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The mas is 3.61 grams.

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10y ago

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When 250. mL of a 0.15 M solution of ammonium sulfide (NH4)2S is poured into 120. mL of a 0.053 M solution of cadmium sulfate CdSO4 how many grams of a yellow precipitate of cadmium sulfide CdS are fo?

To determine the amount of cadmium sulfide (CdS) precipitate formed, you would need to calculate the limiting reagent between (NH4)2S and CdSO4. Once you have the limiting reagent, use stoichiometry to calculate the amount of CdS formed. Given the balanced chemical equation CdSO4 + (NH4)2S -> CdS + (NH4)2SO4 and the molar mass of CdS, calculate the mass of CdS precipitated.


Mass in grams of 6.76x10-3 of CdS?

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