224 grams of Oxygen will be in 2 moles of Potassium dichromate.
This is a mixture of 2K+ and Cr2O72- ions in strong sulfuric acid, made from potassium chromate.2CrO4- + 2H+ ----> Cr2O72- + H2Ochromate-yellow -> dichromate-orangeNote:Potassium ions do NOT react, they are tribune-ions
- Dry potassium dichromate (standard certified quality, from NIST - SRM 136f or from another supplier), using a platinum dish or crucible. - Follow the mode of drying (generally 1 hour at 120 0C in an oven) indicated by the supplier. Place the potassium dichromate in an exsicator. - Prepare a volume of demineralized or distilled water - Weight 73,546 25 g potassium dichromate in a platinum dish calcined to a constant weight; apply a correction for the flotability of the air and the purity of the dichromate. Use a metrologically checked microbalance. - Place carefully the potassium dichromate in a 1 000 mL volumetric flask, dried and washed - Add about 900 mL water - Place the volumetric flask in a thermostat at 20 0C; after approx. 30 min add the water exactly to the mark. - Stirr the content of the volumetric flask; place a clear label on the flask (concentration, material, date of preparation, operator's name).
The formula for potassium hydrogen sulfide is KHS. Another name for this inorganic compound is potassium hydrosulfide. Its molar mass is 72.17 grams per mole, and it is soluble in water.
This is more of a math question that requires a bit of knowledge of chemistry. So it helps to know the steps of this answer mathematically. Additionally it's worth noting that there are a number of ways to answer this question. The method I provide may take an extra step, but it allows for a better understanding of the process.First we need to know some basic information about potassium permanganate, KMnO4. This basic information can be found on a periodic table, like the one in the link below. The first step is finding the weight of oxygen in one mole of potassium permanganate as a percent. For this you need to know the atomic weights of the elements involved.K: 39.1 gramsMn: 54.9 gramsO: 16.0 grams × 4 atoms = 64.0 gramsKMnO4: 39.1 + 54.9 + 64.0 = 158.0 grams/molSo now we know the weight of one mole of potassium permanganate (158.0 grams). Because we also know the weight of oxygen, we can find the percent of oxygen in the compound by mass.64.0 grams O ÷ 158.0 grams KMnO4 = 0.405 = 40.5%In one mole of potassium permanganate, 64.0 grams of it is oxygen, meaning 40.5% of it is oxygen. Because of the Law of Definite Proportions, we know that in any amount of potassium permanganate, 40.5% of it is oxygen.Then you can set up an equation.40.5% of (some amount of KMnO4) = 27.5 grams oxygenLet's set the amount of KMnO4 as the variable "x".0.405x = 27.5x = 67.9 grams KMnO4
The reaction between potassium dichromate and sodium thiosulfate is a redox reaction in which potassium dichromate is reduced to chromium(III) ions and sodium thiosulfate is oxidized to form sulfur. The overall reaction can be summarized by the following equation: K2Cr2O7 + 3 Na2S2O3 → Cr2(SO4)3 + 3 Na2SO4 + 2 K2SO4
In potassium dichromate (K2Cr2O7), there are 7 oxygen atoms per molecule. Therefore, two moles of K2Cr2O7 would contain 14 moles of oxygen atoms. Each mole of oxygen atoms has a molar mass of approximately 16 grams, so there would be 224 grams of oxygen in two moles of potassium dichromate.
The answer is 224,24 g oxygen.
In one mole of potassium dichromate, there seven moles of oxygen. This means in two moles of K2Cr2O7, there are 14 moles of O, or 7 Moles of O2, which equals 224 grams.
This is a mixture of 2K+ and Cr2O72- ions in strong sulfuric acid, made from potassium chromate.2CrO4- + 2H+ ----> Cr2O72- + H2Ochromate-yellow -> dichromate-orangeNote:Potassium ions do NOT react, they are tribune-ions
There are 6 moles of oxygen atoms in 2 moles of potassium dichromate (K2Cr2O7). Each mole of K2Cr2O7 contains 7 oxygen atoms, so 2 moles would contain 14 oxygen atoms. The molar mass of oxygen is 16 g/mol, so there would be 224 grams of oxygen in 2 moles of K2Cr2O7.
potassium dichromate- K2Cr2O7 12.5 grams K2Cr2O7 *(1 mol K2Cr2O7/294 grams K2Cr2O7)= .0425 mols K2Cr2O7 There's two mols of K (potassium) for every 1 mol of K2Cr2O7 (Potassium Dichromate) so you multiply the K2Cr2O7 by two to get mols of K .0425 mols K2Cr2O7*(2 mols K/1 mol K2Cr2O7)=.085 mols K Multiply by the molar mass of K to get grams .85 mols K*(39 grams/1 mol K)= 3.32 grams potassium
The answer is 224,141 grams oxygen.
In potassium dichromate (K2Cr2O7), the molar mass is 294.18 g/mol. Therefore, 2 moles of K2Cr2O7 will contain 2 x 294.18 = 588.36 grams of the compound. Since there are 7 oxygen atoms in each molecule of K2Cr2O7, the total mass of oxygen in 2 moles will be 7 x 16 (molar mass of oxygen) x 2 = 224 grams.
To calculate the amount of potassium chlorate needed to produce 112.5g of oxygen, you first need to determine the molar ratio between potassium chlorate and oxygen. Then, use this ratio to convert the grams of oxygen to grams of potassium chlorate using the molar masses of each compound.
The molar mass of potassium chlorate (KClO3) is 122.55 g/mol. This means that 122.55 grams of potassium chlorate yield 3 moles of oxygen gas. To calculate the amount of potassium chlorate that decomposes to yield 30 grams of oxygen, you can set up a simple ratio using the molar masses.
The reaction between potassium chlorate and oxygen gas generates potassium chloride and oxygen gas. Therefore, the amount of potassium chlorate produced from the reaction is equal to the amount of potassium chlorate that was used, which is 500 grams.
To determine the grams of potassium chloride formed, you first need to calculate the moles of oxygen produced by the decomposition of potassium chlorate. Then, use the stoichiometry of the balanced chemical equation to convert moles of oxygen to moles of potassium chloride. Finally, from the molar mass of potassium chloride, you can calculate the grams formed.