300 g sulfur is equivalent to 9,36 moles.
3.3 moles of K2S 3.3 moles of S-2 6.6 moles of K+1
To determine the number of moles of sulfur (S) present in 7.71g of S, you should first find the molar mass of sulfur, use it to convert the grams of sulfur to moles. Sulfur has a molar mass of approximately 32.06 g/mol, so the number of moles of S present in 7.71g is 7.71g / 32.06 g/mol = 0.24 moles of S.
Hydrogen reacts with sulfur in the proportions dictated by this equation:H2 + S --> H2S. The reactants are in a 1:1 proportion with each other, so 1.72 moles of hydrogen will react with 1.72 moles of sulfur.
There are 6 units of 500g in 3kg. This is because 3kg is equal to 3000g, and 3000g divided by 500g equals 6.
To find the number of moles of S in 22.9 g of C6H10S, you need to first calculate the molar mass of C6H10S, which is 126.23 g/mol. Then, divide the given mass by the molar mass to find the number of moles. For S in C6H10S, the molar mass contribution is 32.06 g/mol, so 22.9 g is equivalent to 0.717 moles of S.
The answer is 30kg
3000g = 3000 grams
300 dekagrams is 3000g
3.3 moles of K2S 3.3 moles of S-2 6.6 moles of K+1
6,35 moles of S contain 38,24059444195.10e23 sulfur atoms.
6,5 grams of sulfur S are equal to 0,203 moles.
3000g = 3kg
3 since each kg is 1000 grams.
=
well if 1000g is one kg 3000g is 3kg
6kg what's the
To determine the number of moles of sulfur (S) present in 7.71g of S, you should first find the molar mass of sulfur, use it to convert the grams of sulfur to moles. Sulfur has a molar mass of approximately 32.06 g/mol, so the number of moles of S present in 7.71g is 7.71g / 32.06 g/mol = 0.24 moles of S.