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If you have 60 grams of sodium hydroxide NaOH (FW 40 gramsmole) how many moles of sodium hydroxide would you have?
60 g NaOH x 1 mole NaOH/40 g NaOH = 1.5 moles NaOH
What is the mass of 2.75 moles of sodium hydroxide?
The molar mass of sodium hydroxide (NaOH) is approximately 40 g/mol. To find the mass of 2.75 moles of NaOH, you would multiply the number of moles by the molar mass: 2.75 moles x 40 g/mol = 110 grams.
How many moles of sodium hydroxide are required to neutralize 20 mol of nitric acid?
The balanced chemical equation for the neutralization between sodium hydroxide (NaOH) and nitric acid (HNO3) is 1 mol of NaOH reacts with 1 mol of HNO3. Therefore, 20 moles of nitric acid would require 20 moles of sodium hydroxide to neutralize it.
How many moles are present in 4g sodium hydroxide?
To determine the number of moles in 4g of sodium hydroxide (NaOH), divide the mass by the molar mass of NaOH. The molar mass of NaOH is approximately 40g/mol (Na = 23g/mol, O = 16g/mol, H = 1g/mol). Therefore, 4g of NaOH is equal to 0.1 moles.
What is the number of moles of sodium hydroxide NaOH corresponding to 10.84 and times 1023 formula units of NaOH?
To find the number of moles of NaOH, you need to divide the given number of formula units by Avogadro's number (6.022 x 10^23). Therefore, the number of moles of NaOH is 10.84/6.022 ≈ 1.8 x 10^-23 moles.
If you have 60 grams of sodium hydroxide NaOH (FW 40 gramsmole) how many moles of sodium hydroxide would you have?
60 g NaOH x 1 mole NaOH/40 g NaOH = 1.5 moles NaOH
How many moles are there in 8 g sodium hydroxide?
8 g NaOH x 1 mole NaOH/40 g = 0.2 moles NaOH
What is 83 grams of sodium hydroxide in moles?
For this you need the atomic (molecular) mass of NaOH. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. NaOH= 40.083.0 grams NaOH / (40.0 grams)= 2.08 moles NaOH
What is the mass of 2.75 moles of sodium hydroxide?
The molar mass of sodium hydroxide (NaOH) is approximately 40 g/mol. To find the mass of 2.75 moles of NaOH, you would multiply the number of moles by the molar mass: 2.75 moles x 40 g/mol = 110 grams.
How many moles of sodium hydroxide are required to neutralize 20 mol of nitric acid?
The balanced chemical equation for the neutralization between sodium hydroxide (NaOH) and nitric acid (HNO3) is 1 mol of NaOH reacts with 1 mol of HNO3. Therefore, 20 moles of nitric acid would require 20 moles of sodium hydroxide to neutralize it.
How many moles are present in 4g sodium hydroxide?
To determine the number of moles in 4g of sodium hydroxide (NaOH), divide the mass by the molar mass of NaOH. The molar mass of NaOH is approximately 40g/mol (Na = 23g/mol, O = 16g/mol, H = 1g/mol). Therefore, 4g of NaOH is equal to 0.1 moles.
What is the make up of 0.1 sodium hydroxide?
0.1 M sodium hydroxide solution contains 0.1 moles of sodium hydroxide per liter of solution. This corresponds to 0.1 moles of NaOH per 40 g (1 mole) of NaOH, resulting in 4 g of NaOH in 1 liter of 0.1 M NaOH solution.
What is the mass in grams of 25 mol of sodium hydroxide?
The molar mass of sodium hydroxide (NaOH) is approximately 40 grams/mol. To find the mass of 25 moles of NaOH, you would multiply the number of moles by the molar mass: 25 mol * 40 g/mol = 1000 grams. So, the mass of 25 moles of sodium hydroxide is 1000 grams.
Calculate the mass of 2.5 moles of sodium hydroxide?
To calculate the mass of 2.5 moles of sodium hydroxide (NaOH), you need to know the molar mass of NaOH, which is 40 g/mol. Multiply the number of moles by the molar mass: 2.5 moles x 40 g/mol = 100 grams of sodium hydroxide.
How many moles of sodium hydroxide are in 40 grams of sodium hydroxide?
To find the number of moles in 40 grams of sodium hydroxide, you first need to calculate the molar mass of NaOH. The molar mass of NaOH is about 40 g/mol. Then, you divide the given mass by the molar mass to get the number of moles. So, 40 grams divided by 40 g/mol is equal to 1 mole of NaOH.
How many grams of solute are required to make a 918 mL solution of sodium hydroxide with a concentration of 0.4922 M?
Molarity = moles of solute/Liters of solution ( 918 ml = 0.918 liters )rearranged algebraically,moles of solute = Liters of solution * Molaritymoles of NaOH = (0.918 l)(0.4922 M)= 0.45184 moles NaOH=======================so,0.45184 moles NaOH (39.998 grams/1 mole NaOH)= 18.1 grams sodium hydroxide needed============================
What is the number of moles of sodium hydroxide NaOH corresponding to 10.84 and times 1023 formula units of NaOH?
To find the number of moles of NaOH, you need to divide the given number of formula units by Avogadro's number (6.022 x 10^23). Therefore, the number of moles of NaOH is 10.84/6.022 ≈ 1.8 x 10^-23 moles.
