Hydrogen reacts with sulfur in the proportions dictated by this equation:
H2 + S --> H2S. The reactants are in a 1:1 proportion with each other, so 1.72 moles of hydrogen will react with 1.72 moles of sulfur.
One mole to react with ONE mole CH3COOH (ethaancarbonic acid) because it has only ONE proton (H+) to react with, the other 3 Hydrogen's are not proteolytic (=NON-acidic)
2H2 + O2 --> 2H2OAs you can see by the balanced reaction, for every 1 mole of oxygen used, 2 moles of water are formed. Also notice that for every 1 mole of oxygen used, you need 2 moles of hydrogen to produce the 2 moles of water. So in your case 110 moles of oxygen would produce 220 moles of water & would also require 220 moles of hydrogen (which you have in excess since you have 230 moles of hydrogen). So 220 moles of water are the most that can be formed.
1.5 moles of Hydrogen. In every mole of H2SO4 (Sulfuric Acid) there are 2 moles of Hydrogen atoms. So, in .75 moles of Sulfuric Acid, there would be 1.5 (double the moles of sulfuric acid) moles of Hydrogen.
2 moles C8H18 (18 moles H/1 mole C8H18) = 36 moles of hydrogen =================
The balanced chemical equation for the reaction between potassium hydroxide (KOH) and nitric acid (HNO3) is 1:1 ratio. Therefore, 3 moles of nitric acid will require 3 moles of potassium hydroxide to neutralize it.
To determine how many moles of oxygen are needed to completely react with isooctane (C₈H₁₈), we can use the balanced combustion reaction: 2 C₈H₁₈ + 25 O₂ → 16 CO₂ + 18 H₂O. From this equation, 2 moles of isooctane react with 25 moles of oxygen, indicating that 1 mole of isooctane requires 12.5 moles of oxygen. Therefore, for 4 moles of isooctane, 4 × 12.5 = 50 moles of oxygen are needed.
3,44 moles H2 react with 1,146 moles NH3. The limiting reactant is hydrogen. O,244 moles N2 remain. 19,5 g NH3 are obtained.
The ratio H/O is 2.
To determine how many moles of water are needed to react with 2.0 moles of calcium (Ca), we first need to consider the chemical reaction between calcium and water. The balanced equation is: [ \text{Ca} + 2 \text{H}_2\text{O} \rightarrow \text{Ca(OH)}_2 + \text{H}_2 ] From the equation, 1 mole of calcium reacts with 2 moles of water. Therefore, for 2.0 moles of calcium, you would need ( 2.0 , \text{moles Ca} \times 2 , \text{moles H}_2\text{O}/\text{mole Ca} = 4.0 , \text{moles H}_2\text{O} ). Thus, 4.0 moles of water are required.
The answer is 10 moles.
One mole to react with ONE mole CH3COOH (ethaancarbonic acid) because it has only ONE proton (H+) to react with, the other 3 Hydrogen's are not proteolytic (=NON-acidic)
2H2 + O2 --> 2H2OAs you can see by the balanced reaction, for every 1 mole of oxygen used, 2 moles of water are formed. Also notice that for every 1 mole of oxygen used, you need 2 moles of hydrogen to produce the 2 moles of water. So in your case 110 moles of oxygen would produce 220 moles of water & would also require 220 moles of hydrogen (which you have in excess since you have 230 moles of hydrogen). So 220 moles of water are the most that can be formed.
To determine the number of moles of water needed to react with 1.7 moles of Li2O, we can use the balanced chemical equation for the reaction: [ \text{Li}_2\text{O} + 2\text{H}_2\text{O} \rightarrow 2\text{LiOH}. ] From the equation, 1 mole of Li2O reacts with 2 moles of water. Therefore, 1.7 moles of Li2O would require 1.7 x 2 = 3.4 moles of water.
To calculate the moles of hydrogen needed to produce 68 grams of ammonia (NH₃), we start with the balanced chemical equation for the synthesis of ammonia: N₂ + 3H₂ → 2NH₃. The molar mass of ammonia is approximately 17 g/mol, so 68 grams of NH₃ corresponds to 68 g / 17 g/mol = 4 moles of NH₃. Since 3 moles of hydrogen are required for every 2 moles of ammonia, the moles of hydrogen needed is (4 moles NH₃) × (3 moles H₂ / 2 moles NH₃) = 6 moles of H₂. Therefore, 6 moles of hydrogen must react to produce 68 grams of ammonia.
The combustion of butane (C₄H₁₀) can be represented by the balanced equation: 2 C₄H₁₀ + 13 O₂ → 8 CO₂ + 10 H₂O. From this equation, we see that 2 moles of butane produce 8 moles of carbon dioxide. Therefore, if 5.31 moles of C₄H₁₀ are used, the moles of CO₂ produced can be calculated as follows: (5.31 moles C₄H₁₀) × (8 moles CO₂ / 2 moles C₄H₁₀) = 21.24 moles of CO₂.
When sodium (Na) reacts with water (H₂O), it produces sodium hydroxide (NaOH) and hydrogen gas (H₂). The balanced chemical equation for this reaction is: [ 2 \text{Na} + 2 \text{H}_2\text{O} \rightarrow 2 \text{NaOH} + \text{H}_2 ] From the equation, 2 moles of sodium produce 1 mole of hydrogen. Therefore, if 4 moles of sodium react completely, they will produce 2 moles of hydrogen gas.
1.5 moles of Hydrogen. In every mole of H2SO4 (Sulfuric Acid) there are 2 moles of Hydrogen atoms. So, in .75 moles of Sulfuric Acid, there would be 1.5 (double the moles of sulfuric acid) moles of Hydrogen.