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In order to compare the number of atoms, one needs to first convert the masses into moles:
3 g Fe x 1 mole/55.8 g = 0.054 moles Fe
2 g S x 1 mole/32 g = 0.063 moles S
Therefore, 2 g of sulfur contains more atoms than does 3 g of Fe. This is because 1 mole of ANY element contains 602x10^23 atoms, so the more moles you have, the more atoms you have.
What else can I help you with?
How many grams atoms are in 100 of sulfur?
The molar mass of sulfur is approximately 32 grams per mole. Therefore, 100 grams of sulfur would contain approximately 3 moles of sulfur atoms (100 grams / 32 grams/mole). To find the number of atoms, you would then multiply the number of moles by Avogadro's number (6.022 x 10^23 atoms/mole) to get the total number of sulfur atoms in 100 grams.
How many grams atoms of sulfur are there in g of sulfur?
To determine the number of grams atoms of sulfur in a given mass of sulfur (g), you need to calculate the number of moles of sulfur first. Then, you can use Avogadro's number to convert moles to atoms. Finally, multiply the number of moles by Avogadro's number to find the number of atoms.
How many atoms are 6.02 grams of sulfur?
To find the number of atoms in 6.02 grams of sulfur, you first need to determine the number of moles of sulfur in 6.02 grams using the molar mass of sulfur. Then, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles of sulfur to atoms.
How many atoms are in 25.1 grams in sulfur?
To find the number of atoms in 25.1 grams of sulfur, you first need to calculate the number of moles using the molar mass of sulfur (32.06 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. So, number of atoms in 25.1 grams of sulfur would be: ( \dfrac{25.1 , \text{g}}{32.06 , \text{g/mol}} \times 6.022 \times 10^{23} , \text{atoms/mol})
How many atoms does thirty two grams of sulfur contain?
Thirty two grams of sulfur contains approximately 1.0 x 10^23 sulfur atoms. This is calculated by converting the mass to moles and then using Avogadro's number to determine the number of atoms in that many moles.
How many grams atoms are in 100 of sulfur?
The molar mass of sulfur is approximately 32 grams per mole. Therefore, 100 grams of sulfur would contain approximately 3 moles of sulfur atoms (100 grams / 32 grams/mole). To find the number of atoms, you would then multiply the number of moles by Avogadro's number (6.022 x 10^23 atoms/mole) to get the total number of sulfur atoms in 100 grams.
How many grams atoms of sulfur are there in g of sulfur?
To determine the number of grams atoms of sulfur in a given mass of sulfur (g), you need to calculate the number of moles of sulfur first. Then, you can use Avogadro's number to convert moles to atoms. Finally, multiply the number of moles by Avogadro's number to find the number of atoms.
How many atoms are 6.02 grams of sulfur?
To find the number of atoms in 6.02 grams of sulfur, you first need to determine the number of moles of sulfur in 6.02 grams using the molar mass of sulfur. Then, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles of sulfur to atoms.
How many sulfur atoms are in 3 grams of sulfur?
To calculate the number of sulfur atoms in 3 grams of sulfur, you first need to convert the mass (3 grams) to moles using the molar mass of sulfur, which is approximately 32.06 g/mol. Then, use Avogadro's constant (6.022 x 10^23) to find the number of atoms in that number of moles.
How many atoms are in 25.1 grams in sulfur?
To find the number of atoms in 25.1 grams of sulfur, you first need to calculate the number of moles using the molar mass of sulfur (32.06 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. So, number of atoms in 25.1 grams of sulfur would be: ( \dfrac{25.1 , \text{g}}{32.06 , \text{g/mol}} \times 6.022 \times 10^{23} , \text{atoms/mol})
How many atoms does thirty two grams of sulfur contain?
Thirty two grams of sulfur contains approximately 1.0 x 10^23 sulfur atoms. This is calculated by converting the mass to moles and then using Avogadro's number to determine the number of atoms in that many moles.
How many ATOMS of sulfur are present in 9.96 grams of sulfur trioxide?
The formula for sulfur trioxide is SO3. The molecular weight is 80.06. The atomic weight of sulfur is 32.06. Therefore, the fraction by weight of sulfur in sulfur trioxide is 32.06/80.06 is 0.4004, to the justified number of significant digits, so that 9.96 grams of sulfur trioxide contains 3.988 grams of sulfur. The number of atoms present in 3.988 grams of sulfur therefore is Avogadro's Number X (3.988/80.06) or 3.000 X 1021 atoms, to the justified number of significant digits. (Note: A depressed final digit in a decimal means that the digit may not be significant.)
How many atoms of sulfer are present in 155 grams of sulfer?
The atomic weight of sulfur is about 32.066. Therefore, 155 grams of sulfur contains 155/32.066 or about 4.83 gram atomic masses of sulfur to the justified number of significant digits. Each such gram atomic mass contains Avogadro's number of atoms, for a total of 4.83 X 6.022 X 1023 or 2.91 X 1024 atoms.
What is the of 3.09x10 24 atoms of sulfur in grams?
3,09x10e24 atoms of sulfur in grams is equal to 164,65 g.
How many atoms are in 64 grams sulfur?
To find the number of atoms in 64 grams of sulfur, you would first calculate the number of moles by dividing the given mass by the molar mass of sulfur. The molar mass of sulfur is approximately 32.06 g/mol. Then, you can use Avogadro's number (6.022 x 10^23) to convert moles to atoms.
What is the mass of x atoms of sulfur?
208
How many atoms are there in 128.4 grams of sulfur?
To calculate the number of atoms in 128.4 grams of sulfur, you first need to determine the number of moles of sulfur using its molar mass (32.06 g/mol). Then, you can use Avogadro's number (6.022 x 10^23) to calculate the number of sulfur atoms in that many moles.
