1 g of ammonia (NH3) is equal to 0,059 mol.
1 g silicon is equal to 0,0356 moles.
1.50 moles C9H8O4 (9 moles C/1 mole C9H8O4)(6.022 X 1023/1 mole C)= 8.13 X 1024 carbon atoms===================
2.45 X 1023 molecules CH2 (1 mole CH2/6.022 X 1023)= 0.407 moles CH2============
1 mol of hydrogen ion () corresponds to 1 equivalent. Therefore, 2.75 moles of in a solution would contain 2.75 equivalents.
Assuming that you mean the reaction of nitrogen and hydrogen to form ammonia N2 + 3H2 -> 2NH3 1 mole of nitrogen forms 2 moles of ammonia- so 4.08 l of nitrogen will be consumed to form 8.16 moles of ammonia. This assumes both are pretty ideal gases which is a reasonabale approximation.
There are approximately 0.023 moles of ammonia in 1 g of ammonia (NH3).
0,522 moles of ammonia contain 3,143.10e23 molecules of NH3.
To find the number of moles of electrons in ammonia (NH3), we first need to calculate the number of moles of ammonia using its molar mass. The molar mass of NH3 is 17 g/mol. Therefore, 17 grams of NH3 is equal to 1 mole. Since there are 3 electrons in each molecule of ammonia, there are 6.022 x 10^23 electrons present in 1 mole of NH3.
N2 + 3H2 -----> 2NH3 so 3 moles of hydrogen produce 2 moles of ammonia. Therefore 12.0 moles of hydrogen will produce 8 moles of ammonia.
Since ammonia has a chemical formula of NH3, it contains one mole of nitrogen and three moles of hydrogen per mole of ammonia. Therefore, 3 moles of ammonia contain 3 moles of nitrogen and 9 moles of hydrogen atoms.
There is 1 mole present in 1 lb-mole.
The calculation is: Moles = Mass / Atomic Mass Moles = 0.085 / 17 Moles = 0.005 Atomic mass is 17 because ammonia is NH3, with N = 14, and H = 1. 14 + 1 + 1 + 1 = 17.
Three moles of nitrogen are required to produce 2 moles of ammonia according to the balanced chemical reaction for ammonia synthesis. Therefore, 27 moles of nitrogen are required to produce 18 moles of ammonia.
That amount of ammonia contains two moles of hydrogen gas. One mole of hydrogen gas weighs 2.016 grams. Therfore 3.75 grams of ammonia contains two moles of hydrogen.
To form ammonia, reaction is N(2) + 3H(2) ---> 2NH(3) + H(2)O. As you can see for 1 mole of nitrogen three moles of hydrogen is required. Hence for your question, 1.13 moles nitrogen is required.
N2 + 3H2 --> 2NH3 You have been told, indirectly, that nitrogen limits and will drive the reaction. 3 moles N2 (2 moles NH3/1 mole N2) = 6 moles ammonia gas produced ========================
There are 5 moles of sulfur in 5 moles of H2SO4, as there is 1 mole of sulfur in each mole of H2SO4.