The balanced chemical equation for the reaction is:
4Fe + 3O2 -> 2Fe2O3
From the equation, it can be seen that 3 moles of O2 are required to react with 4 moles of Fe. Therefore, to determine the grams of O2 required to react with 100 g Fe, you would need to use stoichiometry to find the answer.
To determine the amount of gas needed to react with 348.5 grams of oxygen, you need to know the balanced chemical equation of the reaction. Then, use the stoichiometry of the reaction to calculate the amount of gas required based on the molar ratio between the gas and oxygen in the reaction.
The balanced equation for the reaction between ammonia (NH3) and oxygen (O2) is 4NH3 + 5O2 → 4NO + 6H2O. To find the grams of oxygen needed to react with 23.9 grams of ammonia, you need to calculate the molar ratio between ammonia and oxygen using the balanced equation. Once you find the molar ratio, you can calculate the grams of oxygen required.
To determine the grams of ZnS required to react with oxygen gas, we need to write a balanced chemical equation of the reaction. Then we can use stoichiometry to calculate the amount of ZnS needed. Given that the reaction involves ZnS and oxygen gas at STP (Standard Temperature and Pressure), we can use the ideal gas law to find the number of moles of oxygen, which will help us determine the amount of ZnS needed.
When the amount of oxygen is limited, carbon and oxygen react to form carbon monoxide. How many grams of CO can be formed from 35 grams of oxygen?
The balanced chemical equation for the reaction of ethanol with oxygen to form carbon dioxide and water is C2H5OH + 3O2 -> 2CO2 + 3H2O. From this equation, we can see that 3 moles of oxygen are needed to react with 1 mole of ethanol. Therefore, 2 moles of ethanol will require 6 moles of oxygen to react. To find the grams of oxygen, you can multiply the moles of oxygen by its molar mass (32 g/mol).
To determine the amount of gas needed to react with 348.5 grams of oxygen, you need to know the balanced chemical equation of the reaction. Then, use the stoichiometry of the reaction to calculate the amount of gas required based on the molar ratio between the gas and oxygen in the reaction.
The balanced equation for the reaction between ammonia (NH3) and oxygen (O2) is 4NH3 + 5O2 → 4NO + 6H2O. To find the grams of oxygen needed to react with 23.9 grams of ammonia, you need to calculate the molar ratio between ammonia and oxygen using the balanced equation. Once you find the molar ratio, you can calculate the grams of oxygen required.
Three atoms of oxygen are required to react with each two atoms of aluminum to form the most common product of reaction between oxygen and aluminum. Therefore, 0.75 mole of oxygen atoms will be required to react with 0.5 mole of aluminum atoms. The atomic weight of oxygen is 15.999; therefore, the mass will be (0.75)(15.999) = 12 grams of oxygen, to the maximum possibly justified number of significant digits.
The answer is 152 g oxygen.
To determine the grams of ZnS required to react with oxygen gas, we need to write a balanced chemical equation of the reaction. Then we can use stoichiometry to calculate the amount of ZnS needed. Given that the reaction involves ZnS and oxygen gas at STP (Standard Temperature and Pressure), we can use the ideal gas law to find the number of moles of oxygen, which will help us determine the amount of ZnS needed.
The balanced chemical equation for the reaction between aluminum and oxygen is 4Al + 3O2 → 2Al2O3. Using the stoichiometry of the equation, you would need 50 g of aluminum to react with 75 g of oxygen, since the molar ratio between Al and O2 is 4:3.
the equation of this reaction is C + O2 = CO2 (s) (g) (g) according to this reaction 1mol of Carbon react with same number of moles of Oxygen. and this combination gives 1mol of CO2 as result. so first we have to find the number of moles in the weight we are going to use. 12 grams of carbon contains 1mol so 6 grams of carbon contains ( 1/12 )*6 = 0.5mol 32 grams of Oxygen contains 1mol 16 grams of Oxygen contains ( 1/36 )*16 = 0.5mol as 1mol of C react with 1mol of O2,0.5mol of C react with 0.5mol of O2. this produces equal number of moles (0.5mol) of CO2.
When the amount of oxygen is limited, carbon and oxygen react to form carbon monoxide. How many grams of CO can be formed from 35 grams of oxygen?
The balanced chemical equation for the reaction of ethanol with oxygen to form carbon dioxide and water is C2H5OH + 3O2 -> 2CO2 + 3H2O. From this equation, we can see that 3 moles of oxygen are needed to react with 1 mole of ethanol. Therefore, 2 moles of ethanol will require 6 moles of oxygen to react. To find the grams of oxygen, you can multiply the moles of oxygen by its molar mass (32 g/mol).
Burning is a reaction with oxygen, an oxydation; americium can react with oxygen.
The balanced chemical equation for the reaction between iron and oxygen to produce Fe2O3 is 4Fe + 3O2 -> 2Fe2O3. From the equation, we see that 3 moles of oxygen react with 4 moles of iron to produce 2 moles of Fe2O3. Therefore, to find the grams of oxygen needed, we need to calculate the molar mass of Fe2O3 and then determine the number of grams needed using the mole ratio from the balanced equation.
To calculate the number of grams of oxygen needed to react with 6.78 grams of ammonia, we first write out the balanced chemical equation for the reaction between ammonia (NH3) and oxygen (O2) to form nitrogen monoxide (NO) and water (H2O). Then we use the stoichiometry of the equation to find the molar ratio between ammonia and oxygen. Finally, we convert the mass of ammonia to moles and then use the molar ratio to find the mass of oxygen needed.