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How many moles are present in 1 g of ammonia nh3?
To find the number of moles in 1 g of ammonia (NH₃), first calculate its molar mass. The molar mass of NH₃ is approximately 17 g/mol (14 g/mol for nitrogen and 3 g/mol for hydrogen). Using the formula for moles (moles = mass/molar mass), we can calculate: 1 g NH₃ × (1 mol / 17 g) ≈ 0.059 moles of NH₃.
How many moles of ammonia will be required to produce 13.8 mol of water?
The balanced chemical equation for the formation of water from ammonia is: 2 NH₃ + 3 O₂ → 2 H₂O + N₂. According to the equation, 2 moles of ammonia produce 2 moles of water. Therefore, to produce 13.8 moles of water, you would require 13.8 moles of ammonia, since the ratio is 1:1.
How many moles are present in gram's of silicon Si?
1 g silicon is equal to 0,0356 moles.
How many carbon atoms are present in 1.50 moles of aspirin c9h8o4?
1.50 moles C9H8O4 (9 moles C/1 mole C9H8O4)(6.022 X 1023/1 mole C)= 8.13 X 1024 carbon atoms===================
How many moles present 2.45x1023 molecules of CH2?
2.45 X 1023 molecules CH2 (1 mole CH2/6.022 X 1023)= 0.407 moles CH2============
How many moles are present in 1 g of ammonia?
There are approximately 0.023 moles of ammonia in 1 g of ammonia (NH3).
How many molecules of ammonia NH3 are present in 0.522 moles of ammonia?
0,522 moles of ammonia contain 3,143.10e23 molecules of NH3.
How many moles of electrons are present in 17 grams of ammonia?
To find the number of moles of electrons in ammonia (NH3), we first need to calculate the number of moles of ammonia using its molar mass. The molar mass of NH3 is 17 g/mol. Therefore, 17 grams of NH3 is equal to 1 mole. Since there are 3 electrons in each molecule of ammonia, there are 6.022 x 10^23 electrons present in 1 mole of NH3.
How many moles of ammonia are produced from 12.0 moles of hydrogen?
N2 + 3H2 -----> 2NH3 so 3 moles of hydrogen produce 2 moles of ammonia. Therefore 12.0 moles of hydrogen will produce 8 moles of ammonia.
How many moles are present in 1 g of ammonia nh3?
To find the number of moles in 1 g of ammonia (NH₃), first calculate its molar mass. The molar mass of NH₃ is approximately 17 g/mol (14 g/mol for nitrogen and 3 g/mol for hydrogen). Using the formula for moles (moles = mass/molar mass), we can calculate: 1 g NH₃ × (1 mol / 17 g) ≈ 0.059 moles of NH₃.
How many moles of ammonia will be required to produce 13.8 mol of water?
The balanced chemical equation for the formation of water from ammonia is: 2 NH₃ + 3 O₂ → 2 H₂O + N₂. According to the equation, 2 moles of ammonia produce 2 moles of water. Therefore, to produce 13.8 moles of water, you would require 13.8 moles of ammonia, since the ratio is 1:1.
How many moles of hydrogen atoms are contained in 3 moles of ammonia?
Since ammonia has a chemical formula of NH3, it contains one mole of nitrogen and three moles of hydrogen per mole of ammonia. Therefore, 3 moles of ammonia contain 3 moles of nitrogen and 9 moles of hydrogen atoms.
How many moles are present in 1 lb-mole?
There is 1 mole present in 1 lb-mole.
0.085g of amonia is to how many moles?
The calculation is: Moles = Mass / Atomic Mass Moles = 0.085 / 17 Moles = 0.005 Atomic mass is 17 because ammonia is NH3, with N = 14, and H = 1. 14 + 1 + 1 + 1 = 17.
How many moles of nitrogen are required to produce 18 mol of ammonia?
Three moles of nitrogen are required to produce 2 moles of ammonia according to the balanced chemical reaction for ammonia synthesis. Therefore, 27 moles of nitrogen are required to produce 18 moles of ammonia.
How many moles of ammonia are needed to produce 3.5 mole of nitrogen?
That amount of ammonia contains two moles of hydrogen gas. One mole of hydrogen gas weighs 2.016 grams. Therfore 3.75 grams of ammonia contains two moles of hydrogen.
How many moles of nitrogen are required to react with 3.4 moles of hydrogen to form ammonia feterlizer?
To form ammonia, reaction is N(2) + 3H(2) ---> 2NH(3) + H(2)O. As you can see for 1 mole of nitrogen three moles of hydrogen is required. Hence for your question, 1.13 moles nitrogen is required.
