N2 + 3H2 -> 2NH3
The stoichiometric equation (or balanced equation) for the formation of ammonia
from this we can read off the mole ratio between hydrogen and ammonia;
3M H2 needed to produce 2M NH3
times each by 9 (so the ratio remains the same and 18M NH3 is formed)
27M H2 needed to produce 18M NH3
N2 + 3H2 -----> 2NH3 so 3 moles of hydrogen produce 2 moles of ammonia. Therefore 12.0 moles of hydrogen will produce 8 moles of ammonia.
The balanced chemical equation for the reaction between hydrogen and nitrogen to form ammonia is: 3H2 + N2 -> 2NH3 From the equation, it can be seen that 3 moles of hydrogen react to produce 2 moles of ammonia. Therefore, 18 moles of hydrogen can produce (2/3) x 18 = 12 moles of ammonia.
The reaction of nitrogen with hydrogen to form ammonia is: N2 +3H2 = 2NH3 Therefore to make 10 moles of ammonia you need 5 moles N2 and 15 moles H2
Three moles of nitrogen are required to produce 2 moles of ammonia according to the balanced chemical reaction for ammonia synthesis. Therefore, 27 moles of nitrogen are required to produce 18 moles of ammonia.
When 1 liter of nitrogen gas reacts with 3 liters of hydrogen gas, they will react to produce 2 liters of ammonia gas. This follows the balanced chemical equation: N2 + 3H2 → 2NH3. Each mole of nitrogen reacts with 3 moles of hydrogen to produce 2 moles of ammonia.
N2 + 3H2 -----> 2NH3 so 3 moles of hydrogen produce 2 moles of ammonia. Therefore 12.0 moles of hydrogen will produce 8 moles of ammonia.
To form ammonia, reaction is N(2) + 3H(2) ---> 2NH(3) + H(2)O. As you can see for 1 mole of nitrogen three moles of hydrogen is required. Hence for your question, 1.13 moles nitrogen is required.
The balanced chemical equation for the reaction between hydrogen and nitrogen to form ammonia is: 3H2 + N2 -> 2NH3 From the equation, it can be seen that 3 moles of hydrogen react to produce 2 moles of ammonia. Therefore, 18 moles of hydrogen can produce (2/3) x 18 = 12 moles of ammonia.
The reaction of nitrogen with hydrogen to form ammonia is: N2 +3H2 = 2NH3 Therefore to make 10 moles of ammonia you need 5 moles N2 and 15 moles H2
This is based on calculations too. It contains 18 hydrogen moles.
Three moles of nitrogen are required to produce 2 moles of ammonia according to the balanced chemical reaction for ammonia synthesis. Therefore, 27 moles of nitrogen are required to produce 18 moles of ammonia.
To produce 525 grams of ammonia (NH3), you would need 25 moles of ammonia. Since the balanced chemical equation for the reaction between hydrogen and nitrogen to form ammonia is 3H2 + N2 -> 2NH3, you would need 75 moles of hydrogen molecules (H2) to produce 525 grams of ammonia. This is equivalent to 4,500 molecules of hydrogen.
That amount of ammonia contains two moles of hydrogen gas. One mole of hydrogen gas weighs 2.016 grams. Therfore 3.75 grams of ammonia contains two moles of hydrogen.
The mole ratio of hydrogen to ammonia in the reaction is 3:2. This means that for every 3 moles of hydrogen that react, 2 moles of ammonia are produced.
The balanced chemical equation for the reaction between nitrogen and hydrogen to produce ammonia is: 3 H2 + N2 -> 2 NH3 From the balanced equation, we see that 1 mole of N2 produces 2 moles of NH3. Therefore, to convert 9 moles of H2 to NH3, we would need 9/3 = 3 moles of N2.
The balanced chemical equation for the formation of ammonia from nitrogen and hydrogen is N2 + 3H2 → 2NH3. From the equation, it can be seen that 1 mole of nitrogen reacts with 3 moles of hydrogen to produce 2 moles of ammonia. Calculate the moles of nitrogen and hydrogen provided, determine the limiting reactant, and then use stoichiometry to find the grams of ammonia that can be produced.
To produce 1 mole of water, you need 2 moles of hydrogen. Therefore, to produce 7.4 moles of water, you would need 2 * 7.4 = 14.8 moles of hydrogen.