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How many moles are in 3.3 moles of K2S?
3.3 moles of K2S 3.3 moles of S-2 6.6 moles of K+1
How many moles of H will react with 1.72 moles of S?
Hydrogen reacts with sulfur in the proportions dictated by this equation:H2 + S --> H2S. The reactants are in a 1:1 proportion with each other, so 1.72 moles of hydrogen will react with 1.72 moles of sulfur.
How many grams of silver can be produced from the reaction of 92.8 g of silver nitrate with 1.34 g of aluminum?
Oxidation-reduction reaction:Ag^+(aq) + Al(s) ===> Ag(s) + Al^3+ or looked at another way... 3AgNO3(aq) + Al(s) ===> Al(NO3)3(aq) + 3Ag(s) moles AgNO3 present = 92.8 g x 1 mole/170 g =0.546 moles moles Al present = 1.34 g x 1 mole/26.9 g = 0.0498 moles Al is limiting based on mole ratio of 3 AgNO3 : 1 Al moles Ag(s) produced = 0.0498 moles Al x 3 moles Ag/mole Al = 0.1494 moles Ag mass of Ag = 0.1494 moles Ag x 108 g/mole = 16.1 g Ag formed
What is the number of S atoms in 0.660 mole of S?
There are 0.660 moles of sulfur atoms in 0.660 moles of S. To find the number of atoms, you would multiply the number of moles by Avogadro's number (6.022 x 10^23), so there are 3.97 x 10^23 sulfur atoms present.
How many moles of S are in 22.9g of C6H10S?
To find the number of moles of S in 22.9 g of C6H10S, you need to first calculate the molar mass of C6H10S, which is 126.23 g/mol. Then, divide the given mass by the molar mass to find the number of moles. For S in C6H10S, the molar mass contribution is 32.06 g/mol, so 22.9 g is equivalent to 0.717 moles of S.
How many moles s are present in 1 g of ammonia?
1 g of ammonia (NH3) is equal to 0,059 mol.
How many moles are in 3.3 moles of K2S?
3.3 moles of K2S 3.3 moles of S-2 6.6 moles of K+1
How many sulfur molecules are there in 6.35 moles of S?
6,35 moles of S contain 38,24059444195.10e23 sulfur atoms.
How many moles are in 6.5 grams of sulfur S?
6,5 grams of sulfur S are equal to 0,203 moles.
How many moles of H will react with 1.72 moles of S?
Hydrogen reacts with sulfur in the proportions dictated by this equation:H2 + S --> H2S. The reactants are in a 1:1 proportion with each other, so 1.72 moles of hydrogen will react with 1.72 moles of sulfur.
How many grams of silver can be produced from the reaction of 92.8 g of silver nitrate with 1.34 g of aluminum?
Oxidation-reduction reaction:Ag^+(aq) + Al(s) ===> Ag(s) + Al^3+ or looked at another way... 3AgNO3(aq) + Al(s) ===> Al(NO3)3(aq) + 3Ag(s) moles AgNO3 present = 92.8 g x 1 mole/170 g =0.546 moles moles Al present = 1.34 g x 1 mole/26.9 g = 0.0498 moles Al is limiting based on mole ratio of 3 AgNO3 : 1 Al moles Ag(s) produced = 0.0498 moles Al x 3 moles Ag/mole Al = 0.1494 moles Ag mass of Ag = 0.1494 moles Ag x 108 g/mole = 16.1 g Ag formed
A mixture containing 9 mol of F2 and 4 mol of S is allowed to react. How many moles of F2 remain after 3 mol of S have reacted?
After 3 moles of S have reacted, 3 moles of F2 will also have reacted since the reaction ratio is 1:1 based on the balanced chemical equation. This leaves 6 moles of F2 remaining (9 moles initially - 3 moles reacted).
What is the number of S atoms in 0.660 mole of S?
There are 0.660 moles of sulfur atoms in 0.660 moles of S. To find the number of atoms, you would multiply the number of moles by Avogadro's number (6.022 x 10^23), so there are 3.97 x 10^23 sulfur atoms present.
How many moles of S are in 22.9g of C6H10S?
To find the number of moles of S in 22.9 g of C6H10S, you need to first calculate the molar mass of C6H10S, which is 126.23 g/mol. Then, divide the given mass by the molar mass to find the number of moles. For S in C6H10S, the molar mass contribution is 32.06 g/mol, so 22.9 g is equivalent to 0.717 moles of S.
How many moles of Fe and S are contained in one mole of FeS2?
the atomic mass of FeS2 is 110. You cannot find the no. of moles in a mole of FeS2 coz it is only a mole.
How many atoms are present in 8g of S?
To determine the number of atoms in 8g of sulfur (S), you would first calculate the number of moles using the molar mass of sulfur (32 g/mol). Then, using Avogadro's number (6.022 x 10^23), you can convert the moles to atoms.
How many moles of copper must react to form 3.50 mol of Ag?
Cu(s) + 2AgNO3(aq) ---> Cu(NO3)2(aq) + 2Ag(s) So you need half as many moles of Cu. Thus 5.8/2 = 2.9 moles of Cu are needed.
