N2 + 3H2 -> 2NH3
The stoichiometric equation (or balanced equation) for the formation of ammonia
from this we can read off the mole ratio between hydrogen and ammonia;
3M H2 needed to produce 2M NH3
times each by 9 (so the ratio remains the same and 18M NH3 is formed)
27M H2 needed to produce 18M NH3
N2 + 3H2 -----> 2NH3 so 3 moles of hydrogen produce 2 moles of ammonia. Therefore 12.0 moles of hydrogen will produce 8 moles of ammonia.
The reaction of nitrogen with hydrogen to form ammonia is: N2 +3H2 = 2NH3 Therefore to make 10 moles of ammonia you need 5 moles N2 and 15 moles H2
The chemical equation is N2 + 3H2 -> 2NH3 So reacting 2 moles of N2 will produce 4 moles ammonia.
2N + 3H2 -> 2NH3 18 moles H2 (2 moles NH3/3 moles H2) = 12 mole ammonia
3H2 + N2 <------> 2NH3 is the balanced equation for Hydrogen and Nitrogen making ammonia. 3 moles of H2 produces two moles of ammonia and thus to make 6 moles requires 9 moles of Hydrogen.
N2 + 3H2 -----> 2NH3 so 3 moles of hydrogen produce 2 moles of ammonia. Therefore 12.0 moles of hydrogen will produce 8 moles of ammonia.
That amount of ammonia contains two moles of hydrogen gas. One mole of hydrogen gas weighs 2.016 grams. Therfore 3.75 grams of ammonia contains two moles of hydrogen.
To form ammonia, reaction is N(2) + 3H(2) ---> 2NH(3) + H(2)O. As you can see for 1 mole of nitrogen three moles of hydrogen is required. Hence for your question, 1.13 moles nitrogen is required.
9H2 + 3N2 ------> 6NH3 3 moles of N2 would be required.
3,75 moles hydrogen
N2 + 3H2 ---> 2NH3 so 3 moles of Hydrogen produces 2 moles of ammonia. Thus 1.8 moles will produce 1.8/3 x 2 = 1.2 moles of ammonia.
The reaction of nitrogen with hydrogen to form ammonia is: N2 +3H2 = 2NH3 Therefore to make 10 moles of ammonia you need 5 moles N2 and 15 moles H2
This is not a common reaction at standard temperature and pressure.
To form ammonia, balanced reaction is N(2) + 3H(2) ---> 2NH(3) + H(2)O. As you can see for 1 mole of nitrogen three moles of hydrogen is required. Hence for your question, 3 moles nitrogen is required to satisfy the ratio.
The chemical equation is N2 + 3H2 -> 2NH3 So reacting 2 moles of N2 will produce 4 moles ammonia.
2N + 3H2 -> 2NH3 18 moles H2 (2 moles NH3/3 moles H2) = 12 mole ammonia
There are two elements that make up Ammonia (NH3) … One mole of Nitrogen (N) plus three moles of Hydrogen (H) react to produce one mole of Ammonia (NH3)