The number of moles of NaOH used in the titration process can be calculated by dividing the volume of NaOH solution used by the molarity of the NaOH solution.
x/18.38L = 0.1574m/Lx= 2.893 mol------------------------------------------------18.38 ml = .01838 Lx/.01838 L = 0.1574 Mx= 0.0029 mol
To begin, calculate the number of moles of KHP using its molar mass. Next, use the stoichiometry of the reaction to determine the moles of NaOH required for complete titration. Finally, use the concentration of NaOH to calculate the volume needed in milliliters using the formula: volume (mL) = moles needed / molarity.
When titrating NaOH with KHP (potassium hydrogen phthalate), the number of moles of NaOH will be equal to the number of moles of KHP at the equivalence point. This is because the reaction is stoichiometric, with one mole of NaOH reacting with one mole of KHP.
To calculate the grams of NaOH in the solution, you first need to find the moles of NaOH present in 400.0 ml of the solution. The moles of NaOH can be calculated using the formula: moles = molarity x volume (in liters). Once you have the moles of NaOH, you can then calculate the grams using the formula: grams = moles x molecular weight.
First, calculate the number of moles of NaOH: Moles = Molarity x Volume (L) Convert mL to L: 450 mL = 0.45 L Moles = 0.25 N x 0.45 L = 0.1125 moles of NaOH.
To calculate the moles of NaOH used in the titration, multiply the volume (in liters) by the molarity. Converting 20.0 mL to liters (20.0 mL * 1 L/1000 mL = 0.020 L), the moles of NaOH used would be (0.020 L * 150 mol/L = 3.0 moles of NaOH).
x/18.38L = 0.1574m/Lx= 2.893 mol------------------------------------------------18.38 ml = .01838 Lx/.01838 L = 0.1574 Mx= 0.0029 mol
I need to see the balanced equation to work!NaOH + HCl --> NaCl + H2O ( good, all one to one )Now, find molarity HCl ( sodium, or sodium hydroxide; no matter )(17.65 mL)(0.110 M NaOH) = (25.00 mL)(X M HCl)= 0.07766 M HCl-------------------------now,Molarity = moles of solute/Liters of solution ( 25.00 mL = 0.025 L)0.07766 M HCl = X moles/0.025 Liters= 0.001942 moles HCl---------------------------------------formal set up, though not needed0.001942 moles HCl (1 mole NaOH/1 mole HCl)= 0.00194 moles sodium hydroxide used=============================
208g NaOH
The number of moles is 0,0038.
Molarity = moles of solute/Liters of solution 3.42 M NaOH = 1.3 moles NaOH/Liters NaOH Liters NaOH = 1.3 moles NaOH/3.42 M NaOH = 0.38 Liters
To determine the grams of KHP required, you first need to calculate the number of moles of NaOH present in the 50 mL solution. Then, using the balanced chemical equation of the titration between NaOH and KHP, you can find the mole ratio. From the mole ratio and the moles of NaOH, you can calculate the moles of KHP needed and then convert that to grams of KHP.
moles = mass/Mr moles = 100/(23+16+1) moles of NaOH = 2.5mol
8 g NaOH x 1 mole NaOH/40 g = 0.2 moles NaOH
To begin, calculate the number of moles of KHP using its molar mass. Next, use the stoichiometry of the reaction to determine the moles of NaOH required for complete titration. Finally, use the concentration of NaOH to calculate the volume needed in milliliters using the formula: volume (mL) = moles needed / molarity.
When titrating NaOH with KHP (potassium hydrogen phthalate), the number of moles of NaOH will be equal to the number of moles of KHP at the equivalence point. This is because the reaction is stoichiometric, with one mole of NaOH reacting with one mole of KHP.
To calculate the grams of NaOH in the solution, you first need to find the moles of NaOH present in 400.0 ml of the solution. The moles of NaOH can be calculated using the formula: moles = molarity x volume (in liters). Once you have the moles of NaOH, you can then calculate the grams using the formula: grams = moles x molecular weight.