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How many moles of which reactant will remain if 1.39 moles of N and 3.44 moles of H will react to form ammonia find out how many grams of ammonia can be formed and how many moles of limiting reactant?
3,44 moles H2 react with 1,146 moles NH3. The limiting reactant is hydrogen. O,244 moles N2 remain. 19,5 g NH3 are obtained.
How many grams of H2 are needed to produce 10.06 g of NH3?
The formula reaction for NH3 when using N2 and H2 is: (N2)+3(H2) ---> 2(NH3) Now, first step is to find the moles of the H2 reactant. This is found via (grams of reactant)/(molar mass of reactant). There are 10 grams, and the molar mass of H2 is approximately 2.016. Therefore, the equation should look like: 10/2.016. This yields a value of ~4.9606 moles of H2. Now, you use the molar ratio from the reactant to the product to determine how many moles of product were yielded. According to the reaction, three moles of H2 are required to produces 2 moles of NH3. So, the mole ratio is 2/3. Multiply the number of moles of H2 with the molar ratio to determine the moles of NH3. 4.0606 * 2/3 = 3.3071 moles of NH3. Multiply the number of moles with the molar mass of NH3 (17.0306), and voila! 3.3071 * 17.0306 = 56.3216 grams. Now, if your teacher is feeling like a stickler about significant figures, than that value should be rounded to 56 grams of NH3.
How many moles of hydrigen are present in a 2 grams sample of hydrogen gas?
Mass (g) = Mr * Moles If you rearrange it, you get Moles = Mass/Mr Working with a 2dp periodic table you get: Moles = 2/1.01 =1.98 There are 1.98 moles of hydrogen in 2g of H2 gas.
18 l of ammonia were produced by the haber process how many liters of hydrogen were used during the reaction the reaction took place at stp 0ºc and 1.0 atm n2 g plus 3 h2 g --2 nh3 g?
According to the balanced chemical equation, 3 moles of hydrogen are required to produce 2 moles of ammonia. As 22.4 liters of any gas at STP is equal to 1 mole, 1 mole of hydrogen gas occupies 22.4 liters. Therefore, to produce 18 liters of ammonia, (18/22.4) x 3 = 2.68 moles of hydrogen were used. This equates to 2.68 x 22.4 = 60.03 liters of hydrogen gas used during the reaction.
How many grams of oxygen will be required to produce 25 moles of sulfur dioxide how many grams of oxygen will be required to produce 25 moles of sulfur dioxide?
800 g oxygen are needed.
How many hydrogen molecules are needed to produce 525 grams of ammonia?
To produce 525 grams of ammonia (NH3), you would need 25 moles of ammonia. Since the balanced chemical equation for the reaction between hydrogen and nitrogen to form ammonia is 3H2 + N2 -> 2NH3, you would need 75 moles of hydrogen molecules (H2) to produce 525 grams of ammonia. This is equivalent to 4,500 molecules of hydrogen.
How many moles of ammonia are produced from 12.0 moles of hydrogen?
N2 + 3H2 -----> 2NH3 so 3 moles of hydrogen produce 2 moles of ammonia. Therefore 12.0 moles of hydrogen will produce 8 moles of ammonia.
How many moles of ammonia are needed to produce 3.5 mole of nitrogen?
That amount of ammonia contains two moles of hydrogen gas. One mole of hydrogen gas weighs 2.016 grams. Therfore 3.75 grams of ammonia contains two moles of hydrogen.
Ammonia gas NH3 can be manufactured by combining hydrogen and nitrogen gases If 28 g of nitrogen and 7 g of hydrogen are available how many grams of ammonia can be produced?
The balanced chemical equation for the formation of ammonia from nitrogen and hydrogen is N2 + 3H2 → 2NH3. From the equation, it can be seen that 1 mole of nitrogen reacts with 3 moles of hydrogen to produce 2 moles of ammonia. Calculate the moles of nitrogen and hydrogen provided, determine the limiting reactant, and then use stoichiometry to find the grams of ammonia that can be produced.
How many moles of ammonia can be produced from 18 moles of hydrogen?
The balanced chemical equation for the reaction between hydrogen and nitrogen to form ammonia is: 3H2 + N2 -> 2NH3 From the equation, it can be seen that 3 moles of hydrogen react to produce 2 moles of ammonia. Therefore, 18 moles of hydrogen can produce (2/3) x 18 = 12 moles of ammonia.
How many moles of hydrogen are required to produce 18.00 moles of ammonia?
N2 + 3H2 -> 2NH3 The stoichiometric equation (or balanced equation) for the formation of ammonia from this we can read off the mole ratio between hydrogen and ammonia; 3M H2 needed to produce 2M NH3 times each by 9 (so the ratio remains the same and 18M NH3 is formed) 27M H2 needed to produce 18M NH3
How many moles of nitrogen and hydrogen are needed to get 10 moles of ammonia?
The reaction of nitrogen with hydrogen to form ammonia is: N2 +3H2 = 2NH3 Therefore to make 10 moles of ammonia you need 5 moles N2 and 15 moles H2
How many grams of ammonia NH3 will be prepared when 6.00g of hydrogen H2 has reacted?
The reaction between hydrogen and ammonia to form ammonia is 3H2 + N2 → 2NH3. To find the amount of ammonia produced when 6.00g of hydrogen reacts, first convert the mass of hydrogen to moles using its molar mass. Then, use the mole ratio from the balanced equation to find the moles of ammonia produced, and finally, convert this to grams using the molar mass of ammonia.
How many moles of hydgrogen are needed to produce 6.0 moles of ammonia?
This is based on calculations too. It contains 18 hydrogen moles.
If an excess of nitrogen is reacted with 3.41 grams of hydrogen how many grams of ammonia can be produced?
Balanced equation first. N2 + 3H2 >> 2NH3 (hydrogen is limiting and drives the reaction ) 3.41 grams H2 (1mol/2.016g )(2mol NH3/3mol H2 )(17.034g NH3/1mol NH3 ) = 19.2 grams of ammonia produced ( this is called the Born-Haber process )
What has more atoms 17.031 grams of ammonia or 72.922 grams of hydrogen chloride?
Molar mass of ammonia is 17.031 whereas molar mass of hydrogen chloride (or hydrochloric acid) is 36.461. Hence if given masses, there is 1 mole ammonia and 2 moles HCl. Hence there is more number of hydrogen chloride.
Mass of 3 moles of ammonia?
Molar mass of ammonia = (14.01 + 3.03) (Molar mass of nitrogen + 3 times molar mass of hydrogen, as chemical formula of ammonia is NH3). Molar mass= 17.04 Molar mass x moles = mass 17.04 x 3 = 51.12 Mass of 3 moles of ammonia is 51.12g.
