8g / 18 g/mol H2O = .44 moles H2O
There are 4.17 moles of H2O present in 75.0g of H2O.
2.5 moles H2O (2 moles H/1 mole H2O) = 5 moles of hydrogen
For the reaction 2 H2 + O2 -> 2 H2O, we see that 1 mole of O2 produces 2 moles of H2O. Therefore, to produce 10.2 moles of H2O, we would need 5.1 moles of O2.
1 mole is equal to 18 grams of H2O, so 60 grams is 3.33 moles.
Using the molar mass of nh3, we find that we have 2.5 moles of nh3. Since 3 moles of h2o are produced per 2 moles of nh3, we see that we will produce 3.75 moles of h2o. This is equivalent to around 3.79 g.
The answer is 8,33 moles.
The answer is 0,44 moles.
There are 4.17 moles of H2O present in 75.0g of H2O.
3.0 moles of H2O have 54 g.
2.5 moles H2O (2 moles H/1 mole H2O) = 5 moles of hydrogen
H2O or water doesn't have any helium in it.
The answer is 97,66 moles.
For the reaction 2 H2 + O2 -> 2 H2O, we see that 1 mole of O2 produces 2 moles of H2O. Therefore, to produce 10.2 moles of H2O, we would need 5.1 moles of O2.
1 mole is equal to 18 grams of H2O, so 60 grams is 3.33 moles.
To find the number of moles in 117g of H2O, you first need to determine the molar mass of H2O, which is approximately 18 g/mol. Then, divide the mass given (117g) by the molar mass to find the number of moles. In this case, 117g of H2O is equal to 6.5 moles.
Using the molar mass of nh3, we find that we have 2.5 moles of nh3. Since 3 moles of h2o are produced per 2 moles of nh3, we see that we will produce 3.75 moles of h2o. This is equivalent to around 3.79 g.
To determine the moles of H2O required for the reaction with 0.24 moles of Cl2, we first need the balanced chemical equation. For example, in the reaction of chlorine gas with water, Cl2 + H2O → HCl + HOCl, one mole of Cl2 reacts with one mole of H2O. Therefore, 0.24 moles of Cl2 would require 0.24 moles of H2O.