The answer is 224,141 grams oxygen.
In 2 moles of potassium dichromate, there are 16 moles of oxygen atoms (from the two oxygen atoms in each formula unit). The molar mass of oxygen is 16 g/mol, so in 2 moles of potassium dichromate, there are 32 grams of oxygen.
In potassium dichromate (K2Cr2O7), there are 7 oxygen atoms per molecule. Therefore, two moles of K2Cr2O7 would contain 14 moles of oxygen atoms. Each mole of oxygen atoms has a molar mass of approximately 16 grams, so there would be 224 grams of oxygen in two moles of potassium dichromate.
In one mole of potassium dichromate, there seven moles of oxygen. This means in two moles of K2Cr2O7, there are 14 moles of O, or 7 Moles of O2, which equals 224 grams.
The answer is 224,24 g oxygen.
There are 6 moles of oxygen atoms in 2 moles of potassium dichromate (K2Cr2O7). Each mole of K2Cr2O7 contains 7 oxygen atoms, so 2 moles would contain 14 oxygen atoms. The molar mass of oxygen is 16 g/mol, so there would be 224 grams of oxygen in 2 moles of K2Cr2O7.
In potassium dichromate (K2Cr2O7), the molar mass is 294.18 g/mol. Therefore, 2 moles of K2Cr2O7 will contain 2 x 294.18 = 588.36 grams of the compound. Since there are 7 oxygen atoms in each molecule of K2Cr2O7, the total mass of oxygen in 2 moles will be 7 x 16 (molar mass of oxygen) x 2 = 224 grams.
16 grams of oxygen how many moles is 0,5 moles.
320 grams of oxygen is the equivalent of 10 moles.
In one mole of sodium dichromate (Na2Cr2O7), there are 7 oxygen atoms. To find the number of moles in 7.00 g, you need to divide 7.00 g by the molar mass of Na2Cr2O7 to find the number of moles of Na2Cr2O7. Then, multiply the number of moles by 7 to find the number of oxygen atoms in 7.00 g of sodium dichromate.
12.8 grams oxygen (1 mole O/16.0 grams) = 0.800 moles of oxygen
0,667 g oxygen equal 0,021 moles.
The molar mass of oxygen is approximately 16 grams/mol. Therefore, the mass of 3 moles of oxygen would be 3 moles * 16 grams/mole = 48 grams.