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CH4 + 4S --> CS2 + 2H2S

120 g CH4 / 16.04 g/mol = 7.48 mol CH4

120 g S / 32.06 g/mol = 3.74 mol S

1 mol CH4 requires 4x1 mol S

7.48 mol CH4 requires 29.92 mol S

S is limiting

3.74 mol S will yield 3.74 / 4 or 0.935 mol CS2

0.935 mol CS2 x 76.1 g/mol = 71.2 g CS2 theoretical yield

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Q: How can the theoretical yield of carbon disulfide be calculated when 120 g of methane is reacted with an equal mass of sulfur?
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