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16y ago

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How many liters of naoh are in 1.3 moles of 3.42 m of naoh?

Molarity = moles of solute/Liters of solution 3.42 M NaOH = 1.3 moles NaOH/Liters NaOH Liters NaOH = 1.3 moles NaOH/3.42 M NaOH = 0.38 Liters


How many moles of NaOH are in 23.3 mL of 0.162 M NaOH?

The number of moles is 0,0038.


How many moles are in gram of NaOH?

moles = mass/Mr moles = 100/(23+16+1) moles of NaOH = 2.5mol


How many grams of NaOH are there in 5.2 moles NaOH?

208g NaOH


How many moles NaOH would be in 450 mL of 0.25 N NaOH?

First, calculate the number of moles of NaOH: Moles = Molarity x Volume (L) Convert mL to L: 450 mL = 0.45 L Moles = 0.25 N x 0.45 L = 0.1125 moles of NaOH.


How many grams of NaOH(MW40.0) are there in 400.0 ml of a 0.175 M NaOH solution?

To calculate the grams of NaOH in the solution, you first need to find the moles of NaOH present in 400.0 ml of the solution. The moles of NaOH can be calculated using the formula: moles = molarity x volume (in liters). Once you have the moles of NaOH, you can then calculate the grams using the formula: grams = moles x molecular weight.


How many moles of naoh are contained in 65.0ml of a 2.20m solution of naoh in H2O?

Moles/Liters=Molarity (M) therefore: Molarity*Liters=moles Since you were given milliliters, you must first convert your volume to liters for the equation to be accurate. 2.2M*.065L=moles=.143 moles NaOH


How many moles of NaOH are present in 24.5 mL of 0.130 M NaOH?

Molarity = moles of solute/Liters of solution ( 24.5 mL = 0.0245 L)Rearranged,moles of solute = Liters of solution * MolarityMoles NaOH = (0.0245 L)(0.130 M NaOH)= 3.19 X 10 -3 moles NaOH==================


How many moles are there in 8 g sodium hydroxide?

8 g NaOH x 1 mole NaOH/40 g = 0.2 moles NaOH


How many moles of hydroxide are in 18.00 mL of 0.1123M NaOH?

Molarity = moles of solute/Liters of solution (18.00 ml = 0.018 Liters)0.1123 M NaOH = X moles solute/0.018 L= 2.021 X 10 -3 moles NaOH============================as all is one to one,2.021 X 10 -3 moles OH -==================


How many moles of NaOH were used in the titration process?

The number of moles of NaOH used in the titration process can be calculated by dividing the volume of NaOH solution used by the molarity of the NaOH solution.


How many moles of NaOH needed to prepare 300 mL of a 0.2 m solution of NaOH?

To find the moles of NaOH needed, use the formula: moles = concentration (molarity) x volume (liters). First, convert 300 mL to liters (0.3 L). Then, calculate: moles = 0.2 mol/L x 0.3 L = 0.06 moles. Therefore, 0.06 moles of NaOH are needed to prepare 300 mL of a 0.2 M solution.