The answer is 97,66 moles.
The nunber of moles of oxygen is 2,5.
You can make a simple balance. There are (12.36 * 3) moles of H You have 2*H to form H2. So take the total from ammonia and divide by two to find the moles of H2 required.
For this you do not have to have an Atomic Mass. Take the number of moles and multiply it by Avogadro's constant, 6.02 × 1023. Divide by one mole for units to cancel.2.5 moles × (6.02 × 1023 atoms) = 1.51 × 1024atoms in 2.5 moles
First take the molecular mass.Just multiply 2.33 by it
To convert grams to moles you need mercury's atomic mass: 200.59 grams/mole. You can then take your measurement and divide it by the atomic mass to get moles.Grams ÷ Atomic mass = Moles50.15 grams ÷ 200.59 grams = 0.2500 moles Hg
Your equation is properly balanced so for every mole of hydrogen produced it takes 2moles of sodium; therefore to produce 4.0 mol of hydrogen it would take at least 8.0 mol of sodium if the reaction were 100 % efficient.
The nunber of moles of oxygen is 2,5.
The answer is 2,68 moles.
You can make a simple balance. There are (12.36 * 3) moles of H You have 2*H to form H2. So take the total from ammonia and divide by two to find the moles of H2 required.
this is not possible yet..scientists have discovered an enzyme that can convert ethane to methane..however, if u take indirect route ..then its possible..
Moles = Mass/Molar Mass.Using this equation, we can take 25/(1.0 + 19) and find that it is equal to 1.25 moles.Keep in mind that very few significant figures were used for this example (2), and that if accuracy is to be expected, as many as possible should be used.
Why don't you do your own school assignment? Just take the Carbon part of ethane. We will ignore the Hydrogen that turns to water. When carbon burns, it will produce carbon dioxide. If one molecule contains two carbon atoms, that molecule will burn to produce two molecules of carbon dioxide. Now, you figure it out. To answer this question we need to know what the experimental temperature and pressures are and if ethane is to be considered an ideal gas. STP? RTP? That is not what your question asks. Your question asks, "How many liters of carbon dioxide will be produced. I would assume that it is talking about the same pressure, however I would not know. I would guess that the real issue is asking how much carbon dioxide will be dissolve in the water to form a weak acid and how much will remain free gas. Without more information, Ethane should be considered to be an ideal gas as should water above 100c. You can guess at the temperature by looking up the delta H and calculating with a formula. ---------------------------------------------------------- Lets suppose that the experiment is conducted at STP and that Ethane is an ideal gas. Ethane oxidizes via the formula C2H6 + 7/2 O2 -> 2 CO2 + 3H2O at STP (0'C) water will become a liquid and not contribute significantly to the final volume. At STP pressures are constant and all reactions are exothermic so T remains at 0'C (after everything settles down that is). And lets say that the water remains pure, without significant levels of Carbonic Acid. The question stated that there were 269 litres of Ethane so lets suppose that we are ignoring the initial oxygen gases as well, only considering the volume occupied by the ethane. Oxidized Ethane will produce double the volume of Carbon Dioxide so, at the very simplest, the final volume of Carbon Dioxide with be double the initial volume (of Ethane) so that would be 538 litres. This question gets a lot more complicated if you consider that real behavior of non-ideal gases and that it all takes place in a bomb calorminitor at constant pressure.
there are over 10,000,000 soccer balls in the entire world
For this you need the Atomic Mass of Cr. Take the number of moles and multiply it by the Atomic Mass. Divide by one mole for units to cancel.11.9 moles Cr × (52.0 grams) =618.8 grams Cr
it would be in your best interest to take a trip to the zoo to see moles.
For this you need the atomic mass of Zn. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.671.89 moles Zn × (65.4 grams)) = 10.3 grams Zn
For this you need the atomic (molecular) mass of N2. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel..713 moles × (69.7 grams) = 49.7 grams Ga