Assuming 0.75 g of P2O5,
moles of P2O5 = 0.0053 moles
1 molecule of P2O5 has 7 atoms.
so reqd. no. is 2.23 X 1022.
There are 1.15 x 10^21 atoms in 0.220 g of P2O5.
To find the total number of atoms in 0.850 g of P2O5, we need to first calculate the number of moles of P2O5 using its molar mass. Then, using Avogadro's number (6.022 x 10^23 atoms/mole), we can determine the total number of atoms. Finally, the answer is approximately 2.57 x 10^22 atoms in 0.850 g of P2O5.
There are 200 atoms in 25 molecules of P2O5. Each molecule of P2O5 contains a total of 7 atoms (2 phosphorus atoms and 5 oxygen atoms). Multiplying this by 25 molecules gives a total of 175 atoms from oxygen and 50 atoms from phosphorus, adding up to 200 atoms in total.
The formula P2O5, could itself represent one molecule of diphosphorus pentoxide. Or you could specify any number of moles. One mole of P2O5 would be 6.022 x 1023 molecules of P2O5. Two moles would be 1.204 x 1024 molecules, and so on.
P2O5 2 atoms of phosphorous 5 atoms of oxygen ------------------------------+ 7 atoms altogether
In the chemical formula P2O5, there are 2 phosphorus (P) atoms and 5 oxygen (O) atoms. To find the total number of atoms, you simply add these numbers together: 2 + 5 = 7. Therefore, there are a total of 7 atoms in P2O5.
There are 1.15 x 10^21 atoms in 0.220 g of P2O5.
To find the total number of atoms in 0.850 g of P2O5, we need to first calculate the number of moles of P2O5 using its molar mass. Then, using Avogadro's number (6.022 x 10^23 atoms/mole), we can determine the total number of atoms. Finally, the answer is approximately 2.57 x 10^22 atoms in 0.850 g of P2O5.
There are 200 atoms in 25 molecules of P2O5. Each molecule of P2O5 contains a total of 7 atoms (2 phosphorus atoms and 5 oxygen atoms). Multiplying this by 25 molecules gives a total of 175 atoms from oxygen and 50 atoms from phosphorus, adding up to 200 atoms in total.
The formula P2O5, could itself represent one molecule of diphosphorus pentoxide. Or you could specify any number of moles. One mole of P2O5 would be 6.022 x 1023 molecules of P2O5. Two moles would be 1.204 x 1024 molecules, and so on.
P2O5 2 atoms of phosphorous 5 atoms of oxygen ------------------------------+ 7 atoms altogether
5, the subscript immediately after the atomic symbol O for oxygen.
To find the number of atoms in 740 g of P2O5, we need to first convert the mass to moles using the molar mass of P2O5, which is 141.94 g/mol. Then, we can use Avogadro's number (6.022 x 10^23) to find the number of atoms. So, 740 g of P2O5 is equal to approximately 5.21 moles, which is equivalent to 3.14 x 10^24 atoms.
In one molecule of diphosphorus pentoxide (P2O5), there are 5 oxygen atoms. So, in 5.00 mol of P2O5, there would be 5.00 mol * 5 = 25.00 moles of oxygen atoms.
P2O5 stands for diphosphorus pentoxide. It is a chemical compound composed of two phosphorus atoms bonded to five oxygen atoms.
P is phosphorus, O is oxygen P2O5 molecules have two (di-) P atoms, and five (pent-) O atoms, so the name of the compound is diphosphorus pentoxide.
The valency of phosphorus in P2O5 is +5. This is because each oxygen atom has a valency of -2, and since there are 5 oxygen atoms in P2O5, the total negative charge is -10. To balance this, the phosphorus atom must have a valency of +5.