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The gram molecular mass of HF is 20.01. Therefore, 0.589 mole has a mass of 11.79 grams and is sufficient to form 0.589 mole of sodium fluoride* when sodium is present in excess. The gram molecular mass of sodium fluoride is 41.99, so that 0.589 grams of it has a mass of 24.7 grams, to the justified number of significant digits.

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The formula unit of both hydrogen and sodium fluorides contains a single fluorine atom.

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11y ago
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11y ago

(0.500molHf x 1molNa2SiOx41.988gNaF)/(8moleHF)= 2.62gNaF x 2= 5.25gNaF

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8y ago

6 moles of HF react with 1 mole of SiO2.

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10y ago

2.40 mol HF

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7y ago

1,6 moles of HF are needed.

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7y ago

0.44 moles HF required.

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11y ago

0,61 g

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Q: How many moles of HF are needed to react with 0.220 mol of Na2SiO3?
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