The same number of moles for each.
First, calculate the number of moles of NaOH: Moles = Molarity x Volume (L) Convert mL to L: 450 mL = 0.45 L Moles = 0.25 N x 0.45 L = 0.1125 moles of NaOH.
To calculate the grams of NaOH in the solution, you first need to find the moles of NaOH present in 400.0 ml of the solution. The moles of NaOH can be calculated using the formula: moles = molarity x volume (in liters). Once you have the moles of NaOH, you can then calculate the grams using the formula: grams = moles x molecular weight.
Molarity = moles of solute/Liters of solution ( 24.5 mL = 0.0245 L)Rearranged,moles of solute = Liters of solution * MolarityMoles NaOH = (0.0245 L)(0.130 M NaOH)= 3.19 X 10 -3 moles NaOH==================
Molarity = moles of solute/Liters of solution (18.00 ml = 0.018 Liters)0.1123 M NaOH = X moles solute/0.018 L= 2.021 X 10 -3 moles NaOH============================as all is one to one,2.021 X 10 -3 moles OH -==================
The number of moles of NaOH used in the titration process can be calculated by dividing the volume of NaOH solution used by the molarity of the NaOH solution.
Molarity = moles of solute/Liters of solution 3.42 M NaOH = 1.3 moles NaOH/Liters NaOH Liters NaOH = 1.3 moles NaOH/3.42 M NaOH = 0.38 Liters
The number of moles is 0,0038.
moles = mass/Mr moles = 100/(23+16+1) moles of NaOH = 2.5mol
208g NaOH
First, calculate the number of moles of NaOH: Moles = Molarity x Volume (L) Convert mL to L: 450 mL = 0.45 L Moles = 0.25 N x 0.45 L = 0.1125 moles of NaOH.
To calculate the grams of NaOH in the solution, you first need to find the moles of NaOH present in 400.0 ml of the solution. The moles of NaOH can be calculated using the formula: moles = molarity x volume (in liters). Once you have the moles of NaOH, you can then calculate the grams using the formula: grams = moles x molecular weight.
Moles/Liters=Molarity (M) therefore: Molarity*Liters=moles Since you were given milliliters, you must first convert your volume to liters for the equation to be accurate. 2.2M*.065L=moles=.143 moles NaOH
Molarity = moles of solute/Liters of solution ( 24.5 mL = 0.0245 L)Rearranged,moles of solute = Liters of solution * MolarityMoles NaOH = (0.0245 L)(0.130 M NaOH)= 3.19 X 10 -3 moles NaOH==================
8 g NaOH x 1 mole NaOH/40 g = 0.2 moles NaOH
Molarity = moles of solute/Liters of solution (18.00 ml = 0.018 Liters)0.1123 M NaOH = X moles solute/0.018 L= 2.021 X 10 -3 moles NaOH============================as all is one to one,2.021 X 10 -3 moles OH -==================
The number of moles of NaOH used in the titration process can be calculated by dividing the volume of NaOH solution used by the molarity of the NaOH solution.
To find the moles of NaOH needed, use the formula: moles = concentration (molarity) x volume (liters). First, convert 300 mL to liters (0.3 L). Then, calculate: moles = 0.2 mol/L x 0.3 L = 0.06 moles. Therefore, 0.06 moles of NaOH are needed to prepare 300 mL of a 0.2 M solution.