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How many moles of NaOH do you need to react with CH3CO2H?
One mole to react with ONE mole CH3COOH (ethaancarbonic acid) because it has only ONE proton (H+) to react with, the other 3 Hydrogen's are not proteolytic (=NON-acidic)
How many moles of water are formed with 230 moles of H2 and 110 moles of O2?
2H2 + O2 --> 2H2OAs you can see by the balanced reaction, for every 1 mole of oxygen used, 2 moles of water are formed. Also notice that for every 1 mole of oxygen used, you need 2 moles of hydrogen to produce the 2 moles of water. So in your case 110 moles of oxygen would produce 220 moles of water & would also require 220 moles of hydrogen (which you have in excess since you have 230 moles of hydrogen). So 220 moles of water are the most that can be formed.
How many moles of H are in 0.75 moles of H2SO4?
1.5 moles of Hydrogen. In every mole of H2SO4 (Sulfuric Acid) there are 2 moles of Hydrogen atoms. So, in .75 moles of Sulfuric Acid, there would be 1.5 (double the moles of sulfuric acid) moles of Hydrogen.
How many moles of H are in 2 mol of c8h18?
2 moles C8H18 (18 moles H/1 mole C8H18) = 36 moles of hydrogen =================
How many moles of potassium hydroxide are needed to neutralize 3 moles of nitric acid?
The balanced chemical equation for the reaction between potassium hydroxide (KOH) and nitric acid (HNO3) is 1:1 ratio. Therefore, 3 moles of nitric acid will require 3 moles of potassium hydroxide to neutralize it.
How many moles of Oxygen are needed to completely react with 4 moles of isooctane?
To determine how many moles of oxygen are needed to completely react with isooctane (C₈H₁₈), we can use the balanced combustion reaction: 2 C₈H₁₈ + 25 O₂ → 16 CO₂ + 18 H₂O. From this equation, 2 moles of isooctane react with 25 moles of oxygen, indicating that 1 mole of isooctane requires 12.5 moles of oxygen. Therefore, for 4 moles of isooctane, 4 × 12.5 = 50 moles of oxygen are needed.
How many moles of which reactant will remain if 1.39 moles of N and 3.44 moles of H will react to form ammonia find out how many grams of ammonia can be formed and how many moles of limiting reactant?
3,44 moles H2 react with 1,146 moles NH3. The limiting reactant is hydrogen. O,244 moles N2 remain. 19,5 g NH3 are obtained.
The relative number of moles of hydrogen to moles of oxygen that react to form water represents what?
The ratio H/O is 2.
How many moles are in 20.0g H?
The answer is 10 moles.
How many moles of NaOH do you need to react with CH3CO2H?
One mole to react with ONE mole CH3COOH (ethaancarbonic acid) because it has only ONE proton (H+) to react with, the other 3 Hydrogen's are not proteolytic (=NON-acidic)
How many moles of water are formed with 230 moles of H2 and 110 moles of O2?
2H2 + O2 --> 2H2OAs you can see by the balanced reaction, for every 1 mole of oxygen used, 2 moles of water are formed. Also notice that for every 1 mole of oxygen used, you need 2 moles of hydrogen to produce the 2 moles of water. So in your case 110 moles of oxygen would produce 220 moles of water & would also require 220 moles of hydrogen (which you have in excess since you have 230 moles of hydrogen). So 220 moles of water are the most that can be formed.
How many moles of water are needed to react with 1.7 moles of Li2O?
To determine the number of moles of water needed to react with 1.7 moles of Li2O, we can use the balanced chemical equation for the reaction: [ \text{Li}_2\text{O} + 2\text{H}_2\text{O} \rightarrow 2\text{LiOH}. ] From the equation, 1 mole of Li2O reacts with 2 moles of water. Therefore, 1.7 moles of Li2O would require 1.7 x 2 = 3.4 moles of water.
How many moles of hydrogen must react to produce 68 grams of ammonia?
To calculate the moles of hydrogen needed to produce 68 grams of ammonia (NH₃), we start with the balanced chemical equation for the synthesis of ammonia: N₂ + 3H₂ → 2NH₃. The molar mass of ammonia is approximately 17 g/mol, so 68 grams of NH₃ corresponds to 68 g / 17 g/mol = 4 moles of NH₃. Since 3 moles of hydrogen are required for every 2 moles of ammonia, the moles of hydrogen needed is (4 moles NH₃) × (3 moles H₂ / 2 moles NH₃) = 6 moles of H₂. Therefore, 6 moles of hydrogen must react to produce 68 grams of ammonia.
How many moles of co2 will be produced if 5.31 moles of c4h10 are used?
The combustion of butane (C₄H₁₀) can be represented by the balanced equation: 2 C₄H₁₀ + 13 O₂ → 8 CO₂ + 10 H₂O. From this equation, we see that 2 moles of butane produce 8 moles of carbon dioxide. Therefore, if 5.31 moles of C₄H₁₀ are used, the moles of CO₂ produced can be calculated as follows: (5.31 moles C₄H₁₀) × (8 moles CO₂ / 2 moles C₄H₁₀) = 21.24 moles of CO₂.
How many moles of H are in 0.75 moles of H2SO4?
1.5 moles of Hydrogen. In every mole of H2SO4 (Sulfuric Acid) there are 2 moles of Hydrogen atoms. So, in .75 moles of Sulfuric Acid, there would be 1.5 (double the moles of sulfuric acid) moles of Hydrogen.
The equation of combustion of the isopropyl alcohol is C3H7OH I plus O2 g CO2 g plus H2O g How many moles of isopropyl alcohol are required to consume entirely 16 moles of oxygen?
The balanced equation for the combustion of isopropyl alcohol (C₃H₇OH) is: [ C₃H₇OH + 4 O₂ \rightarrow 3 CO₂ + 3 H₂O. ] From the equation, 1 mole of isopropyl alcohol reacts with 4 moles of oxygen. Therefore, to consume 16 moles of oxygen, you would need: [ \frac{16 \text{ moles O₂}}{4 \text{ moles O₂/mole C₃H₇OH}} = 4 \text{ moles of C₃H₇OH}. ] Thus, 4 moles of isopropyl alcohol are required to react with 16 moles of oxygen.
If there are 5.00 mol of H How many moles of C2H4O2 are present?
5.00 moles H x 1 mole C2H4O2/4 moles H = 1.25 moles of C2H4O2 present.
