moles of S, so there must be 50 moles of oxygen, or 25 moles of diatomic oxygen gas (O2).
0.035mol. Apply to PV=nRT
At STP, assuming petrol is octane with a density of .8 ---- 1 L x .8 = 800 grams --- octane has a molar mass of 116 g/mole --- 800 g / 116 = 7 moles 1 mole of vapour (gas) at STP occupies 22.4 L 22.4 x 7 = 156.8 Liters
For this you need the atomic mass of Na. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.2.1 moles Na × (23.0 grams) = 48.3 grams Na
How many 25¢ is in $800
A pioneer in Agricultural science, Luther Burbank produced over 800 varieties of plants using genetic engineering. He developed the spineless cactus and the plumcot.
800mL equals 80cL
There are 800 millions in 800 million.
It goes in 800 times.