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A titration required 18.38ml of 0.1574 M of NaOh solution how many moles of NaOh were in this volume?
x/18.38L = 0.1574m/Lx= 2.893 mol------------------------------------------------18.38 ml = .01838 Lx/.01838 L = 0.1574 Mx= 0.0029 mol
How many ml of 0.1200 M NaOH is needed to titrate 0.5100 g KHP (MW 204.22 gmol) to the phenolphthalein end point?
To begin, calculate the number of moles of KHP using its molar mass. Next, use the stoichiometry of the reaction to determine the moles of NaOH required for complete titration. Finally, use the concentration of NaOH to calculate the volume needed in milliliters using the formula: volume (mL) = moles needed / molarity.
How many Moles of NaOH equals the moles of KHP?
When titrating NaOH with KHP (potassium hydrogen phthalate), the number of moles of NaOH will be equal to the number of moles of KHP at the equivalence point. This is because the reaction is stoichiometric, with one mole of NaOH reacting with one mole of KHP.
How many grams of NaOH(MW40.0) are there in 400.0 ml of a 0.175 M NaOH solution?
To calculate the grams of NaOH in the solution, you first need to find the moles of NaOH present in 400.0 ml of the solution. The moles of NaOH can be calculated using the formula: moles = molarity x volume (in liters). Once you have the moles of NaOH, you can then calculate the grams using the formula: grams = moles x molecular weight.
How many moles NaOH would be in 450 mL of 0.25 N NaOH?
First, calculate the number of moles of NaOH: Moles = Molarity x Volume (L) Convert mL to L: 450 mL = 0.45 L Moles = 0.25 N x 0.45 L = 0.1125 moles of NaOH.
If 20.0 mL of 150 M NaOH are used in a titration how many moles of NaOH are used?
To calculate the moles of NaOH used in the titration, multiply the volume (in liters) by the molarity. Converting 20.0 mL to liters (20.0 mL * 1 L/1000 mL = 0.020 L), the moles of NaOH used would be (0.020 L * 150 mol/L = 3.0 moles of NaOH).
A titration required 18.38ml of 0.1574 M of NaOh solution how many moles of NaOh were in this volume?
x/18.38L = 0.1574m/Lx= 2.893 mol------------------------------------------------18.38 ml = .01838 Lx/.01838 L = 0.1574 Mx= 0.0029 mol
How many moles of sodium hydroxide are used for the tiltration if 17.65 mL of a 0.110 M sodium is needed to titrated 25.00 mL of a hydrochloride acid solution?
I need to see the balanced equation to work!NaOH + HCl --> NaCl + H2O ( good, all one to one )Now, find molarity HCl ( sodium, or sodium hydroxide; no matter )(17.65 mL)(0.110 M NaOH) = (25.00 mL)(X M HCl)= 0.07766 M HCl-------------------------now,Molarity = moles of solute/Liters of solution ( 25.00 mL = 0.025 L)0.07766 M HCl = X moles/0.025 Liters= 0.001942 moles HCl---------------------------------------formal set up, though not needed0.001942 moles HCl (1 mole NaOH/1 mole HCl)= 0.00194 moles sodium hydroxide used=============================
How many grams of NaOH are there in 5.2 moles NaOH?
208g NaOH
How many moles of NaOH are in 23.3 mL of 0.162 M NaOH?
The number of moles is 0,0038.
How many liters of naoh are in 1.3 moles of 3.42 m of naoh?
Molarity = moles of solute/Liters of solution 3.42 M NaOH = 1.3 moles NaOH/Liters NaOH Liters NaOH = 1.3 moles NaOH/3.42 M NaOH = 0.38 Liters
How many grams of KHP will be required to titrate 50 mL of 12 M NaOh solution?
To determine the grams of KHP required, you first need to calculate the number of moles of NaOH present in the 50 mL solution. Then, using the balanced chemical equation of the titration between NaOH and KHP, you can find the mole ratio. From the mole ratio and the moles of NaOH, you can calculate the moles of KHP needed and then convert that to grams of KHP.
How many moles are in gram of NaOH?
moles = mass/Mr moles = 100/(23+16+1) moles of NaOH = 2.5mol
How many moles are there in 8 g sodium hydroxide?
8 g NaOH x 1 mole NaOH/40 g = 0.2 moles NaOH
How many ml of 0.1200 M NaOH is needed to titrate 0.5100 g KHP (MW 204.22 gmol) to the phenolphthalein end point?
To begin, calculate the number of moles of KHP using its molar mass. Next, use the stoichiometry of the reaction to determine the moles of NaOH required for complete titration. Finally, use the concentration of NaOH to calculate the volume needed in milliliters using the formula: volume (mL) = moles needed / molarity.
How many Moles of NaOH equals the moles of KHP?
When titrating NaOH with KHP (potassium hydrogen phthalate), the number of moles of NaOH will be equal to the number of moles of KHP at the equivalence point. This is because the reaction is stoichiometric, with one mole of NaOH reacting with one mole of KHP.
How many grams of NaOH(MW40.0) are there in 400.0 ml of a 0.175 M NaOH solution?
To calculate the grams of NaOH in the solution, you first need to find the moles of NaOH present in 400.0 ml of the solution. The moles of NaOH can be calculated using the formula: moles = molarity x volume (in liters). Once you have the moles of NaOH, you can then calculate the grams using the formula: grams = moles x molecular weight.
