2 to 3, because of the balanced equation:
2 KClO3 --> 2 KCl + 3 O2
75.0 g
A balanced equation for the reaction is 2 KClO3 -> 2 KCl + 3 O2. Therefore, each mole of potassium chlorate produces 3/2 moles of oxygen, and 1.2 moles of potassium chlorate produces (3/2)1.2 or 1.8 moles of oxygen.
10 mol KClO3 * 3mol O/ 1 mol KClO3= 30
A mole of any element, compound, etc is defined by Avogadro's Constant. There are always 6.02214179×1023 atoms in one mole of that substance.
The formula shows that there are (exactly) 4 oxygen atoms in each mole or formula unit. Therefore, the answer is 4 X 1.10 = 4.40 moles of oxygen atoms.
There is less O in 100 g of [KCl+KClO3]-'mixture' than in 100 g pure [KClO3] because there is more [K] and [Cl] in the first.
224 grams of Oxygen will be in 2 moles of Potassium dichromate.
because it depends on the number of the moles that you will get, so the more moles number that you have for the chlorate the more oxygen that you will get.
Since both chloride anions and nitrate anions have a charge of -1, there will be the same number of moles of silver chloride produced as the moles of silver nitrate reacted. (Since both silver nitrate and silver chloride are ionic compounds, it would be preferable to call their "moles" "formula units" instead.)
Well to find how many grams are in moles you would eventually multiply the mole by the molar mass. The molar mass of aluminum oxide would be 101.96 ( you would find that by multiplying the atomic mass of al by 2 and o by 3 and adding them together). But the molar mass of Oxygen is just about 48 (rounded to 16 instead of 15.9994)5.75 moles of Al2O3 X 48 g oxygen/1 mole of Al2O3=276 g oxygen in 5.75 mole Al2O3
2 KClO3 ----> 2KCl + 3O2 So 2 moles of Potassium Chlorate produces 3 moles of oxygen molecules or 6 moles of oxygen atoms. 3 moles of Potassium chlorate would thus produce 4.5 moles of oxygen molecules or 9 moles of oxygen atoms.
First you need to find the balanced reaction:2S + 3O2 --> 2SO3So using the balanced reaction we see that for every 3 moles of oxygen consumed, 2 moles of sulfur trioxide are produced:1.2 moles O2 consumed * (2 moles SO3/3 moles O2) = 0.8 mole of SO3 produced
4.8/16 moles of oxygen atoms converts to 1.6/16 moles of ozone molecules.
If you mean atoms then two, if molecules one.
Equation: 2KClO3 + Cl2 ---> 2KCl + 3O2 + Cl2 1. Solve for the number of moles of KClO3 in 36.3 g. (.2962 molKClO3) 2. Multiply that value by (3/2), from the equation's coefficients. (.4447 molO2) Note: A BCA table could also be used. 3. Solve for the mass of .4447 molO2. 14.2 grams of oxygen would be produced.
The nunber of moles of oxygen is 2,5.
Absolutely none, as there is no oxygen in hydrogen cyanide. Its formula is HCN--one atom each of hydrogen, carbon and nitrogen.
Alls you do to find a molar mass is add up all of the atomic masses. Potassium=39.09 Chlorine= 35.453 Oxygen(3)=15.999. So KClO3 would equal 271.65g to a mol? Then I think to find the number of atoms of each you would take the atomic mass * avacodo's number so it would be for example chlorine. 1gCl(35.453/1)(6.022*10^23/1) However I might be wrong on that part.
Here is the BALANCED reaction eq'n. 2H2(g) + O2(g) = 2H2O(l) The prefix number are the Molar Ratios 2:1::2 So oxygen is ONE(1) mole Hence hydrogen is TWO(2) moles It produces TWO(2) moles of water.
The formula means, among other things, that there are 7 atoms of oxygen in each mole of the compound. Therefore, in 4.00 moles of the compound, there are 28.00 moles of oxygen atoms. Elemental oxygen usually is diatomic, so that there would be the equivalent of 14 moles of diatomic elemental oxygen.
Each mole of PbO2 contains 2 moles of oxygen (O). Thus there would be 5.43x2 = 10.86 moles O.Each mole of water (H2O) contains 1 mole of O, so from 10.86 moles of O you could get 10.86 moles of H2O.
Balanced Formula:2Mg + O2 --> 2MgOMole ratio:2 : 1 : 2Givens:.486 g oxygen.738 g magnesium24.3 g = atomic mass of magnesium16.0 g = atomic mass of oxygen40.3 g = molecular mass of magnesium oxideFind the amount (in moles) of Magnesium oxide that oneelement will make:(.486 g O) / (16.0 g O) × (2 moles MgO)= .0608 moles MgO(.783 g Mg) / (24.3 g Mg) = .0322 moles MgOThere is less MgO produced with magnesium than oxygen; therefore, magnesium is the limiting reactant and the oxygen is the excess reactant. The magnesium determines how much Magnesium oxide is produced. It would be good to get .0608 moles of MgO, but there isn't enough magnesium. So the amount of MgO produced will be determined on the amount of Magnesium.Convert moles of MgO produced with the amount of oxygen to grams:.0322 mol MgO (40.3 g) = 1.30 grams of MgO produced--------------------------------------------------------------------------------------------------------You will need 3 moles of oxygen if you start with six moles of magnesium. This will allow you to produce 6 moles of magnesium oxide.Source: (e2020)