The formula for sulfur trioxide is SO3. The molecular weight is 80.06. The atomic weight of sulfur is 32.06. Therefore, the fraction by weight of sulfur in sulfur trioxide is 32.06/80.06 is 0.4004, to the justified number of significant digits, so that 9.96 grams of sulfur trioxide contains 3.988 grams of sulfur. The number of atoms present in 3.988 grams of sulfur therefore is Avogadro's Number X (3.988/80.06) or 3.000 X 1021 atoms, to the justified number of significant digits.
(Note: A depressed final digit in a decimal means that the digit may not be significant.)
The molar mass of sulfur trioxide (SO3) is approximately 80.06 grams per mole.
Sulfur Trioxide has a molar mass of 80.0632 grams per mole. Therefore, 6.11 moles of Sulfur Trioxide is 489.186152 grams (without significant figures). With significant figures that would be 489 grams.
To calculate the number of sulfur atoms in 3 grams of sulfur, you first need to convert the mass (3 grams) to moles using the molar mass of sulfur, which is approximately 32.06 g/mol. Then, use Avogadro's constant (6.022 x 10^23) to find the number of atoms in that number of moles.
no of atoms = weight of the given substance/ atomic mass of substance according to the question:- no of atoms = 3/32 answer
To find the number of atoms in 72.0 g of sulfur, you first need to convert grams to moles. The atomic mass of sulfur is 32.06 g/mol. Then, you use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. So, 72.0 g of sulfur would contain 6.022 x 10^23 atoms.
2.408 x 10^24 atoms.
The molar mass of sulfur trioxide (SO3) is approximately 80.06 grams per mole.
The molar mass of sulfur trioxide (SO3) is approximately 80.07 grams per mole. This means that a single sulfur trioxide molecule has a mass of about 80.07 atomic mass units.
Sulfur Trioxide has a molar mass of 80.0632 grams per mole. Therefore, 6.11 moles of Sulfur Trioxide is 489.186152 grams (without significant figures). With significant figures that would be 489 grams.
3,09x10e24 atoms of sulfur in grams is equal to 164,65 g.
The atomic weight of sulfur is about 32.066. Therefore, 155 grams of sulfur contains 155/32.066 or about 4.83 gram atomic masses of sulfur to the justified number of significant digits. Each such gram atomic mass contains Avogadro's number of atoms, for a total of 4.83 X 6.022 X 1023 or 2.91 X 1024 atoms.
To determine the amount of sulfur present in 27.5 grams of carbon disulfide, we need to consider the molar mass of the compound. The molar mass of carbon disulfide (CS2) is 76.142 g/mol. From the chemical formula, one molecule of CS2 contains 2 sulfur atoms. As there are 32.065 grams of sulfur in each mole of CS2, you would calculate the grams of sulfur in 27.5 grams of CS2 using stoichiometry.
The molar mass of sulfur is approximately 32 grams per mole. Therefore, 100 grams of sulfur would contain approximately 3 moles of sulfur atoms (100 grams / 32 grams/mole). To find the number of atoms, you would then multiply the number of moles by Avogadro's number (6.022 x 10^23 atoms/mole) to get the total number of sulfur atoms in 100 grams.
To find the number of atoms in 6.02 grams of sulfur, you first need to determine the number of moles of sulfur in 6.02 grams using the molar mass of sulfur. Then, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles of sulfur to atoms.
The molar mass of sulfur is approximately 32.06 grams/mol. Therefore, 1 mol of sulfur atoms will have a mass of 32.06 grams.
Just about 6.022 X 1023 atoms of sulfur. Sulfur is 32.07 grams per mole.
To determine the number of grams atoms of sulfur in a given mass of sulfur (g), you need to calculate the number of moles of sulfur first. Then, you can use Avogadro's number to convert moles to atoms. Finally, multiply the number of moles by Avogadro's number to find the number of atoms.