Here are 0,2 moles sulfur.
3.3 moles of K2S 3.3 moles of S-2 6.6 moles of K+1
300 g sulfur is equivalent to 9,36 moles.
7.71 grams sulfur (1 mole S/32.07 grams) = 0.2404 moles of sulfur
Hydrogen reacts with sulfur in the proportions dictated by this equation:H2 + S --> H2S. The reactants are in a 1:1 proportion with each other, so 1.72 moles of hydrogen will react with 1.72 moles of sulfur.
AgNO3 + NaCl ===> AgCl(s) + NaNO37 moles silver nitrate will produce 7 moles of silver chloride provided there is sufficient (at least 7 moles) of sodium chloride.
3.3 moles of K2S 3.3 moles of S-2 6.6 moles of K+1
6,5 grams of sulfur S are equal to 0,203 moles.
6,35 moles of S contain 38,24059444195.10e23 sulfur atoms.
300 g sulfur is equivalent to 9,36 moles.
7.71 grams sulfur (1 mole S/32.07 grams) = 0.2404 moles of sulfur
Hydrogen reacts with sulfur in the proportions dictated by this equation:H2 + S --> H2S. The reactants are in a 1:1 proportion with each other, so 1.72 moles of hydrogen will react with 1.72 moles of sulfur.
Cu(s) + 2AgNO3(aq) ---> Cu(NO3)2(aq) + 2Ag(s) So you need half as many moles of Cu. Thus 5.8/2 = 2.9 moles of Cu are needed.
AgNO3 + NaCl ===> AgCl(s) + NaNO37 moles silver nitrate will produce 7 moles of silver chloride provided there is sufficient (at least 7 moles) of sodium chloride.
0,092 moles CaO
Assuming the reaction is S + O2 --> SO2, this equation is balanced as written, with everything in a 1:1 molar ratio. So, 67.1 moles of product would require 67.1 moles of O2 reactant.
3.82g of SO2 equals 0,06 moles.
the atomic mass of FeS2 is 110. You cannot find the no. of moles in a mole of FeS2 coz it is only a mole.