One mole to react with ONE mole CH3COOH (ethaancarbonic acid) because it has only ONE proton (H+) to react with, the other 3 Hydrogen's are not proteolytic (=NON-acidic)
2 moles of NaOH will react with 1 mole of H2SO4 based on the balanced chemical equation: 2NaOH + H2SO4 -> Na2SO4 + 2H2O.
KHC8H4O4(aq) + NaOH(aq) --> KNaC8H4O4(aq) + H2O(l). The molar mass of KHP is approximately 204.22 g/mol. 1.54g of KHP is equivalent to 0.00754 mol of KHP. 1 mole of NaOH reacts per mole of KHP, so .00754 mol of NaOH are needed.
The balanced chemical equation for the reaction is: 3 H3PO4 + 2 NaOH -> Na3PO4 + 3 H2O From the equation, we can see that 3 moles of H3PO4 react with 2 moles of NaOH. Calculate the molar mass of H3PO4 and NaOH. Then, use the molar ratio from the balanced equation to calculate the amount of H3PO4 needed to react with 25.4g of NaOH.
1st Get the balanced equation NaOH + HCl -> NaCl + H2O Find the number of moles in HCl; n = cv n = 0.46x0.61 n = 0.2806 moles the number of moles of HCl and NaOH is the same so 0.2806moles will be needed
The balanced chemical equation for the reaction between sodium oxide (Na2O) and water (H2O) is: 2Na2O + 2H2O -> 4NaOH From the equation, it can be seen that 2 moles of Na2O react with 2 moles of H2O to produce 4 moles of NaOH. Therefore, 42.0 moles of water would react with 21.0 moles of sodium oxide (Na2O).
2 moles of NaOH will react with 1 mole of H2SO4 based on the balanced chemical equation: 2NaOH + H2SO4 -> Na2SO4 + 2H2O.
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KHC8H4O4(aq) + NaOH(aq) --> KNaC8H4O4(aq) + H2O(l). The molar mass of KHP is approximately 204.22 g/mol. 1.54g of KHP is equivalent to 0.00754 mol of KHP. 1 mole of NaOH reacts per mole of KHP, so .00754 mol of NaOH are needed.
The balanced chemical equation for the reaction between HCl and NaOH is: HCl + NaOH -> NaCl + H2O Since the stoichiometry of the reaction is 1:1 for NaCl and HCl, if 1.4 moles of HCl react, then 1.4 moles of NaCl will be formed.
The balanced chemical equation for the reaction is: 3 H3PO4 + 2 NaOH -> Na3PO4 + 3 H2O From the equation, we can see that 3 moles of H3PO4 react with 2 moles of NaOH. Calculate the molar mass of H3PO4 and NaOH. Then, use the molar ratio from the balanced equation to calculate the amount of H3PO4 needed to react with 25.4g of NaOH.
208g NaOH
The number of moles is 0,0038.
Molarity = moles of solute/Liters of solution 3.42 M NaOH = 1.3 moles NaOH/Liters NaOH Liters NaOH = 1.3 moles NaOH/3.42 M NaOH = 0.38 Liters
1st Get the balanced equation NaOH + HCl -> NaCl + H2O Find the number of moles in HCl; n = cv n = 0.46x0.61 n = 0.2806 moles the number of moles of HCl and NaOH is the same so 0.2806moles will be needed
moles = mass/Mr moles = 100/(23+16+1) moles of NaOH = 2.5mol
The balanced chemical equation for the reaction between sodium and water is: 2 Na + 2 H2O -> 2 NaOH + H2 Since 2 moles of water are needed to react with 2 moles of sodium, 1 mole of water is needed to react with 1 mole of sodium. Therefore, 2.5 moles of sodium will require 2.5 moles of water for the reaction.
The balanced chemical equation for the reaction between sodium oxide (Na2O) and water (H2O) is: 2Na2O + 2H2O -> 4NaOH From the equation, it can be seen that 2 moles of Na2O react with 2 moles of H2O to produce 4 moles of NaOH. Therefore, 42.0 moles of water would react with 21.0 moles of sodium oxide (Na2O).