How many atoms are present in 16g of O and 8g of S?

Answer 1

To calculate the number of atoms present in a given mass of a substance, we need to use the concept of molar mass and Avogadro's number. The molar mass of oxygen (O) is approximately 16 g/mol, and the molar mass of sulfur (S) is approximately 32 g/mol.

For oxygen: 16g / 16 g/mol = 1 mol of O. 1 mol of O contains 6.022 x 10^23 atoms (Avogadro's number). Therefore, 16g of O contains 6.022 x 10^23 atoms.

For sulfur: 8g / 32 g/mol = 0.25 mol of S. 0.25 mol of S contains 0.25 x 6.022 x 10^23 atoms = 1.5055 x 10^23 atoms.

Therefore, there are approximately 6.022 x 10^23 atoms in 16g of oxygen and approximately 1.5055 x 10^23 atoms in 8g of sulfur.

Answer 2

Oh, dude, let's break out the Periodic Table for this one! So, oxygen has a molar mass of 16 g/mol, and sulfur has a molar mass of 32 g/mol. So, in 16g of oxygen, you have 1 mole, which is 6.022 x 10^23 atoms. In 8g of sulfur, you have 0.25 moles, which is 1.506 x 10^23 atoms. So, in total, you have around 7.528 x 10^23 atoms. Like, that's a lot of atoms, man.

Answer 3

16 g O x 1 mol/16 g = 1 mole and 1 mole = 6.02x10^23 atoms of O
8g S x 1 mol/32 g = 0..25 moles S and then 0..25 moles x 6.02x10^23 atoms/mole = 1.5x10^23 atoms of S, or rounding to 1 significant figure, you have 2x10^23 atoms of S

Answer 4

In 16g of O, there are (16 g \times \frac{1 \text{mol}}{16.00 g} \times 6.022 \times 10^{23} \text{atoms/mol} = 6.022 \times 10^{23} \text{atoms}) of O. Similarly, in 8g of S, there are (8 g \times \frac{1 \text{mol}}{32.07 g} \times 6.022 \times 10^{23} \text{atoms/mol} = 1.506 \times 10^{23} \text{atoms}) of S.

Answer 5

16 g of oxygen have 3,011.1023 atoms.
8 g of sulfur have 1,503.1023 atoms.

Answer 6

Approx 7.525*10^23 atoms.