5.8 x 10-2 mol
5.00 moles H x 1 mole C2H4O2/4 moles H = 1.25 moles of C2H4O2 present.
N2 + 3H2 --> 2NH3 You have been told, indirectly, that nitrogen limits and will drive the reaction. 3 moles N2 (2 moles NH3/1 mole N2) = 6 moles ammonia gas produced ========================
6. 1 mole of CS2 contains 1 mole of carbon and 2 of sulfur.
3H2 + N2 <------> 2NH3 is the balanced equation for Hydrogen and Nitrogen making ammonia. 3 moles of H2 produces two moles of ammonia and thus to make 6 moles requires 9 moles of Hydrogen.
moles of N2 = 1000/28= 35.7 moles moles of NH3 = 2 x 35.7= 71.4 moles mass of NH3 = 71.4 x 17 (14+1+1+1) = 1214g
1 g of ammonia (NH3) is equal to 0,059 mol.
NH3 is balanced at 1:3, so in 3 moles NH3 there are 3*3 = 9 moles H atoms
The calculation is: Moles = Mass / Atomic Mass Moles = 0.085 / 17 Moles = 0.005 Atomic mass is 17 because ammonia is NH3, with N = 14, and H = 1. 14 + 1 + 1 + 1 = 17.
5.00 moles H x 1 mole C2H4O2/4 moles H = 1.25 moles of C2H4O2 present.
That amount of ammonia contains two moles of hydrogen gas. One mole of hydrogen gas weighs 2.016 grams. Therfore 3.75 grams of ammonia contains two moles of hydrogen.
7.95 X 1022 molecules NH3 (1 mole NH3/6.022 X 1023) = 0.132 moles ammonia =================
To form ammonia, reaction is N(2) + 3H(2) ---> 2NH(3) + H(2)O. As you can see for 1 mole of nitrogen three moles of hydrogen is required. Hence for your question, 1.13 moles nitrogen is required.
N2 + 3H2 --> 2NH3 You have been told, indirectly, that nitrogen limits and will drive the reaction. 3 moles N2 (2 moles NH3/1 mole N2) = 6 moles ammonia gas produced ========================
6. 1 mole of CS2 contains 1 mole of carbon and 2 of sulfur.
1 mole He is 4.0 g. Use as a conversion factor to change 0.12 g He to moles.
The number of moles is 1,5.
220mg of CO2 x (1 g / 1000mg) x (1 mole of CO2 / 44 g ) = 0.005 moles