0
What else can I help you with?
How many moles OF s are present 7.71g of s?
To determine the number of moles of sulfur (S) present in 7.71g of S, you should first find the molar mass of sulfur, use it to convert the grams of sulfur to moles. Sulfur has a molar mass of approximately 32.06 g/mol, so the number of moles of S present in 7.71g is 7.71g / 32.06 g/mol = 0.24 moles of S.
How many atoms of sulfer are present in 155 grams of sulfer?
The atomic weight of sulfur is about 32.066. Therefore, 155 grams of sulfur contains 155/32.066 or about 4.83 gram atomic masses of sulfur to the justified number of significant digits. Each such gram atomic mass contains Avogadro's number of atoms, for a total of 4.83 X 6.022 X 1023 or 2.91 X 1024 atoms.
What is the weight of one mole of sulfur?
The molecular weight of 1 mole of sulfur is 32 amu or grams.
How many moles of sulfur are in 53.7 grams of sulfur?
To determine the number of moles of sulfur in 53.7 grams, you first need to calculate the molar mass of sulfur, which is approximately 32.06 g/mol. Then, divide the given mass by the molar mass to find the number of moles. In this case, 53.7 grams of sulfur is equivalent to about 1.68 moles.
How many grams atoms are in 100 of sulfur?
The molar mass of sulfur is approximately 32 grams per mole. Therefore, 100 grams of sulfur would contain approximately 3 moles of sulfur atoms (100 grams / 32 grams/mole). To find the number of atoms, you would then multiply the number of moles by Avogadro's number (6.022 x 10^23 atoms/mole) to get the total number of sulfur atoms in 100 grams.
How many moles OF s are present 7.71g of s?
To determine the number of moles of sulfur (S) present in 7.71g of S, you should first find the molar mass of sulfur, use it to convert the grams of sulfur to moles. Sulfur has a molar mass of approximately 32.06 g/mol, so the number of moles of S present in 7.71g is 7.71g / 32.06 g/mol = 0.24 moles of S.
How many ATOMS of sulfur are present in 9.96 grams of sulfur trioxide?
The formula for sulfur trioxide is SO3. The molecular weight is 80.06. The atomic weight of sulfur is 32.06. Therefore, the fraction by weight of sulfur in sulfur trioxide is 32.06/80.06 is 0.4004, to the justified number of significant digits, so that 9.96 grams of sulfur trioxide contains 3.988 grams of sulfur. The number of atoms present in 3.988 grams of sulfur therefore is Avogadro's Number X (3.988/80.06) or 3.000 X 1021 atoms, to the justified number of significant digits. (Note: A depressed final digit in a decimal means that the digit may not be significant.)
How many grams of sulfur trioxide are present in 4.136 mol?
2.408 x 10^24 atoms.
How many atoms of sulfer are present in 155 grams of sulfer?
The atomic weight of sulfur is about 32.066. Therefore, 155 grams of sulfur contains 155/32.066 or about 4.83 gram atomic masses of sulfur to the justified number of significant digits. Each such gram atomic mass contains Avogadro's number of atoms, for a total of 4.83 X 6.022 X 1023 or 2.91 X 1024 atoms.
how many grams are in 0.155 mole of sulfur?
To find the mass of sulfur in grams from moles, you can use the molar mass of sulfur, which is approximately 32.07 grams per mole. For 0.155 moles of sulfur, you multiply the number of moles by the molar mass: 0.155 moles × 32.07 g/mole = 4.97 grams. Therefore, there are approximately 4.97 grams of sulfur in 0.155 moles.
What is the of 3.09x10 24 atoms of sulfur in grams?
3,09x10e24 atoms of sulfur in grams is equal to 164,65 g.
What is the weight of one mole of sulfur?
The molecular weight of 1 mole of sulfur is 32 amu or grams.
How many moles of sulfur are in 53.7 grams of sulfur?
To determine the number of moles of sulfur in 53.7 grams, you first need to calculate the molar mass of sulfur, which is approximately 32.06 g/mol. Then, divide the given mass by the molar mass to find the number of moles. In this case, 53.7 grams of sulfur is equivalent to about 1.68 moles.
How many moles are in 6.5 grams of sulfur S?
6,5 grams of sulfur S are equal to 0,203 moles.
How can the theoretical yield of carbon disulfide be calculated when 120 g of methane is reacted with an equal mass of sulfur?
CH4 + 4S --> CS2 + 2H2S 120 g CH4 / 16.04 g/mol = 7.48 mol CH4 120 g S / 32.06 g/mol = 3.74 mol S 1 mol CH4 requires 4x1 mol S 7.48 mol CH4 requires 29.92 mol S S is limiting 3.74 mol S will yield 3.74 / 4 or 0.935 mol CS2 0.935 mol CS2 x 76.1 g/mol = 71.2 g CS2 theoretical yield
What is 2.50 mol of sulfur?
1 mol Sulfur is 32 g Sulfur So 2.5 mol Sulfur is 80 g Sulfur
How much carbon can 22 grams of carbon dioxide make?
22 grams of carbon dioxide contains 12 grams of carbon. This amount of carbon can combine with 32 grams of oxygen to form 44 grams of carbon dioxide.
