Moles = Mass/Molar Mass.
Using this equation, we can take 25/(1.0 + 19) and find that it is equal to 1.25 moles.
Keep in mind that very few significant figures were used for this example (2), and that if accuracy is to be expected, as many as possible should be used.
2KClO3 --> 2KCl + 3O2For every 3 moles of oxygen gas produced, 2 moles of potassium chlorate are used.6 moles O2 * (2 moles KClO3 reacted / 3 moles O2 produced) = 4 moles KClO3
There are 3 moles of nitrogen in 3 moles of ammonium nitrate. Ammonium nitrate contains 2 nitrogen atoms in its chemical formula NH4NO3. Each mole of ammonium nitrate contains 2 moles of nitrogen atoms.
For every one mole of iron-III-chromate, there are three moles of chromate ions present. Therefore, in a sample containing 3.71 moles of iron-III-chromate, there would be 3.71 moles multiplied by 3, which is 11.13 moles of chromate ions.
N2 + 3H2 -----> 2NH3 so 3 moles of hydrogen produce 2 moles of ammonia. Therefore 12.0 moles of hydrogen will produce 8 moles of ammonia.
The most straightforward reaction for the formation of SO3 from SO2 is 2 SO2 + O2 => 2 SO3. If this is the actual reaction for the formation, 3 moles of SO3 are formed from 3 moles of SO2.
The molar mass of HF (hydrofluoric acid) is 20.01 g/mol. Therefore, 3 moles of HF would be equal to 60.03 grams.
The balanced equation for the reaction between HF and SiO2 is: 6 HF + SiO2 -> H2SiF6 + 2 H2O. Therefore, each mole of SiO2 reacts with 6 moles of HF. So, 12.5 mol of SiO2 will react with 12.5 mol x 6 = 75 mol of HF.
To calculate the amount of HF needed to react with 7.75 kg of UO2, you first need to determine the molar ratio between UO2 and HF from the balanced chemical equation. Then convert 7.75 kg of UO2 to moles using the molar mass of UO2 and apply the molar ratio to find the moles of HF required. Finally, convert the moles of HF to kilograms using the molar mass of HF.
To calculate the grams of SnF2 produced, you need to first determine the moles of HF using the molar mass of HF. Then use the mole ratio between HF and SnF2 from the balanced chemical equation to find the moles of SnF2 produced. Finally, convert the moles of SnF2 to grams using the molar mass of SnF2.
First, balance the chemical equation between Na2SiO3 and HF to determine the stoichiometry. Then, use the molar masses of Na2SiO3 and HF to convert the mass of HF to moles. Finally, use the stoichiometry to calculate the mass of Na2SiO3 that can react with 0.740 g of HF.
The gram molecular mass of HF is 20.01. Therefore, 0.589 mole has a mass of 11.79 grams and is sufficient to form 0.589 mole of sodium fluoride* when sodium is present in excess. The gram molecular mass of sodium fluoride is 41.99, so that 0.589 grams of it has a mass of 24.7 grams, to the justified number of significant digits. __________________________ The formula unit of both hydrogen and sodium fluorides contains a single fluorine atom.
An 0.010 M HF solution gives pH = 2.6, so 0.0022 molesare present in 0.22 L
60 g
The answer is 3 moles of Cu)NO3)2..
The answer is 3 moles.
When 3 moles Cu react 3 moles of copper nitrate are obtained.
Here is the solution,for 1mole NH3 or ammonia,N: 14.0067 g/mol x 1H: 1.00794 g/mol x 3So approximately it is--> 17.03052 g/mol)Now multiply this into 4.5 for 4.5 moles of ammonia, --> 4.5x17.03052 =76.64g