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NH3 is balanced at 1:3, so in 3 moles NH3 there are 3*3 = 9 moles H atoms

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What is the number of hydrogen atoms present in 0.791 mole of ammonia?

The number of hydrogen atoms is 14,290540253661.10e23.


How many moles of hydrogen are in 6.50 g of ammonia?

To find the number of moles of hydrogen in 6.50 g of ammonia (NH3), first calculate the molar mass of ammonia (17.03 g/mol). Since ammonia has 3 hydrogen atoms, each with a molar mass of 1.01 g/mol, one mole of ammonia contains 3 moles of hydrogen atoms. Therefore, 6.50 g of ammonia contains (6.50 g / 17.03 g/mol) * 3 moles of hydrogen atoms.


How many moles of ammonia are produced from 12.0 moles of hydrogen?

N2 + 3H2 -----> 2NH3 so 3 moles of hydrogen produce 2 moles of ammonia. Therefore 12.0 moles of hydrogen will produce 8 moles of ammonia.


How many moles of nitrogen and hydrogen are needed to get 10 moles of ammonia?

The reaction of nitrogen with hydrogen to form ammonia is: N2 +3H2 = 2NH3 Therefore to make 10 moles of ammonia you need 5 moles N2 and 15 moles H2


What is the mole ratio of hydrogen to ammonia?

The mole ratio of hydrogen to ammonia in the reaction is 3:2. This means that for every 3 moles of hydrogen that react, 2 moles of ammonia are produced.


How many moles of ammonia can be produced from 18 moles of hydrogen?

The balanced chemical equation for the reaction between hydrogen and nitrogen to form ammonia is: 3H2 + N2 -> 2NH3 From the equation, it can be seen that 3 moles of hydrogen react to produce 2 moles of ammonia. Therefore, 18 moles of hydrogen can produce (2/3) x 18 = 12 moles of ammonia.


What has more atoms 17.031 grams of ammonia or 72.922 grams of hydrogen chloride?

Molar mass of ammonia is 17.031 whereas molar mass of hydrogen chloride (or hydrochloric acid) is 36.461. Hence if given masses, there is 1 mole ammonia and 2 moles HCl. Hence there is more number of hydrogen chloride.


How many atoms in seventeen moles of hydrogen?

Seventeen moles of hydrogen correspond to 204,75.10e23 atoms.


How many moles of hydrogen must react to produce 68 grams of ammonia?

To calculate the moles of hydrogen needed to produce 68 grams of ammonia (NH₃), we start with the balanced chemical equation for the synthesis of ammonia: N₂ + 3H₂ → 2NH₃. The molar mass of ammonia is approximately 17 g/mol, so 68 grams of NH₃ corresponds to 68 g / 17 g/mol = 4 moles of NH₃. Since 3 moles of hydrogen are required for every 2 moles of ammonia, the moles of hydrogen needed is (4 moles NH₃) × (3 moles H₂ / 2 moles NH₃) = 6 moles of H₂. Therefore, 6 moles of hydrogen must react to produce 68 grams of ammonia.


How many moles of hydrogen atoms are present in 2 moles of benzene?

2 moles of benzene gives 12 moles of hydrogen atoms since benzene is C6H6


Results for Calculate The Amount In Moles Of Molecules For Each Substance. A) A Sample Of Ammonia NH3(g) Containing 8.1x1020 Atoms Of Hydrogen?

NH3 Molecules = ( 8.1 x 10^20 H atoms ) ( 1 NH3 molecule / 3 H atoms ) NH3 Molecules = 2.7 x 10^20 NH3 molecules NH3 moles = ( NH3 molecules ) / ( N Avogadro ) NH3 moles = ( 2.7 x 10^20 NH3 molecules ) / ( 6.022 x 10^23 molecules / mole ) NH3 moles = 4.48 x 10^-4 NH3 moles <--------------


How many atoms are contained in 5.26 moles of oxygen?

5,26 moles of oxygen contain 31,676.10e23 atoms.