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First, balance the chemical equation between Na2SiO3 and HF to determine the stoichiometry. Then, use the molar masses of Na2SiO3 and HF to convert the mass of HF to moles. Finally, use the stoichiometry to calculate the mass of Na2SiO3 that can react with 0.740 g of HF.

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How many moles of HF are needed to react with 0.220 mol of Na2SiO3?

The gram molecular mass of HF is 20.01. Therefore, 0.589 mole has a mass of 11.79 grams and is sufficient to form 0.589 mole of sodium fluoride* when sodium is present in excess. The gram molecular mass of sodium fluoride is 41.99, so that 0.589 grams of it has a mass of 24.7 grams, to the justified number of significant digits. __________________________ The formula unit of both hydrogen and sodium fluorides contains a single fluorine atom.


How many grams of oxygen are needed to react with 23.9 grams of ammonia?

The balanced equation for the reaction between ammonia (NH3) and oxygen (O2) is 4NH3 + 5O2 → 4NO + 6H2O. To find the grams of oxygen needed to react with 23.9 grams of ammonia, you need to calculate the molar ratio between ammonia and oxygen using the balanced equation. Once you find the molar ratio, you can calculate the grams of oxygen required.


Given that zinc reacts with iodine in the fixed mass ratio of 1 gram of zinc to 3.88 grams of iodine how many grams of iodine are required to completely react with 4.2 grams of zinc?

For every 1 gram of zinc, 3.88 grams of iodine are required to react. So in this case, with 4.2 grams of zinc, the amount of iodine needed would be (4.2 grams zinc) * (3.88 grams iodine / 1 gram zinc) = 16.296 grams of iodine.


How many grams of Oxygen are required to react with 100 g Fe in this reaction?

The balanced chemical equation for the reaction is: 4Fe + 3O2 -> 2Fe2O3 From the equation, it can be seen that 3 moles of O2 are required to react with 4 moles of Fe. Therefore, to determine the grams of O2 required to react with 100 g Fe, you would need to use stoichiometry to find the answer.


How many grams of iron will be needed to react completely with an excess of oxygen to form 40 grams of iron3 oxide?

To determine the amount of iron needed to react with 40 grams of iron(III) oxide, you should use the stoichiometry of the reaction. Calculate the molar mass of iron(III) oxide (Fe2O3) and determine the molar ratio between iron and iron(III) oxide in the balanced chemical equation. From there, you can calculate the amount of iron needed to fully react with 40 grams of iron(III) oxide.

Related Questions

How many moles of HF are needed to react with 0.220 mol of Na2SiO3?

The gram molecular mass of HF is 20.01. Therefore, 0.589 mole has a mass of 11.79 grams and is sufficient to form 0.589 mole of sodium fluoride* when sodium is present in excess. The gram molecular mass of sodium fluoride is 41.99, so that 0.589 grams of it has a mass of 24.7 grams, to the justified number of significant digits. __________________________ The formula unit of both hydrogen and sodium fluorides contains a single fluorine atom.


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2