no of atoms = weight of the given substance/ Atomic Mass of substance
according to the question:-
no of atoms = 3/32 answer
1.87810*10^22 Sulfur Atoms.
The number of sulfur atoms in 27.1 g of molecular sulfur are: 27.1 g S8 x (1 mol S8/32.066 g S8) x (6.022 x 10^23 atoms/1 mole) = 5.09 x 10^23
32 g S * (1 mole S/32 g S) * (6.022*1023 atoms/1 mole S) = 6.022*1023 atomsThere are 6.022*1023 atoms in 32 grams of sulfur.
72.0 grams sulfur (1 mole S/32.07 grams)(6.022 X 10^23/1 mole S) = 1.35 X 10^24 atoms of sulfur
2(6.02*10 23) atoms
5 g of sulfur contain 0,94.10e23 atoms.
1.87810*10^22 Sulfur Atoms.
Just about 6.022 X 1023 atoms of sulfur. Sulfur is 32.07 grams per mole.
Just about 6.022 X 1023 atoms of sulfur. Sulfur is 32.07 grams per mole.
Just about 6.022 X 1023 atoms of sulfur. Sulfur is 32.07 grams per mole.
2(6.02 x 10^23) atoms
32g of Sulfur is a Mole of Sulfur and therefore contains Avogadro's number of atoms of Sulfur. Avogadro's number is 6.023 × 10 to the 23.
3,09x10e24 atoms of sulfur in grams is equal to 164,65 g.
8 g sulfur have 1,5027176187149.1023 atoms.
The number of sulfur atoms in 27.1 g of molecular sulfur are: 27.1 g S8 x (1 mol S8/32.066 g S8) x (6.022 x 10^23 atoms/1 mole) = 5.09 x 10^23
Hydrogen sulphide H2S(g)
32 g S * (1 mole S/32 g S) * (6.022*1023 atoms/1 mole S) = 6.022*1023 atomsThere are 6.022*1023 atoms in 32 grams of sulfur.