2KClO3 --> 2KCl + 3O2
For every 3 moles of oxygen gas produced, 2 moles of potassium chlorate are used.
6 moles O2 * (2 moles KClO3 reacted / 3 moles O2 produced) = 4 moles KClO3
2KClO3 + heat -> 2KCl + 3O2 14 moles KClO3 (3 mole O2/2 mole KClO3) = 21 moles oxygen made This is a common industrial method of producing oxygen.
The molar volume of gas at STP is 22.4 L/mol. So, 200 L of oxygen is equivalent to 200/22.4 = 8.93 moles. The balanced chemical equation for the decomposition of ammonium chlorate is 2NH4ClO3 -> 2N2 + Cl2 + 3O2. Therefore, to produce 3 moles of oxygen, we need 2 moles of ammonium chlorate. 8.93 moles of oxygen would require 2/3 * 8.93 = 5.95 moles of ammonium chlorate. The molar mass of NH4ClO3 is 101.5 g/mol, so the mass of ammonium chlorate needed would be 5.95 * 101.5 = 604.5 grams.
In 2 moles of potassium dichromate, there are 16 moles of oxygen atoms (from the two oxygen atoms in each formula unit). The molar mass of oxygen is 16 g/mol, so in 2 moles of potassium dichromate, there are 32 grams of oxygen.
2 to 3, because of the balanced equation:2 KClO3 --> 2 KCl + 3 O2
The balanced equation for this reaction is: 2K3PO4 + 3Al(NO3)3 -> 6KNO3 + AlPO4. This indicates that 2 moles of potassium phosphate react with 2 moles of aluminum nitrate to produce 6 moles of potassium nitrate.
The chemical reactin is:2 KClO3 = 2 KCl + 3 O24 moles of potassium chlorate produce 6 moles oxygen.
Four moles of potassium chlorate are needed.
12 moles KClO3 (3 moles O/1 mole KClO3) = 36 moles of oxygen.
For the decomposition of potassium chlorate, the molar ratio between potassium chlorate (KClO3) and oxygen (O2) is 2:3. Therefore, to produce 15 moles of oxygen, 10 moles of potassium chlorate are needed. (15 moles O2) x (2 moles KClO3 / 3 moles O2) = 10 moles KClO3.
1 mole of potassium chlorate produces 3 moles of oxygen gas when heated, or 1 mole of potassium chlorate produces 1.344 L of oxygen gas at NTP. To produce 2.24 L of oxygen gas, you would need about 1.67 moles of potassium chlorate.
We need 3 moles of potassium perchlorate.
The answer is 1 mole potassium chlorate.
For every mole of potassium chlorate that decomposes, three moles of oxygen are produced. Therefore, if 7.5 moles of potassium chlorate decompose, 22.5 moles of oxygen would be produced (7.5 moles x 3).
2KClO3==>2KCl+3O2 is the equation. so you need 4 moles of KClO3.
2KClO3 + heat -> 2KCl + 3O2 14 moles KClO3 (3 mole O2/2 mole KClO3) = 21 moles oxygen made This is a common industrial method of producing oxygen.
To calculate the amount of oxygen gas produced from potassium chlorate, use the balanced chemical equation for the decomposition of potassium chlorate: 2KClO3 -> 2KCl + 3O2. From the equation, every 2 moles of KClO3 produce 3 moles of O2. First, convert the given mass of KClO3 to moles, then use the mole ratio from the balanced equation to find the moles of O2 produced. Finally, convert moles of O2 to grams using its molar mass (32 g/mol).
To find the moles of cesium chlorate needed to produce 2.7 moles of oxygen gas, use the balanced chemical equation for the decomposition of cesium chlorate: 2CsClO3 -> 2CsCl + 3O2 From the equation, it shows that 2 moles of cesium chlorate produce 3 moles of oxygen gas. Therefore, you will need (2/3) * 2.7 = 1.8 moles of cesium chlorate to produce 2.7 moles of oxygen gas.