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How much does 2.18 mol of Cu weigh?

Updated: 4/28/2022
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139 g Cu

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Q: How much does 2.18 mol of Cu weigh?
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How does 2.18 mol of Cu weigh?

A 2.18 moles of Cu has a weight of 138.53 g. This is obtained by multiplying the 2.18 by the weight of 1 mole of Cu.


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How many grams do 4.6 x1025 atoms of cu weigh?

I assume you mean 4.6 X 10^25 atoms. This is the conversion. 4.6 X 10^25 atoms Cu ( 1mol Cu/ 6.022 X 10^23 )( 63.55 grams Cu/ 1 mol Cu ) = 4854.37 grams Cu


How much does 1 cu meter of copper weigh?

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Calculate the number of atoms in 61.0 g of Cu?

The molar mass of copper is its atomic weight on the periodic table in g/mol, and is 63.5g/mol We know that one mole of copper contains 6.022×10^23 atoms of copper . First convert given mass to moles, and moles to atoms. = 61.0 g Cu × (1 mol Cu / 63.5 g per mol) ×6.022 × 10 ^23 atom cu / 1 mol Cu) = 5.78× 10^23. atoms. 61 g Cu 5.7 ×10^23 atoms of Cu.


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What is the molecular weight of Cu?

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How do you get moles Chemistry?

The mole in chemistry is also called the chemist's dozen and is defined as the amount of material containing 6.0221421 X10^23 particles(This number is called Avogadro's number) The value of mole is the number of particles in excactly 12 grams of c-12, so, if you have 12grams of c-12 , you will have 6.022x10^23 carbon atoms ,which is also a mol of C. For any other element a mol of that element is the Atomic Mass expressed as grams. 0.0265 g C find mol of C plan gC -> mol C 1 mol / 12.01 g C ( relationship; 1 mol C = 12.01 g C ) 0.0265 g C x 1 mol C / 12.01 g C = 2.21 x 10 ^-3 mol C to find atoms change to mol then times 6.022X10^23 3.10g Cu find Cu atoms plan g -> mol cu -> atoms Cu (3.10 g cu )x (1 mol Cu /63.55 g Cu ) ( 6.022 x 10^23 / 1 mol cu = 2.94 x 10^22 Cu atoms


How much does 1 cu ft of miracle grow weigh?

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How many grams of Cu(OH)2 can be produced from the reaction of 0.500g Cu with 30.0mL of 3.0M NaOH?

Cu + 2NaOH ---> Cu(OH)2 + 2NaSince we have a finite amount of two reactants we must first determine which is the limiting reactant. For Cu: n= m/M = 0.500 g/63.53 g/mol = 7.87E-3 mol For NaOH: n = CV = (3.0 mol/L)(0.0300 L) = 9.00E-2 mol Copper is by far the limiting reactant therefore we will use its amount to find the maximum Cu(OH)2 that can be yielded from the reaction. Since the above reaction scheme indicates that Cu and Cu(OH)2 are in a 1 to 1 ratio, their molar amounts are the same ie. at the end of the reaction there will be 7.87E-3 mol of Cu(OH)2 To find the mass that corresponds to this molar amount we multiply by the molar mass of Cu(OH)2 (97.56 g/mol): m=nM = (7.87E-3 mol)(97.56 g/mol) = 0.7678 g Therefore 0.500 g of Cu will yield 0.768 g (3 sig fig) of Cu(OH)2.