0
What else can I help you with?
How many moles of potassium chlorate must be used to produce 6 moles of oxygen gas?
2KClO3 --> 2KCl + 3O2For every 3 moles of oxygen gas produced, 2 moles of potassium chlorate are used.6 moles O2 * (2 moles KClO3 reacted / 3 moles O2 produced) = 4 moles KClO3
How many moles of nitrogen are there in 3 moles of ammonium nitrate?
There are 3 moles of nitrogen in 3 moles of ammonium nitrate. Ammonium nitrate contains 2 nitrogen atoms in its chemical formula NH4NO3. Each mole of ammonium nitrate contains 2 moles of nitrogen atoms.
How many moles of chromate ions are present in a sample that contains 3.71 moles of iron-III- chromate Fe2-CrO4-3. Dashes are parentheses.?
For every one mole of iron-III-chromate, there are three moles of chromate ions present. Therefore, in a sample containing 3.71 moles of iron-III-chromate, there would be 3.71 moles multiplied by 3, which is 11.13 moles of chromate ions.
How many moles of ammonia are produced from 12.0 moles of hydrogen?
N2 + 3H2 -----> 2NH3 so 3 moles of hydrogen produce 2 moles of ammonia. Therefore 12.0 moles of hydrogen will produce 8 moles of ammonia.
How many moles of sulfur trioxide are formed from 3 moles of sulfur dioxide?
The most straightforward reaction for the formation of SO3 from SO2 is 2 SO2 + O2 => 2 SO3. If this is the actual reaction for the formation, 3 moles of SO3 are formed from 3 moles of SO2.
How many grams 3 of HF?
The molar mass of HF (hydrofluoric acid) is 20.01 g/mol. Therefore, 3 moles of HF would be equal to 60.03 grams.
How many moles of HF will react completely with 12.5 mol of SiO2?
The balanced equation for the reaction between HF and SiO2 is: 6 HF + SiO2 -> H2SiF6 + 2 H2O. Therefore, each mole of SiO2 reacts with 6 moles of HF. So, 12.5 mol of SiO2 will react with 12.5 mol x 6 = 75 mol of HF.
How many kilograms of HF are needed to completely react with 7.75 kg or UO2?
To calculate the amount of HF needed to react with 7.75 kg of UO2, you first need to determine the molar ratio between UO2 and HF from the balanced chemical equation. Then convert 7.75 kg of UO2 to moles using the molar mass of UO2 and apply the molar ratio to find the moles of HF required. Finally, convert the moles of HF to kilograms using the molar mass of HF.
How many grams of SnF2 are produced from the reaction of 30-g of HF?
To calculate the grams of SnF2 produced, you need to first determine the moles of HF using the molar mass of HF. Then use the mole ratio between HF and SnF2 from the balanced chemical equation to find the moles of SnF2 produced. Finally, convert the moles of SnF2 to grams using the molar mass of SnF2.
How many formula units are in Mg of HF?
To determine the number of formula units in a given mass of HF (hydrofluoric acid), you first need to convert the mass of HF to moles using its molar mass (approximately 20.01 g/mol for HF). Then, multiply the number of moles by Avogadro's number (approximately (6.022 \times 10^{23}) formula units/mol). For example, if you have 1 g of HF, you would calculate the moles and then multiply by Avogadro's number to find the number of formula units.
How many kilograms of HF are needed to completely react with 5.01 kg of UO2?
To determine the amount of HF needed to react with UO2, we first need to look at the balanced chemical reaction between UO2 and HF. The reaction can be represented as: [ \text{UO}_2 + 4 \text{HF} \rightarrow \text{UF}_4 + 2 \text{H}_2\text{O} ] From the equation, 1 mole of UO2 reacts with 4 moles of HF. The molar mass of UO2 is approximately 270 g/mol. Therefore, 5.01 kg of UO2 is about 18.5 moles. Given that 4 moles of HF are required for each mole of UO2, we need 74 moles of HF, which corresponds to about 1,470 g or 1.47 kg of HF.
How many grams of Na2SiO3 can react with 0.740 g of HF?
First, balance the chemical equation between Na2SiO3 and HF to determine the stoichiometry. Then, use the molar masses of Na2SiO3 and HF to convert the mass of HF to moles. Finally, use the stoichiometry to calculate the mass of Na2SiO3 that can react with 0.740 g of HF.
How many moles of HF are needed to react with 0.220 mol of Na2SiO3?
The gram molecular mass of HF is 20.01. Therefore, 0.589 mole has a mass of 11.79 grams and is sufficient to form 0.589 mole of sodium fluoride* when sodium is present in excess. The gram molecular mass of sodium fluoride is 41.99, so that 0.589 grams of it has a mass of 24.7 grams, to the justified number of significant digits. __________________________ The formula unit of both hydrogen and sodium fluorides contains a single fluorine atom.
How many moles of HF Ka6.8104 must be present in 0.220dm3 to form a solution with a pH of 2.60?
An 0.010 M HF solution gives pH = 2.6, so 0.0022 molesare present in 0.22 L
How many grams are In 3 of HF?
60 g
How many grams are 4.5 moles of NH3?
Here is the solution,for 1mole NH3 or ammonia,N: 14.0067 g/mol x 1H: 1.00794 g/mol x 3So approximately it is--> 17.03052 g/mol)Now multiply this into 4.5 for 4.5 moles of ammonia, --> 4.5x17.03052 =76.64g
How many grams of HF are needed to make 0.50 l of a 0.750 m solution?
To prepare a 0.750 m (molal) solution, you need to know the mass of the solvent (in kg) because molality is defined as moles of solute per kg of solvent. For a 0.50 L solution, assuming the solvent is water with a density of approximately 1 g/mL, you have 0.50 kg of water. Thus, for 0.750 m, you need 0.750 moles of HF. The molar mass of HF is about 20.01 g/mol, so you would need 0.750 moles × 20.01 g/mol = 15.01 grams of HF.
