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How can the theoretical yield of carbon disulfide be calculated when 120 g of methane is reacted with an equal mass of sulfur?
CH4 + 4S --> CS2 + 2H2S
120 g CH4 / 16.04 g/mol = 7.48 mol CH4
120 g S / 32.06 g/mol = 3.74 mol S
1 mol CH4 requires 4x1 mol S
7.48 mol CH4 requires 29.92 mol S
S is limiting
3.74 mol S will yield 3.74 / 4 or 0.935 mol CS2
0.935 mol CS2 x 76.1 g/mol = 71.2 g CS2 theoretical yield
What else can I help you with?
When methane is burned in a lime kiln why are the wast gages carbon dioxide and nitrogen?
When methane is burned in a lime kiln, the waste gases are carbon dioxide and nitrogen because methane (CH4) reacts with oxygen (O2) to produce carbon dioxide (CO2) and water vapor (H2O) during combustion. Nitrogen is also present in the air and is not directly involved in the combustion process, so it remains as a waste gas in the form of nitrogen (N2).
Scientists believe that earth's early atmosphere changes in composition as a result of?
volcanic activity releasing gases, like carbon dioxide, methane, and water vapor. Over time, these gases reacted with other elements on Earth, leading to the formation of a new atmosphere. Additionally, the capture of gases from comets and asteroids also contributed to the changing composition of Earth's early atmosphere.
How is hydrogen processed?
One method for creating hydrogen is through methane reforming. Natural gas (which is mostly methane) is reacted, sometimes with steam, sometimes with oxygen. This natural gas degrades into hydrogen, carbon dioxide and carbon monoxide in varying amounts. This reaction takes place above 500 C and is used industrially to create hydrogen.
How many moles of hydrogen gas are produced when 0.066 mole of sodium is completely reacted?
The balanced chemical equation for the reaction between sodium and water is: 2Na + 2H2O -> 2NaOH + H2 This means that for every mole of sodium (Na) reacted, one mole of hydrogen gas (H2) is produced. Therefore, when 0.066 mole of sodium is reacted, 0.066 mole of hydrogen gas will be produced.
What is the percent yield when 7.80 grams of benzene burns in oxygen gas to form 3 grams of CO2 and water vapor?
C6H6 + 15 O2 = 12 CO2 + 6 H2O moles of C6H6 = 7.8 / 78 = .1 moles the O2 is in excess so benzene is the limiting agent and forms .1 x 6 moles of CO2 .6 moles of CO2 = .6 x 44 = 26.7 g at 100 % yield but we have 3 g or 3 / 26.7 % = 11.23 %
If in the previous problem only 25.9 grams of water vapor were formed how much methane actually reacted with oxygen?
The equation for the reaction between methane (CH4) and oxygen is: CH4 + 2O2 → CO2 + 2H2O From the previous information, if 25.9 grams of water vapor were formed, this corresponds to 25.9 grams ÷ 18.0 g/mol = 1.44 moles of water. This means 0.72 moles of methane reacted. If the molar mass of methane is 16.0 g/mol, then 0.72 moles of methane corresponds to 0.72 moles × 16.0 g/mol = 11.52 grams of methane reacted with oxygen.
What is the theoretical percent yield?
Percent yield is a term that compares the amount actually produced in a chemical reaction versus how much could have been produced had all the reactants reacted fully. Theoretical percent yield is always 100%, because theoretically, all of the reactants reacted.
When 500g of ammonia reacted with excess sulfuric acid to produce ammonium sulfate 1789g of product were obtained What is the percent yield of ammonium sulfate for this reaction?
The theoretical yield of ammonium sulfate can be calculated by determining the amount that would be produced if all the ammonia reacted. Given that 500g of ammonia was used, convert this amount to grams of ammonium sulfate. Then, divide the actual yield (1789g) by the theoretical yield and multiply by 100 to calculate the percent yield.
How do you convert Propane to Methane?
no i cannot
When 300g of ammonia reacted with excess sulfuric acid to produce ammonium sulfate 985 g of product were obtained what is the percent yield of ammonium sulfate for this reaction?
The theoretical yield of ammonium sulfate can be calculated based on the amount of ammonia used. To find the percent yield, divide the actual yield (985 g) by the theoretical yield and multiply by 100. Percent yield = (actual yield / theoretical yield) x 100.
What is made when methane and air are reacted?
methane rapidly combines with oxygen to form carbon dioxide and water, releasing lots of heat. it's called combustion.-------------------------------------------------------------------------CH4 + 2O2 = CO2 + 2H2O + heat
Which alkane do you suggest for preparation of toluene?
Methane could be used used for preparation of toluene but not directly. First, methane is reacted with chlorine to give chloromethane and that chloromethane is reacted with AlCl3 to form CH3+ and AlCl4- . This is reacted with Benzene(C6H6). This yields toluene as CH3+ replaces a hydrogen from Benzene.
What happened to ammonia and methane in earth's early atmosphere?
Ammonia and methane were likely abundant in Earth's early atmosphere, but over time they reacted with sunlight and other compounds to form new molecules like water vapor, carbon dioxide, and nitrogen gas. These changes were driven by processes such as photochemical reactions and biological activity, leading to the composition of the atmosphere we have today.
Calculate the theoretical yield of calcium chloride expected for this reaction if 0.80 mol of calcium hydroxide is reacted with excess hydrochloric acid.?
The balanced chemical equation for the reaction is Ca(OH)2 + 2HCl -> CaCl2 + 2H2O. Since 1 mol of Ca(OH)2 produces 1 mol of CaCl2, if 0.80 mol of Ca(OH)2 is reacted, the theoretical yield of CaCl2 is also 0.80 mol.
What is the dependent and independent variable in an experiment to find the gas constant where you change the mass of Mg reacted with HCl to form different number of moles of H2 gas?
co2 and oxygen even a little methane
You heat 3.970 g of a mixture of Fe3O4 and FeO to form 4.195 g Fe2O3 The mass of oxygen reacted is?
The change in mass is 0.225 g. The oxygen reacted can be calculated by determining the difference in the amount of oxygen in the reactants and products. The molar ratio of Fe2O3 to O2 is 2:3, so the mass of oxygen reacted would be 0.150 g.
How many moles of carbon dioxide are formed from 14 moles of methane?
When methane undergoes complete combustion, the equation for the reaction is CH4 + 2 O2 -> CO2 + 2 H2O. This shows that the number of moles of carbon dioxide formed are the same as the number of moles of methane reacted, so that 14 moles of carbon dioxide will be formed from 14 moles of methane.
