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Molarity = moles of solute/Liters of solution ( 918 ml = 0.918 liters )

rearranged algebraically,

moles of solute = Liters of solution * Molarity

moles of NaOH = (0.918 l)(0.4922 M)

= 0.45184 moles NaOH

=======================so,

0.45184 moles NaOH (39.998 grams/1 mole NaOH)

= 18.1 grams sodium hydroxide needed

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Q: How many grams of solute are required to make a 918 mL solution of sodium hydroxide with a concentration of 0.4922 M?
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