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What is the number of moles of sulfur in sulfur trioxide?
To find the number of moles of sulfur in sulfur trioxide (SO3), you can use the molar ratio from the chemical formula. In SO3, there is 1 mole of sulfur for every 1 mole of SO3. Therefore, the number of moles of sulfur in 1 mole of SO3 is also 1 mole.
How many moles of each atom are in 2.00moles of sulfur trioxide?
How_many_moles_of_each_atom_are_in_2.00moles_of_sulphur_trioxide
6.11 mole of sulfur trioxide have a mass of how many grams?
Sulfur Trioxide has a molar mass of 80.0632 grams per mole. Therefore, 6.11 moles of Sulfur Trioxide is 489.186152 grams (without significant figures). With significant figures that would be 489 grams.
How many ATOMS of sulfur are present in 9.96 grams of sulfur trioxide?
The formula for sulfur trioxide is SO3. The molecular weight is 80.06. The atomic weight of sulfur is 32.06. Therefore, the fraction by weight of sulfur in sulfur trioxide is 32.06/80.06 is 0.4004, to the justified number of significant digits, so that 9.96 grams of sulfur trioxide contains 3.988 grams of sulfur. The number of atoms present in 3.988 grams of sulfur therefore is Avogadro's Number X (3.988/80.06) or 3.000 X 1021 atoms, to the justified number of significant digits. (Note: A depressed final digit in a decimal means that the digit may not be significant.)
How many molecules does four moles of sulfur dioxide SO2 consist of?
Four moles of sulfur dioxide would consist of how many molecules?
How many moles of sulfur trioxide will be produced when two moles of sulfur combine with three moles of oxygen?
One mole of sulfur reacts with 1.5 moles of oxygen to produce one mole of sulfur trioxide. So, with two moles of sulfur and three moles of oxygen, the limiting reactant is sulfur. Therefore, two moles of sulfur will produce two moles of sulfur trioxide.
What is the number of moles of sulfur in sulfur trioxide?
To find the number of moles of sulfur in sulfur trioxide (SO3), you can use the molar ratio from the chemical formula. In SO3, there is 1 mole of sulfur for every 1 mole of SO3. Therefore, the number of moles of sulfur in 1 mole of SO3 is also 1 mole.
How many moles of each atom are in 2.00moles of sulfur trioxide?
How_many_moles_of_each_atom_are_in_2.00moles_of_sulphur_trioxide
6.11 mole of sulfur trioxide have a mass of how many grams?
Sulfur Trioxide has a molar mass of 80.0632 grams per mole. Therefore, 6.11 moles of Sulfur Trioxide is 489.186152 grams (without significant figures). With significant figures that would be 489 grams.
How many ATOMS of sulfur are present in 9.96 grams of sulfur trioxide?
The formula for sulfur trioxide is SO3. The molecular weight is 80.06. The atomic weight of sulfur is 32.06. Therefore, the fraction by weight of sulfur in sulfur trioxide is 32.06/80.06 is 0.4004, to the justified number of significant digits, so that 9.96 grams of sulfur trioxide contains 3.988 grams of sulfur. The number of atoms present in 3.988 grams of sulfur therefore is Avogadro's Number X (3.988/80.06) or 3.000 X 1021 atoms, to the justified number of significant digits. (Note: A depressed final digit in a decimal means that the digit may not be significant.)
What is the limiting reactant when 3.1 moles of SO2 react with 2.7 moles of O2 to produce sulfur trioxide?
The limiting reactant is oxygen.
How many molecules does four moles of sulfur dioxide SO2 consist of?
Four moles of sulfur dioxide would consist of how many molecules?
How many grams of oxygen will be required to produce 25 moles of sulfur dioxide how many grams of oxygen will be required to produce 25 moles of sulfur dioxide?
800 g oxygen are needed.
How many molecules of sulfur dioxide are present in 1.60 moles of sulfur dioxide?
There are approximately 9.65 x 10^23 molecules of sulfur dioxide in 1.60 moles of sulfur dioxide. This is because one mole of any substance contains Avogadro's number of molecules, which is 6.022 x 10^23.
How many molecules of sulfur dioxide are present in 72 g of the substance?
To determine the number of molecules of sulfur dioxide in 72 g of the substance, we first need to calculate the number of moles of sulfur dioxide present. The molar mass of sulfur dioxide (SO2) is approximately 64 g/mol. Therefore, 72 g of sulfur dioxide is equal to 72 g / 64 g/mol = 1.125 moles. Next, we use Avogadro's number, which is 6.022 x 10^23 molecules/mol, to convert moles to molecules. Therefore, there are approximately 6.78 x 10^23 molecules of sulfur dioxide in 72 g of the substance.
25 moles of sulfur dioxide how many grams of oxygen does it contain?
25 moles of sulfur dioxide contain 600 grams of oxygen. Each mole of SO2 contains 2 moles of oxygen, and the molar mass of O is 16 g/mol. So, 25 moles x 2 moles = 50 moles of O, which is 50 moles x 16 g/mol = 800 g of O.
How many moles of CS2 will be generated if 8.0 moles of coke react with a surplus of sulfur dioxide?
The balanced chemical equation shows that 1 mole of coke reacts with 1 mole of sulfur dioxide to produce 1 mole of carbon disulfide. Therefore, if 8.0 moles of coke react, then 8.0 moles of carbon disulfide will be generated.
